{"id":428,"date":"2023-01-04T14:09:46","date_gmt":"2023-01-04T19:09:46","guid":{"rendered":"https:\/\/opentextbc.ca\/alfm4\/?post_type=chapter&#038;p=428"},"modified":"2025-09-19T16:55:06","modified_gmt":"2025-09-19T20:55:06","slug":"multiplying-decimals","status":"publish","type":"chapter","link":"https:\/\/opentextbc.ca\/alfm4\/chapter\/multiplying-decimals\/","title":{"raw":"Topic A: Multiplying Decimals","rendered":"Topic A: Multiplying Decimals"},"content":{"raw":"Multiplying decimals uses the same method that you learned for multiplying whole numbers. Review multiplication of whole numbers.\r\n<div class=\"textbox\">\r\n\r\n<strong>Vocabulary Review<\/strong>\r\n\r\nReview the diagram below and try to write in the explanations of the mathematical terms. You may refer to the glossary, if you wish. For right now, it is mostly important to remember what factor means.\r\n\r\n<img class=\"size-full wp-image-828 aligncenter\" src=\"https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2023\/01\/Factors-and-product.jpg\" alt=\"3 times 7 = 21. 3 and 7 are factors and 21 is the product.\" width=\"232\" height=\"105\" \/>\r\n\r\n<strong>Product:<\/strong>\r\n\r\n<strong>Factors:<\/strong>\r\n\r\n<\/div>\r\n<h1>How to Multiply Decimals<\/h1>\r\nMultiplying decimals follows almost the same steps as multiplying whole numbers. On the next few pages, you will be shown two ways to multiply decimals.\r\n<h2>Method One<\/h2>\r\nOne method is to [pb_glossary id=\"647\"]estimate[\/pb_glossary] the [pb_glossary id=\"697\"]product[\/pb_glossary] using whole numbers to determine where the decimal goes.\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example A<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n[latex]4.3 \u00d7 5.7[\/latex]\r\n\r\nEstimate: 4.3 \u00d7 5.7 \u2248 4 \u00d7 6 = 24\r\n\r\nThis tells us that the correct answer will be around 24 (which is two whole number places). We know that the answer will not be around 2.4 and it will not be around 240.\r\n\r\nIf we take the decimals out and just multiply the [pb_glossary id=\"631\"]digits[\/pb_glossary], the answer is <strong>2451<\/strong>.\r\n\r\n[latex]\\begin{array}{rr}&amp;57\\\\ \\times&amp;43\\\\ \\hline &amp;171\\\\+&amp;2280\\\\ \\hline &amp;2451\\end{array}[\/latex]\r\n\r\nThe estimate shows that the decimal point will come after two whole number places, so 4.3 \u00d7 5.7 = 24.51\r\n\r\n[latex]\\begin{array}{rr}&amp;5.7\\\\ \\times&amp;4.3\\\\ \\hline &amp;171\\\\+&amp;2280\\\\ \\hline &amp;24.51\\end{array}[\/latex]\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example B<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n[latex]23.24 \u00d7 3.9[\/latex]\r\n\r\nEstimate: 23.24 \u00d7 3.9 \u2248 23 \u00d7 4 = 92\r\n\r\nThe answer will be around 92. It will not be around 9.2 and it will not be around 920.\r\n\r\nIf we take the decimals out and just multiply the digits, the answer is 90636.\r\n\r\nThe estimate shows that the decimal point will come after two whole number places.\r\n\r\nSo [latex]23.24\\times3.9 = 90.636[\/latex]\r\n\r\n[latex]\\begin{array}{rr}&amp;23.24\\\\ \\times &amp;3.9\\\\ \\hline &amp;20916\\\\+&amp;69720\\\\ \\hline &amp;90.636\\end{array}[\/latex]\r\n\r\nIf the whole numbers in the question are large, you can round to the nearest ten or hundred to help you decide where to put the decimal point. This is a quick estimate.\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example C<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n[latex]383.298 \u00d7 213.87[\/latex]\r\n\r\n383.298 \u00d7 213.87 \u2248 400 \u00d7 200 = 80<span style=\"margin-left: 0.25em;\">000<\/span>\r\n\r\nThe answer will be around 80<span style=\"margin-left: 0.25em;\">000<\/span>. \u00a0It will not be around 8<span style=\"margin-left: 0.25em;\">000<\/span> or 800<span style=\"margin-left: 0.25em;\">000<\/span>.\r\n\r\nIf we take the decimals out and just multiply the digits 383.298 by 213.87, the numerals in the product are 8<span style=\"margin-left: 0.25em;\">197<\/span><span style=\"margin-left: 0.25em;\">594<\/span><span style=\"margin-left: 0.25em;\">326<\/span>.\r\n\r\nThe estimate shows that the whole number will go up to the ten-thousands place, which is five whole number places, so\r\n\r\n383.298 \u00d7 213.87 = 81<span style=\"margin-left: 0.25em;\">975<\/span>.94326\u00a0 \u00a0<strong>W<\/strong><strong>hew!<\/strong>\r\n\r\n[latex]\\begin{array}{rr}&amp;383.298\\\\ \\times &amp;213.87\\\\ \\hline &amp;81975.94326\\end{array}[\/latex]\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Exercise 1<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nAll the multiplying has been done already. Your task is to put the decimal point in the product by doing a whole number estimate of the question.\r\n\r\n<strong>Example<\/strong>\r\n\r\n[latex]\\begin{array}{rr}&amp;2.8\\\\ \\times &amp;4.3\\\\ \\hline &amp;84\\\\+&amp;1120\\\\\\hline&amp;12.04\\end{array}[\/latex]\u00a0\u00a0\u00a0\u00a0 Estimate: [latex]\\begin{array}{rr}&amp;3\\\\ \\times &amp;4\\\\ \\hline &amp;12\\end{array}[\/latex]\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>[latex]\\begin{array}[t]{rr}&amp;56.9\\\\ \\times&amp;12.3\\\\ \\hline &amp;1707\\\\ &amp;11380\\\\&amp;56900\\\\ \\hline &amp;69987\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}[t]{rr}&amp;7.3\\\\ \\times&amp;19.6\\\\ \\hline &amp;14308\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}[t]{rrrr}&amp;28.7\\\\ \\times&amp;64.97\\\\ \\hline &amp;1864639\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}[t]{rrrr}&amp;73.2\\\\ \\times&amp;1.6\\\\ \\hline &amp;11712\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}[t]{rrrr}&amp;1.8\\\\ \\times&amp;1.3\\\\ \\hline &amp;234\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}[t]{rrrr}&amp;48.29\\\\ \\times&amp;55.6\\\\ \\hline&amp;2684924\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}[t]{rrrr}&amp;91.2\\\\ \\times&amp;1.5\\\\ \\hline&amp;13680 \\end{array}[\/latex]<\/li>\r\n<\/ol>\r\n<strong>Answers to Exercise 1<\/strong>\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>699.87<\/li>\r\n \t<li>143.08<\/li>\r\n \t<li>1864.639<\/li>\r\n \t<li>117.12<\/li>\r\n \t<li>2.34<\/li>\r\n \t<li>2684.924<\/li>\r\n \t<li>136.80<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<h2>Method Two<\/h2>\r\nAnother way of locating the decimal point in the product is to look at the number of decimal places in the decimals you are multiplying.\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example D<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n[latex]\\begin{array}{lll}&amp;43.23&amp;\\text{2 decimal places}\\\\ \\times&amp;19.6&amp;\\text{1 decimal place}\\\\ \\hline \\end{array}[\/latex]\r\n\r\nThen add the number of decimal places you counted above (2 + 1 = 3)\r\n\r\nThis is the number of decimal places you will have in your answer.\r\n\r\n[latex]\\begin{array}{lrl}&amp;43.23&amp;\\text{2 decimal places}\\\\ \\times&amp;19.6&amp;\\text{1 decimal place}\\\\ \\hline &amp;847.\\mathbf{308}&amp;\\text{3 decimal places}\\end{array}[\/latex]\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example E<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n[latex]\\begin{array}{lrl}&amp;0.35&amp;\\text{2 decimal places}\\\\ \\times&amp;0.47&amp;\\text{2 decimal places}\\\\ \\hline &amp;0.\\mathbf{1645}&amp;\\text{4 decimal places}\\end{array}[\/latex]\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example F<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n[latex]\\begin{array}{lrl}&amp;13.452&amp;\\text{3 decimal places}\\\\ \\times&amp;30&amp;\\text{0 decimal places}\\\\ \\hline &amp;403.\\mathbf{560}&amp;\\text{3 decimal places}\\end{array}[\/latex]\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Exercise 2<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nAgain, the multiplying has been done. Use the method of multiplying the understood [pb_glossary id=\"625\"]denominators[\/pb_glossary] to put the decimal point in the product.\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>[latex]\\begin{array}{lrl}&amp;9.2&amp;\\text{1 decimal place}\\\\ \\times&amp;0.3&amp;\\text{1 decimal place}\\\\ \\hline &amp;2.76&amp;\\text{2 decimal places}\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{lrl}&amp;0.27&amp;\\text{2 decimal places}\\\\ \\times&amp;1.8&amp;\\text{1 decimal place}\\\\ \\hline &amp;0.486&amp;\\text{3 decimal places}\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;6.8\\\\ \\times&amp;0.4\\\\ \\hline &amp;272\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;2.4\\\\ \\times &amp;0.13\\\\ \\hline &amp;0312\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;240\\\\ \\times &amp;0.05\\\\ \\hline &amp;1200\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;0.91\\\\ \\times&amp;6.2\\\\ \\hline &amp;5642\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;0.29\\\\ \\times&amp;1.2\\\\ \\hline &amp;0348\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;0.87\\\\ \\times&amp;0.19\\\\ \\hline &amp;01653\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;7.3\\\\ \\times &amp;3.8\\\\ \\hline &amp; 2774\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;4.24\\\\ \\times &amp;0.07\\\\ \\hline &amp;02968\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;0.042\\\\ \\times &amp;60\\\\ \\hline &amp;2520\\end{array}[\/latex]<\/li>\r\n<\/ol>\r\n<strong>Answers to Exercise 2<\/strong>\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>2.76<\/li>\r\n \t<li>0.486<\/li>\r\n \t<li>2.72<\/li>\r\n \t<li>0.312<\/li>\r\n \t<li>12.00<\/li>\r\n \t<li>5.642<\/li>\r\n \t<li>0.348<\/li>\r\n \t<li>0.1653<\/li>\r\n \t<li>27.74<\/li>\r\n \t<li>0.2968<\/li>\r\n \t<li>2.52<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Exercise 3<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nIf you had trouble with the first two exercises, then get help from your instructor. Here is extra practice if you want or need it.\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>[latex]\\begin{array}{lrl}&amp;41&amp;\\text{0 decimal places}\\\\ \\times&amp;0.061&amp;\\text{3 decimal places}\\\\ \\hline &amp;2.501&amp;\\text{3 decimal places}\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{lrl}&amp;7.8&amp;\\text{1 decimal place}\\\\ \\times&amp;0.5&amp;\\text{1 decimal place}\\\\ \\hline &amp;3.90&amp;\\text{2 decimal places total}\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;59.275\\\\ \\times&amp;0.08\\\\ \\hline &amp;474200\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;7.18\\\\ \\times &amp;23.46\\\\ \\hline &amp;1684428\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;0.84\\\\ \\times &amp;2.1\\\\ \\hline &amp;1764\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;18.6\\\\ \\times&amp;0.3\\\\ \\hline &amp;558\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;100\\\\ \\times&amp;0.35\\\\ \\hline &amp;3500\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;0.72\\\\ \\times&amp;3.4\\\\ \\hline &amp;2448\\end{array}[\/latex]<\/li>\r\n<\/ol>\r\n<strong>Answers to Exercise 3<\/strong>\r\n<ol class=\"twocolumn\" start=\"3\" type=\"a\">\r\n \t<li>4.74200<\/li>\r\n \t<li>168.4428<\/li>\r\n \t<li>1.764<\/li>\r\n \t<li>5.58<\/li>\r\n \t<li>35.00<\/li>\r\n \t<li>2.448<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Exercise 4<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nMultiply to find the product. Remember to put the decimal point in the correct place; you know two methods!\r\n<ol class=\"twocolumn bigspace\" type=\"a\">\r\n \t<li>[latex]\\begin{array}{lr}&amp;13.8\\\\ \\times&amp;3.9\\\\ \\hline &amp;1242\\\\&amp;4140\\\\ \\hline &amp;53.82\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rrr}&amp;0.076\\\\ \\times&amp;24\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rrr}&amp;2.05\\\\ \\times &amp;1.7\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rrr}&amp;0.429\\\\ \\times &amp;7.5\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rrr}&amp;96\\\\ \\times&amp;0.2\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rrr}&amp;1.79\\\\ \\times&amp;0.33\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rrr}&amp;40.1\\\\ \\times&amp;0.9\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n<\/ol>\r\n<strong>Answers to Exercise 4<\/strong>\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>53.82<\/li>\r\n \t<li>1.824<\/li>\r\n \t<li>3.485<\/li>\r\n \t<li>3.2175<\/li>\r\n \t<li>19.2<\/li>\r\n \t<li>0.5907<\/li>\r\n \t<li>36.09<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<h1>Prefixing Zeros<\/h1>\r\nRemember this skill?\r\n<ul>\r\n \t<li>[latex]\\dfrac{23}{1000}=0.\\mathbf{0}23[\/latex] -\u00a0The <strong>0<\/strong> must be used after the decimal point in 0.<strong>0<\/strong>23 to hold the tenths place. This makes it clear that the denominator is 1000.<\/li>\r\n \t<li>[latex]\\dfrac{7}{100}=0.\\mathbf{0}7[\/latex] - The <strong>0<\/strong> must be used after the decimal point in 0.<strong>0<\/strong>7 to hold the tenths place. This makes it clear that the denominator is 100.<\/li>\r\n \t<li>[latex]\\dfrac{8}{1000}=0.\\mathbf{00}8[\/latex] - The <strong>00<\/strong> must be used after the decimal point in 0.<strong>00<\/strong>8 to hold the tenths and hundredths place. This makes it clear that the denominator is 1000.<\/li>\r\n \t<li>[latex]\\dfrac{19}{10000}=0.\\mathbf{00}19[\/latex] - The <strong>00<\/strong> must be used after the decimal point in 0.<strong>00<\/strong>19 to hold the tenths and hundredths places. This makes it clear that the denominator is 10<span style=\"margin-left: 0.25em;\">000<\/span>.<\/li>\r\n<\/ul>\r\nWhen changing from a fraction to a decimal:\r\n\r\nIf there are not enough digits to fill all the decimal places, put zeros between the decimal point and the digits from the fraction\u2014this is called prefixing zeros.\r\n\r\nHow does this apply to multiplying decimals? Look at the examples.\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example G<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n[latex]\\begin{array}{lll}&amp;0.07&amp;\\text{2 decimal places}\\\\ \\times&amp;0.5&amp;\\text{1 decimal place}\\\\ \\hline &amp;\\phantom{0}35&amp;\\text{3 decimal places}\\end{array}[\/latex]\r\n\r\nUh oh! There are not enough spots in the answer to make the decimals fit in!\r\n\r\n[latex]\\begin{array}{rrc}&amp;0.07\\\\ \\times&amp;0.5\\\\ \\hline &amp;\\mathbf{00}35&amp;\\leftarrow\\\\&amp;\\small{3\\, 2\\, 1}&amp;\\small{\\text{count}}\\end{array}[\/latex]\r\n\r\nAdd zeros before your product. It is completely within the rules of math to do that. Then put in the decimal in the place in the correct place.\r\n\r\n[latex]\\begin{array}{rrc}&amp;0.07\\\\ \\times&amp;0.5\\\\ \\hline &amp;\\mathbf{0.0}35&amp;\\leftarrow\\\\&amp;\\small{3\\, 2\\, 1}&amp;\\small{\\text{count}}\\end{array}[\/latex]\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example H<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n[latex]\\begin{array}{lrl}&amp;0.07&amp;\\text{2 decimal places}\\\\ \\times&amp;0.03&amp;\\text{+2 decimal places}\\\\ \\hline &amp;.\\underline{\\;}\\,\\underline{\\;}21&amp;\\text{4 decimal places in product}\\\\&amp;\\small{4\\,3\\, 2\\, 1}&amp;\\small{\\text{count}}\\\\&amp;\\mathbf{0.0021}\\end{array}[\/latex]\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example I<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nLook carefully at this one \u2014 it is tricky!\r\n\r\n[latex]\\begin{array}{lrl}&amp;0.05&amp;\\text{2 decimal places}\\\\ \\times&amp;0.8&amp;\\text{+1 decimal place}\\\\ \\hline &amp;.\\underline{\\;}40&amp;\\text{3 decimal places in product}\\\\&amp;\\small{3\\, 2\\, 1}&amp;\\small{\\text{count}}\\end{array}[\/latex]\r\n\r\nBecause the last digit, the zero, is the result of multiplying 8 \u00d7 5, you must count it when working out the decimal places to put in the decimal point.\r\n\r\nThe product is forty thousandths:\r\n\r\n[latex]\\dfrac{40}{1000}=0.040[\/latex]\r\n\r\nwhich can also be written as four hundredths:\r\n\r\n[latex]\\dfrac{4}{100}=0.04[\/latex]\r\n\r\nNote that if you had not counted that zero, you would have written 0.004, which is four thousandths and not correct.\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Exercise 5<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nFind the products. Be certain to place all decimal points correctly.\r\n<ol class=\"twocolumn bigspace\" type=\"a\">\r\n \t<li>[latex]\\begin{array}{rr}&amp;0.35\\\\ \\times&amp;0.13\\\\ \\hline&amp;105\\\\&amp;350\\\\ \\hline &amp; 0.0455\\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;1.8\\\\ \\times&amp;0.05\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;300\\\\ \\times&amp;0.04\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;1.3\\\\ \\times&amp;0.027\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;500\\\\ \\times&amp;0.073\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;0.603\\\\ \\times&amp;0.4\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;38.2\\\\ \\times&amp;1.9\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;0.025\\\\ \\times&amp;0.25\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;3.5\\\\ \\times&amp;0.018\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;0.043\\\\ \\times&amp;3.3\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;0.013\\\\ \\times&amp;1.4\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{rr}&amp;0.201\\\\ \\times&amp;2.1\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\r\n<\/ol>\r\n<strong>Answers to Exercise 5<\/strong>\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>0.0455<\/li>\r\n \t<li>0.09<\/li>\r\n \t<li>12.00<\/li>\r\n \t<li>0.0351<\/li>\r\n \t<li>36.500<\/li>\r\n \t<li>0.2412<\/li>\r\n \t<li>72.58<\/li>\r\n \t<li>0.00625<\/li>\r\n \t<li>0.063<\/li>\r\n \t<li>0.1419<\/li>\r\n \t<li>0.0182<\/li>\r\n \t<li>0.4221<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<h1>Multiplying by 10, 100, 1<span style=\"margin-left: 0.25em;\">000<\/span>, 10<span style=\"margin-left: 0.25em;\">000<\/span>...<\/h1>\r\nThere is a pattern that you can see when we multiply by a decimal number by 10, 100, 1<span style=\"margin-left: 0.25em;\">000<\/span>, 10<span style=\"margin-left: 0.25em;\">000<\/span>, and so on. Look at the following example and try to find the pattern:\r\n<p class=\"indent\">45.9264 \u00d7 10 = 459.264<\/p>\r\n<p class=\"indent\">45.9264 \u00d7 100 = 4<span style=\"margin-left: 0.25em;\">592.64<\/span><\/p>\r\n<p class=\"indent\">45.9264 \u00d7 1<span style=\"margin-left: 0.25em;\">000<\/span> = 45<span style=\"margin-left: 0.25em;\">926.4<\/span><\/p>\r\n<p class=\"indent\">45.9264 \u00d7 10<span style=\"margin-left: 0.25em;\">000<\/span> = 459<span style=\"margin-left: 0.25em;\">264<\/span><\/p>\r\nDo you see a pattern?\r\n<div class=\"textbox\">When <strong>multiplying<\/strong> by 10, 100, 1<span style=\"margin-left: 0.25em;\">000<\/span>, 10<span style=\"margin-left: 0.25em;\">000<\/span>, etc., count the zeros in the 10, 100, 1<span style=\"margin-left: 0.25em;\">000<\/span>, etc. and move the decimal point that same number of places to the right.<\/div>\r\n<h2>Multiply by Ten<\/h2>\r\nWhen you multiply by ten, move the decimal point one place to the right. Remember that every whole number can have a decimal point at the right.\r\n<div>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example J<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>.37 \u00d7 10 = 3.7<\/li>\r\n \t<li>13 \u00d7 10 = 130<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Exercise 6<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n<ol class=\"threecolumn\" type=\"a\">\r\n \t<li>2.2 \u00d7 10 =<\/li>\r\n \t<li>6.67 \u00d7 10 =<\/li>\r\n \t<li>2.1 \u00d7 100 =<\/li>\r\n<\/ol>\r\n<strong>Answers to Exercise 6<\/strong>\r\n<ol class=\"threecolumn\" type=\"a\">\r\n \t<li>22<\/li>\r\n \t<li>66.7<\/li>\r\n \t<li>210<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<h2>Multiply by 100<\/h2>\r\nWhen you multiply by 100, move the decimal point two places to the right. Note that zeros may be needed at the end of the numeral.\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example K<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>4.2 \u00d7 100 = 420.<\/li>\r\n \t<li>6 \u00d7 100 = 600.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Exercise 7<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n<ol class=\"threecolumn\" type=\"a\">\r\n \t<li>5.67 \u00d7 100 =<\/li>\r\n \t<li>92.737 \u00d7 100 =<\/li>\r\n \t<li>25 \u00d7 100 =<\/li>\r\n<\/ol>\r\n<strong>Answers:<\/strong>\r\n<ol class=\"threecolumn\" type=\"a\">\r\n \t<li>567<\/li>\r\n \t<li>9<span style=\"margin-left: 0.25em;\">273.7<\/span><\/li>\r\n \t<li>2<span style=\"margin-left: 0.25em;\">500<\/span><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<h2>Multiply by 1000<\/h2>\r\nTo multiply by 1000, move the decimal point three places to the right.\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example L<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n4.2 \u00d7 1000 = 4200.\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Exercise 7<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>6.721 \u00d7 1000 =<\/li>\r\n \t<li>1.56 \u00d7 1000 =<\/li>\r\n \t<li>0.7246 \u00d7 1000 =<\/li>\r\n \t<li>2.1 \u00d7 1000 =<\/li>\r\n<\/ol>\r\n<strong>Answers to Exercise 7\r\n<\/strong>\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>6<span style=\"margin-left: 0.25em;\">721<\/span><\/li>\r\n \t<li>1<span style=\"margin-left: 0.25em;\">560<\/span><\/li>\r\n \t<li>724.6<\/li>\r\n \t<li>2<span style=\"margin-left: 0.25em;\">100<\/span><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Exercise 8<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nWrite the products using the short method you now know.\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>0.4 \u00d7 10 =<\/li>\r\n \t<li>0.27 \u00d7 10 =<\/li>\r\n \t<li>10 \u00d7 0.926 =<\/li>\r\n \t<li>10 \u00d7 0.09 =<\/li>\r\n \t<li>0.62 \u00d7100 =<\/li>\r\n \t<li>0.119 \u00d7 100 =<\/li>\r\n \t<li>100 \u00d7 2.03 =<\/li>\r\n \t<li>100 \u00d7 0.345 =<\/li>\r\n \t<li>1.934 \u00d7 1000 =<\/li>\r\n \t<li>28.9 \u00d7 100 =<\/li>\r\n<\/ol>\r\n<strong>Answers to Exercise 8<\/strong>\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>4<\/li>\r\n \t<li>2.7<\/li>\r\n \t<li>9.26<\/li>\r\n \t<li>0.9<\/li>\r\n \t<li>62<\/li>\r\n \t<li>11.9<\/li>\r\n \t<li>203<\/li>\r\n \t<li>34.5<\/li>\r\n \t<li>1<span style=\"margin-left: 0.25em;\">934<\/span><\/li>\r\n \t<li>2<span style=\"margin-left: 0.25em;\">890<\/span><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<h1>Multiplying Decimals to Determine Area<\/h1>\r\nThe area of an object is: the measurement of the amount of space the object surface covers. Area is described in square units.\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Exercise 9<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nFind the area of the rectangles described below. The measures of the length (l) and width (w) have been given. You should draw and label a sketch for each.\r\n<ol class=\"twocolumn bigspace\" type=\"a\">\r\n \t<li>l = 10.5 cm\r\nw = 6.6 cm\r\n<img class=\"aligncenter size-full wp-image-436\" src=\"https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2023\/01\/8a.png\" alt=\"\" width=\"206\" height=\"116\" \/>\r\nA = l \u00d7 w\r\nA = 10.5 \u00d7 6.6 cm\r\nA =<\/li>\r\n \t<li>l = 100.04 km\r\nw = 70.2 km<\/li>\r\n \t<li>l = 15.5 mm\r\nw = 10.5 mm<\/li>\r\n \t<li>l = 9.75 cm\r\nw = 3.5 cm<\/li>\r\n \t<li>l = 40.43 km\r\nw = 10.9 km<\/li>\r\n \t<li>l = 19.6 cm\r\nw = 2.8 cm<\/li>\r\n<\/ol>\r\n<strong>Answers to Exercise 9<\/strong>\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>69.3 cm<sup>2 <\/sup><\/li>\r\n \t<li>7022.808 km<sup>2 <\/sup><\/li>\r\n \t<li>162.75 mm<sup>2<\/sup><\/li>\r\n \t<li>34.125 cm<sup>2 <\/sup><\/li>\r\n \t<li>440.687 km<sup>2 <\/sup><\/li>\r\n \t<li>54.88 cm<sup>2<\/sup><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Exercise 10<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nFind the area of each square described in the questions below. Even though this is a simple square, it is still good practice to draw the picture.\r\n\r\nRemember, all four sides of a square are the same length.\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>A <sub>square<\/sub>, if \u00a0s = 5 cm\r\n<img class=\"aligncenter size-full wp-image-438\" src=\"https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2023\/01\/9sq.png\" alt=\"\" width=\"110\" height=\"73\" \/><\/li>\r\n \t<li>A <sub>square<\/sub>, if \u00a0s = 12.5 km<\/li>\r\n \t<li>A <sub>square<\/sub>, if \u00a0s = 1.4 km<\/li>\r\n \t<li>A <sub>square<\/sub>, if \u00a0s = 25.4 cm<\/li>\r\n<\/ol>\r\n<strong>Answers to Exercise 10<\/strong>\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>25 cm<sup>2 <\/sup><\/li>\r\n \t<li>156.25 km<sup>2<\/sup><\/li>\r\n \t<li>1.96 km<sup>2<\/sup><\/li>\r\n \t<li>645.16 cm<sup>2<\/sup><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<h1>Word Problems Using Multiplication of Decimals<\/h1>\r\nMultiplication problems usually give information about one thing and ask you to find a total amount for several of the same things. Look for this pattern in the following problems. Also look for key words.\r\n\r\nSome key words which point to multiplication include:\r\n<ul class=\"twocolumn\">\r\n \t<li>[pb_glossary id=\"697\"]product[\/pb_glossary]<\/li>\r\n \t<li>[pb_glossary id=\"727\"]total[\/pb_glossary]<\/li>\r\n \t<li>altogether<\/li>\r\n \t<li>of<\/li>\r\n<\/ul>\r\nMultiplication by a decimal or fraction often uses the word \"of\" in word problems.\r\n\r\n\u201cOf\u201d usually means multiply one number by another number.\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example M<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nKathy spends 0.25 <strong>of<\/strong> her salary on rent. Her salary is $1445 a month. How much is her rent?\r\n\r\n0.25 \u00d7 $1445 = $361.25\r\n\r\nShe spends $361.25 on rent every month.\r\n\r\n<\/div>\r\n<\/div>\r\nRemember, it can be very useful to draw a picture to help yourself visualize the problem.\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Exercise 11<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nSolve these problems. Do an estimation first.\r\n<ol type=\"a\">\r\n \t<li>One crate of juice costs $11.73. How much will five crates cost?\r\n<ul>\r\n \t<li>Estimation: $11.73\u00a0 \u2248\u00a0 $12, 12 \u00d7 5 = 60<\/li>\r\n \t<li>Actual Solution:<\/li>\r\n \t<li>Answer:<\/li>\r\n<\/ul>\r\n<\/li>\r\n \t<li>It takes Maria 0.75 hours to install a bathroom sink. The owner of the Ramada Hotel wants her to install 35 new sinks. How many hours of labour will Maria charge the hotel for this job?\r\n<ul>\r\n \t<li>Estimation:<\/li>\r\n \t<li>Actual Solution:<\/li>\r\n \t<li>Answer:<\/li>\r\n<\/ul>\r\n<\/li>\r\n \t<li>Find the longest hallway in your learning centre. Stand at one end and count how many steps you take until you reach the other end. Write that number here.\r\n<ol class=\"space\" type=\"i\">\r\n \t<li>How many steps would you take if you walked down your hallway 4.5 times?<\/li>\r\n \t<li>How many steps would you take if you walked down your hallway 33.68 times?<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Jessica\u2019s 4\u00d74 truck averages 15.75 kilometres per litre of gas (km\/L). How far could her truck travel with 52 L of gas?\r\n<ul>\r\n \t<li>Estimation:<\/li>\r\n \t<li>Actual Solution:<\/li>\r\n \t<li>Answer:<\/li>\r\n<\/ul>\r\n<\/li>\r\n \t<li>The distance between Jackie\u2019s work place and her home is 4.3 kilometres. She walks to work in the morning and then walks back to her home at the end of the work day, five days a week. How far does she walk each week?\r\n<ul>\r\n \t<li>Estimation:<\/li>\r\n \t<li>Actual Solution:<\/li>\r\n \t<li>Answer:<\/li>\r\n<\/ul>\r\n<\/li>\r\n \t<li>A new subdivision is being built outside of Terrace. There are 21 new houses. Each house needs 25.2 metric tons of crushed rock for the driveway. How much crushed rock will be used to build all the driveways?\r\n<ul>\r\n \t<li>Estimation:<\/li>\r\n \t<li>Actual Solution:<\/li>\r\n \t<li>Answer:<\/li>\r\n<\/ul>\r\n<\/li>\r\n \t<li>Union workers who work on statutory holidays are paid double time and a half. This is 2.5 times their regular pay.\r\n<ol type=\"i\">\r\n \t<li>The employees at the coal terminal earn $17.37 per hour. How much are they paid per hour if they work on a statutory holiday?<\/li>\r\n \t<li>Jesse worked a 7.5 hour shift at the coal terminal on Labour Day last year. What were his earnings for that day?<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Lucy\u2019s aunt in Hartley Bay has a large 50.5 m square vegetable garden. Lucy is going to help her aunt build a barbed wire fence to keep the deer out. The fence will be made with four strands of barbed wire. How much barbed wire should Lucy buy for her aunt? The fence will look like this:\r\n<img class=\"aligncenter wp-image-188\" src=\"https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2022\/12\/image152-e1672954935821.jpeg\" alt=\"Three fence posts and four lines of barbed wire stretched between the posts.\" width=\"300\" height=\"102\" \/>\r\n<ul>\r\n \t<li>Draw a picture:<\/li>\r\n \t<li>Estimation:<\/li>\r\n \t<li>Actual Solution:<\/li>\r\n \t<li>Answer:<\/li>\r\n<\/ul>\r\n<\/li>\r\n \t<li>The directions on a carpet shampoo say one bottle will clean 50 m<sup>2<\/sup> of carpet. Joyce wants to clean the wall-to-wall carpet in three rooms. The living room is 6 m by 4.5 m, the bedroom is 3 m by 4 m, and the hall is 1.2 m by 5 m. How many bottles of carpet shampoo should she buy? (This is a two-part question: Calculate the area of each of the rooms and then find the total area to be cleaned. Remember, Joyce cannot buy a partial bottle!)\r\n<ul>\r\n \t<li>Draw a picture:<\/li>\r\n \t<li>Estimation:<\/li>\r\n \t<li>Actual Solution:<\/li>\r\n \t<li>Answer:<\/li>\r\n<\/ul>\r\n<\/li>\r\n<\/ol>\r\n<strong>Answers to Exercise 11<\/strong>\r\n<ol type=\"a\">\r\n \t<li>Estimation: $12 \u00d7 5 \u2248 $60\r\nActual Solution: $11.73 \u00d7 5 =\u00a0 $58.65\r\nFive packages of juice will cost $58.65<\/li>\r\n \t<li>Estimation: 1 \u00d7 35 \u2248 35 hours\r\nActual Solution: 0.75 \u00d7 35 = 26.25 hours\r\nIt will take Maria 26.25 hours to install the sinks.<\/li>\r\n \t<li>Answers will vary. Please ask your instructor to check your work.<\/li>\r\n \t<li>Estimation: 16 km \u00d7 50 L \u2248 800 km\r\nActual Solution: 15.75 km \u00d7 52 L = 819 km\r\nThe truck could travel 819 km.<\/li>\r\n \t<li>Estimation: 4 km \u00d7 10 (5 trips there and 5 trips home) \u2248 40 km\r\nActual Solution: 4.3 km \u00d7 10 = 43 km\r\nJackie walks 43 km each week.<\/li>\r\n \t<li>Estimation: 25 t \u00d7 20 \u2248 500 t\r\nActual Solution: 25.2 t \u00d7 21 = 529.2 t\r\nThere will be 529.2 metric tons of crushed rock used for the driveways.<\/li>\r\n \t<li>Union workers:\r\n<ol type=\"i\">\r\n \t<li>$17.37 \u00d7 2.5 = $43.425 per hour<\/li>\r\n \t<li>$43.425 \u00d7 7.5 hours = $325.69.\r\nJesse earned $325.69 on Labour Day.<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Estimation: 50 + 50 + 50 + 50 \u2248 200 m, 200 m \u00d7 4 \u2248 800 m\r\nActual Solution: 50.5 m \u00d7 4 = 202 m, 202 m \u00d7 4 = 808 m.\r\nLucy should buy 808 m of barbed wire.<\/li>\r\n \t<li><strong>Estimation:\u00a0<\/strong>\r\n6 m \u00d7 5 m \u2248 30 m<sup>2<\/sup>\r\n3 m \u00d7 4 m \u2248 12 m<sup>2<\/sup>\r\n1 m \u00d7 5 m \u2248 5 m<sup>2<\/sup>\r\n30 m<sup>2<\/sup> + 12 m<sup>2<\/sup> + 5 m<sup>2<\/sup> \u2248 47 m<sup>2<\/sup>\r\n<strong>Actual Solution:\u00a0<\/strong>\r\n6 m \u00d7 4.5 m = 27 m<sup>2<\/sup>\r\n3 m \u00d7 4 m = 12 m<sup>2<\/sup>\r\n1.2 m \u00d7 5 m = 6 m<sup>2<\/sup>\r\n27 m<sup>2<\/sup> + 12 m<sup>2<\/sup> + 6 m<sup>2<\/sup> = 45 m<sup>2<\/sup>\r\nJoyce should buy just one bottle of carpet cleaner.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<h1>Design Your Own House Project Part 2: Roofing Your House<\/h1>\r\nMark: \/16\r\n\r\nUse the graph paper house sketch that you made in the Design Your Own House Project Part 1 in <a href=\"https:\/\/opentextbc.ca\/alfm4\/chapter\/subtracting-decimals\/\">Unit 2 - Topic B: Subtracting Decimals<\/a> to do this activity.\r\n<ol type=\"a\">\r\n \t<li>What is the area of your entire house? (area = length \u00d7 width) <strong>\/2<\/strong><\/li>\r\n \t<li>Your house has a flat roof and overhangs (meaning \"sticks out past\") the edges of the house by 0.5 m. Add the overhang to the length and width of your house and find the area of the roof of your house. <strong>\/2<\/strong><\/li>\r\n \t<li>Before covering a roof, builders put down tarpaper, which keeps water out. Look at a hardware store flyer or go online and check prices for tarpaper.<strong> \/1<\/strong>\r\n<ul type=\"a\">\r\n \t<li>Choose one type of tarpaper and write down the cost per roll.<\/li>\r\n<\/ul>\r\n<\/li>\r\n \t<li>Use your answer for question a to figure out how many rolls will you need to cover the entire roof (remember, you cannot buy part of a roll). <strong>\/2<\/strong><\/li>\r\n \t<li>Using your answers for questions c and d, calculate what it would cost to cover the entire roof with tarpaper. <strong>\/2<\/strong><\/li>\r\n \t<li>Use a flyer or look at hardware stores online and choose a roofing material.\u00a0 <strong>\/1<\/strong>\r\n<ul type=\"a\">\r\n \t<li>Write down your choice.<\/li>\r\n<\/ul>\r\n<\/li>\r\n \t<li>Roofing shingles are often sold in <strong>bundles<\/strong> that will cover 3 m<sup>2<\/sup>. Metal roofing materials are sold in sheets that will cover 50 square feet, which is the equivalent of 15 m<sup>2<\/sup>. What is the price per bundle or sheet for the material you chose in question f?<strong> \/2<\/strong><\/li>\r\n \t<li>Using your answer from question a, calculate how many bundles or sheets of roofing material you will need to cover your roof. \/2<\/li>\r\n \t<li>Using your answers from questions g and h, calculate the total cost of roofing your house.<strong> \/2<\/strong><\/li>\r\n<\/ol>\r\nWhen you have finished this project, put your graph paper somewhere safe, because you will be using it again at the end of Unit 5 Topic A.\r\n<h2>Marking Checklist for House Project Part 2<\/h2>\r\nCalculations:\r\n<ul>\r\n \t<li>The area of the house has been calculated correctly.<\/li>\r\n \t<li>The area of the roof has been calculated correctly.<\/li>\r\n \t<li>The number of rolls of tarpaper has been calculated correctly.<\/li>\r\n \t<li>The cost of covering the roof in tarpaper has been calculated correctly.<\/li>\r\n \t<li>The number of bundles or sheets of roofing material has been calculated correctly.<\/li>\r\n \t<li>The total cost of roofing the house has been calculated correctly.<\/li>\r\n<\/ul>\r\n<h1>Topic A: Self-Test<\/h1>\r\n<strong>Mark \/6\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 Aim 5\/6<\/strong>\r\n<ol type=\"A\">\r\n \t<li>Find the product. (4 marks)\r\n<ol class=\"twocolumn space\" type=\"a\">\r\n \t<li>[latex]\\begin{array}[t]{rr}&amp;66\\\\ \\times&amp;0.7\\\\ \\hline\\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}[t]{rr}&amp;7.25\\\\ \\times&amp;12\\\\ \\hline\\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}[t]{rr}&amp;6.5\\\\ \\times&amp;0.6\\\\ \\hline\\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}[t]{rr}&amp;19.5\\\\ \\times&amp;0.07\\\\ \\hline\\\\ \\end{array}[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Problems. (2 marks)\r\n<ol type=\"a\">\r\n \t<li>Rhonda bought a 3.4 kg roast at $2.89 per kilogram. What was the cost of her roast? (Round to the nearest cent.)\r\n<ul type=\"a\">\r\n \t<li>Estimation:<\/li>\r\n \t<li>Actual Solution:<\/li>\r\n<\/ul>\r\n<\/li>\r\n<\/ol>\r\n<\/li>\r\n<\/ol>\r\n<h2>Answers for Topic A: Self Test<\/h2>\r\n<ol type=\"A\">\r\n \t<li>Find the product.\r\n<ol class=\"twocolumn\" type=\"a\">\r\n \t<li>46.2<\/li>\r\n \t<li>87<\/li>\r\n \t<li>3.9<\/li>\r\n \t<li>1.365<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Problems.\r\n<ol type=\"a\">\r\n \t<li>Estimate: 3 \u00d7 3 = $9<\/li>\r\n \t<li>Actual solution: 3.4 \u00d7 2.89 = 9.826 (round to nearest cent: $9.83). Rhonda paid $9.83 for her roast.<\/li>\r\n<\/ol>\r\n<\/li>\r\n<\/ol>","rendered":"<p>Multiplying decimals uses the same method that you learned for multiplying whole numbers. Review multiplication of whole numbers.<\/p>\n<div class=\"textbox\">\n<p><strong>Vocabulary Review<\/strong><\/p>\n<p>Review the diagram below and try to write in the explanations of the mathematical terms. You may refer to the glossary, if you wish. For right now, it is mostly important to remember what factor means.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-828 aligncenter\" src=\"https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2023\/01\/Factors-and-product.jpg\" alt=\"3 times 7 = 21. 3 and 7 are factors and 21 is the product.\" width=\"232\" height=\"105\" srcset=\"https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2023\/01\/Factors-and-product.jpg 232w, https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2023\/01\/Factors-and-product-65x29.jpg 65w, https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2023\/01\/Factors-and-product-225x102.jpg 225w\" sizes=\"auto, (max-width: 232px) 100vw, 232px\" \/><\/p>\n<p><strong>Product:<\/strong><\/p>\n<p><strong>Factors:<\/strong><\/p>\n<\/div>\n<h1>How to Multiply Decimals<\/h1>\n<p>Multiplying decimals follows almost the same steps as multiplying whole numbers. On the next few pages, you will be shown two ways to multiply decimals.<\/p>\n<h2>Method One<\/h2>\n<p>One method is to <a class=\"glossary-term\" aria-haspopup=\"dialog\" aria-describedby=\"definition\" href=\"#term_428_647\">estimate<\/a> the <a class=\"glossary-term\" aria-haspopup=\"dialog\" aria-describedby=\"definition\" href=\"#term_428_697\">product<\/a> using whole numbers to determine where the decimal goes.<\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example A<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>[latex]4.3 \u00d7 5.7[\/latex]<\/p>\n<p>Estimate: 4.3 \u00d7 5.7 \u2248 4 \u00d7 6 = 24<\/p>\n<p>This tells us that the correct answer will be around 24 (which is two whole number places). We know that the answer will not be around 2.4 and it will not be around 240.<\/p>\n<p>If we take the decimals out and just multiply the <a class=\"glossary-term\" aria-haspopup=\"dialog\" aria-describedby=\"definition\" href=\"#term_428_631\">digits<\/a>, the answer is <strong>2451<\/strong>.<\/p>\n<p>[latex]\\begin{array}{rr}&57\\\\ \\times&43\\\\ \\hline &171\\\\+&2280\\\\ \\hline &2451\\end{array}[\/latex]<\/p>\n<p>The estimate shows that the decimal point will come after two whole number places, so 4.3 \u00d7 5.7 = 24.51<\/p>\n<p>[latex]\\begin{array}{rr}&5.7\\\\ \\times&4.3\\\\ \\hline &171\\\\+&2280\\\\ \\hline &24.51\\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example B<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>[latex]23.24 \u00d7 3.9[\/latex]<\/p>\n<p>Estimate: 23.24 \u00d7 3.9 \u2248 23 \u00d7 4 = 92<\/p>\n<p>The answer will be around 92. It will not be around 9.2 and it will not be around 920.<\/p>\n<p>If we take the decimals out and just multiply the digits, the answer is 90636.<\/p>\n<p>The estimate shows that the decimal point will come after two whole number places.<\/p>\n<p>So [latex]23.24\\times3.9 = 90.636[\/latex]<\/p>\n<p>[latex]\\begin{array}{rr}&23.24\\\\ \\times &3.9\\\\ \\hline &20916\\\\+&69720\\\\ \\hline &90.636\\end{array}[\/latex]<\/p>\n<p>If the whole numbers in the question are large, you can round to the nearest ten or hundred to help you decide where to put the decimal point. This is a quick estimate.<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example C<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>[latex]383.298 \u00d7 213.87[\/latex]<\/p>\n<p>383.298 \u00d7 213.87 \u2248 400 \u00d7 200 = 80<span style=\"margin-left: 0.25em;\">000<\/span><\/p>\n<p>The answer will be around 80<span style=\"margin-left: 0.25em;\">000<\/span>. \u00a0It will not be around 8<span style=\"margin-left: 0.25em;\">000<\/span> or 800<span style=\"margin-left: 0.25em;\">000<\/span>.<\/p>\n<p>If we take the decimals out and just multiply the digits 383.298 by 213.87, the numerals in the product are 8<span style=\"margin-left: 0.25em;\">197<\/span><span style=\"margin-left: 0.25em;\">594<\/span><span style=\"margin-left: 0.25em;\">326<\/span>.<\/p>\n<p>The estimate shows that the whole number will go up to the ten-thousands place, which is five whole number places, so<\/p>\n<p>383.298 \u00d7 213.87 = 81<span style=\"margin-left: 0.25em;\">975<\/span>.94326\u00a0 \u00a0<strong>W<\/strong><strong>hew!<\/strong><\/p>\n<p>[latex]\\begin{array}{rr}&383.298\\\\ \\times &213.87\\\\ \\hline &81975.94326\\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Exercise 1<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>All the multiplying has been done already. Your task is to put the decimal point in the product by doing a whole number estimate of the question.<\/p>\n<p><strong>Example<\/strong><\/p>\n<p>[latex]\\begin{array}{rr}&2.8\\\\ \\times &4.3\\\\ \\hline &84\\\\+&1120\\\\\\hline&12.04\\end{array}[\/latex]\u00a0\u00a0\u00a0\u00a0 Estimate: [latex]\\begin{array}{rr}&3\\\\ \\times &4\\\\ \\hline &12\\end{array}[\/latex]<\/p>\n<ol class=\"twocolumn\" type=\"a\">\n<li>[latex]\\begin{array}[t]{rr}&56.9\\\\ \\times&12.3\\\\ \\hline &1707\\\\ &11380\\\\&56900\\\\ \\hline &69987\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}[t]{rr}&7.3\\\\ \\times&19.6\\\\ \\hline &14308\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}[t]{rrrr}&28.7\\\\ \\times&64.97\\\\ \\hline &1864639\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}[t]{rrrr}&73.2\\\\ \\times&1.6\\\\ \\hline &11712\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}[t]{rrrr}&1.8\\\\ \\times&1.3\\\\ \\hline &234\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}[t]{rrrr}&48.29\\\\ \\times&55.6\\\\ \\hline&2684924\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}[t]{rrrr}&91.2\\\\ \\times&1.5\\\\ \\hline&13680 \\end{array}[\/latex]<\/li>\n<\/ol>\n<p><strong>Answers to Exercise 1<\/strong><\/p>\n<ol class=\"twocolumn\" type=\"a\">\n<li>699.87<\/li>\n<li>143.08<\/li>\n<li>1864.639<\/li>\n<li>117.12<\/li>\n<li>2.34<\/li>\n<li>2684.924<\/li>\n<li>136.80<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<h2>Method Two<\/h2>\n<p>Another way of locating the decimal point in the product is to look at the number of decimal places in the decimals you are multiplying.<\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example D<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>[latex]\\begin{array}{lll}&43.23&\\text{2 decimal places}\\\\ \\times&19.6&\\text{1 decimal place}\\\\ \\hline \\end{array}[\/latex]<\/p>\n<p>Then add the number of decimal places you counted above (2 + 1 = 3)<\/p>\n<p>This is the number of decimal places you will have in your answer.<\/p>\n<p>[latex]\\begin{array}{lrl}&43.23&\\text{2 decimal places}\\\\ \\times&19.6&\\text{1 decimal place}\\\\ \\hline &847.\\mathbf{308}&\\text{3 decimal places}\\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example E<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>[latex]\\begin{array}{lrl}&0.35&\\text{2 decimal places}\\\\ \\times&0.47&\\text{2 decimal places}\\\\ \\hline &0.\\mathbf{1645}&\\text{4 decimal places}\\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example F<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>[latex]\\begin{array}{lrl}&13.452&\\text{3 decimal places}\\\\ \\times&30&\\text{0 decimal places}\\\\ \\hline &403.\\mathbf{560}&\\text{3 decimal places}\\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Exercise 2<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Again, the multiplying has been done. Use the method of multiplying the understood <a class=\"glossary-term\" aria-haspopup=\"dialog\" aria-describedby=\"definition\" href=\"#term_428_625\">denominators<\/a> to put the decimal point in the product.<\/p>\n<ol class=\"twocolumn\" type=\"a\">\n<li>[latex]\\begin{array}{lrl}&9.2&\\text{1 decimal place}\\\\ \\times&0.3&\\text{1 decimal place}\\\\ \\hline &2.76&\\text{2 decimal places}\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{lrl}&0.27&\\text{2 decimal places}\\\\ \\times&1.8&\\text{1 decimal place}\\\\ \\hline &0.486&\\text{3 decimal places}\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&6.8\\\\ \\times&0.4\\\\ \\hline &272\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&2.4\\\\ \\times &0.13\\\\ \\hline &0312\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&240\\\\ \\times &0.05\\\\ \\hline &1200\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&0.91\\\\ \\times&6.2\\\\ \\hline &5642\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&0.29\\\\ \\times&1.2\\\\ \\hline &0348\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&0.87\\\\ \\times&0.19\\\\ \\hline &01653\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&7.3\\\\ \\times &3.8\\\\ \\hline & 2774\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&4.24\\\\ \\times &0.07\\\\ \\hline &02968\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&0.042\\\\ \\times &60\\\\ \\hline &2520\\end{array}[\/latex]<\/li>\n<\/ol>\n<p><strong>Answers to Exercise 2<\/strong><\/p>\n<ol class=\"twocolumn\" type=\"a\">\n<li>2.76<\/li>\n<li>0.486<\/li>\n<li>2.72<\/li>\n<li>0.312<\/li>\n<li>12.00<\/li>\n<li>5.642<\/li>\n<li>0.348<\/li>\n<li>0.1653<\/li>\n<li>27.74<\/li>\n<li>0.2968<\/li>\n<li>2.52<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Exercise 3<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>If you had trouble with the first two exercises, then get help from your instructor. Here is extra practice if you want or need it.<\/p>\n<ol class=\"twocolumn\" type=\"a\">\n<li>[latex]\\begin{array}{lrl}&41&\\text{0 decimal places}\\\\ \\times&0.061&\\text{3 decimal places}\\\\ \\hline &2.501&\\text{3 decimal places}\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{lrl}&7.8&\\text{1 decimal place}\\\\ \\times&0.5&\\text{1 decimal place}\\\\ \\hline &3.90&\\text{2 decimal places total}\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&59.275\\\\ \\times&0.08\\\\ \\hline &474200\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&7.18\\\\ \\times &23.46\\\\ \\hline &1684428\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&0.84\\\\ \\times &2.1\\\\ \\hline &1764\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&18.6\\\\ \\times&0.3\\\\ \\hline &558\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&100\\\\ \\times&0.35\\\\ \\hline &3500\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&0.72\\\\ \\times&3.4\\\\ \\hline &2448\\end{array}[\/latex]<\/li>\n<\/ol>\n<p><strong>Answers to Exercise 3<\/strong><\/p>\n<ol class=\"twocolumn\" start=\"3\" type=\"a\">\n<li>4.74200<\/li>\n<li>168.4428<\/li>\n<li>1.764<\/li>\n<li>5.58<\/li>\n<li>35.00<\/li>\n<li>2.448<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Exercise 4<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Multiply to find the product. Remember to put the decimal point in the correct place; you know two methods!<\/p>\n<ol class=\"twocolumn bigspace\" type=\"a\">\n<li>[latex]\\begin{array}{lr}&13.8\\\\ \\times&3.9\\\\ \\hline &1242\\\\&4140\\\\ \\hline &53.82\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rrr}&0.076\\\\ \\times&24\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rrr}&2.05\\\\ \\times &1.7\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rrr}&0.429\\\\ \\times &7.5\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rrr}&96\\\\ \\times&0.2\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rrr}&1.79\\\\ \\times&0.33\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rrr}&40.1\\\\ \\times&0.9\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<\/ol>\n<p><strong>Answers to Exercise 4<\/strong><\/p>\n<ol class=\"twocolumn\" type=\"a\">\n<li>53.82<\/li>\n<li>1.824<\/li>\n<li>3.485<\/li>\n<li>3.2175<\/li>\n<li>19.2<\/li>\n<li>0.5907<\/li>\n<li>36.09<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<h1>Prefixing Zeros<\/h1>\n<p>Remember this skill?<\/p>\n<ul>\n<li>[latex]\\dfrac{23}{1000}=0.\\mathbf{0}23[\/latex] &#8211;\u00a0The <strong>0<\/strong> must be used after the decimal point in 0.<strong>0<\/strong>23 to hold the tenths place. This makes it clear that the denominator is 1000.<\/li>\n<li>[latex]\\dfrac{7}{100}=0.\\mathbf{0}7[\/latex] &#8211; The <strong>0<\/strong> must be used after the decimal point in 0.<strong>0<\/strong>7 to hold the tenths place. This makes it clear that the denominator is 100.<\/li>\n<li>[latex]\\dfrac{8}{1000}=0.\\mathbf{00}8[\/latex] &#8211; The <strong>00<\/strong> must be used after the decimal point in 0.<strong>00<\/strong>8 to hold the tenths and hundredths place. This makes it clear that the denominator is 1000.<\/li>\n<li>[latex]\\dfrac{19}{10000}=0.\\mathbf{00}19[\/latex] &#8211; The <strong>00<\/strong> must be used after the decimal point in 0.<strong>00<\/strong>19 to hold the tenths and hundredths places. This makes it clear that the denominator is 10<span style=\"margin-left: 0.25em;\">000<\/span>.<\/li>\n<\/ul>\n<p>When changing from a fraction to a decimal:<\/p>\n<p>If there are not enough digits to fill all the decimal places, put zeros between the decimal point and the digits from the fraction\u2014this is called prefixing zeros.<\/p>\n<p>How does this apply to multiplying decimals? Look at the examples.<\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example G<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>[latex]\\begin{array}{lll}&0.07&\\text{2 decimal places}\\\\ \\times&0.5&\\text{1 decimal place}\\\\ \\hline &\\phantom{0}35&\\text{3 decimal places}\\end{array}[\/latex]<\/p>\n<p>Uh oh! There are not enough spots in the answer to make the decimals fit in!<\/p>\n<p>[latex]\\begin{array}{rrc}&0.07\\\\ \\times&0.5\\\\ \\hline &\\mathbf{00}35&\\leftarrow\\\\&\\small{3\\, 2\\, 1}&\\small{\\text{count}}\\end{array}[\/latex]<\/p>\n<p>Add zeros before your product. It is completely within the rules of math to do that. Then put in the decimal in the place in the correct place.<\/p>\n<p>[latex]\\begin{array}{rrc}&0.07\\\\ \\times&0.5\\\\ \\hline &\\mathbf{0.0}35&\\leftarrow\\\\&\\small{3\\, 2\\, 1}&\\small{\\text{count}}\\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example H<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>[latex]\\begin{array}{lrl}&0.07&\\text{2 decimal places}\\\\ \\times&0.03&\\text{+2 decimal places}\\\\ \\hline &.\\underline{\\;}\\,\\underline{\\;}21&\\text{4 decimal places in product}\\\\&\\small{4\\,3\\, 2\\, 1}&\\small{\\text{count}}\\\\&\\mathbf{0.0021}\\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example I<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Look carefully at this one \u2014 it is tricky!<\/p>\n<p>[latex]\\begin{array}{lrl}&0.05&\\text{2 decimal places}\\\\ \\times&0.8&\\text{+1 decimal place}\\\\ \\hline &.\\underline{\\;}40&\\text{3 decimal places in product}\\\\&\\small{3\\, 2\\, 1}&\\small{\\text{count}}\\end{array}[\/latex]<\/p>\n<p>Because the last digit, the zero, is the result of multiplying 8 \u00d7 5, you must count it when working out the decimal places to put in the decimal point.<\/p>\n<p>The product is forty thousandths:<\/p>\n<p>[latex]\\dfrac{40}{1000}=0.040[\/latex]<\/p>\n<p>which can also be written as four hundredths:<\/p>\n<p>[latex]\\dfrac{4}{100}=0.04[\/latex]<\/p>\n<p>Note that if you had not counted that zero, you would have written 0.004, which is four thousandths and not correct.<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Exercise 5<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Find the products. Be certain to place all decimal points correctly.<\/p>\n<ol class=\"twocolumn bigspace\" type=\"a\">\n<li>[latex]\\begin{array}{rr}&0.35\\\\ \\times&0.13\\\\ \\hline&105\\\\&350\\\\ \\hline & 0.0455\\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&1.8\\\\ \\times&0.05\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&300\\\\ \\times&0.04\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&1.3\\\\ \\times&0.027\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&500\\\\ \\times&0.073\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&0.603\\\\ \\times&0.4\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&38.2\\\\ \\times&1.9\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&0.025\\\\ \\times&0.25\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&3.5\\\\ \\times&0.018\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&0.043\\\\ \\times&3.3\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&0.013\\\\ \\times&1.4\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{rr}&0.201\\\\ \\times&2.1\\\\ \\hline \\\\ \\end{array}[\/latex]<\/li>\n<\/ol>\n<p><strong>Answers to Exercise 5<\/strong><\/p>\n<ol class=\"twocolumn\" type=\"a\">\n<li>0.0455<\/li>\n<li>0.09<\/li>\n<li>12.00<\/li>\n<li>0.0351<\/li>\n<li>36.500<\/li>\n<li>0.2412<\/li>\n<li>72.58<\/li>\n<li>0.00625<\/li>\n<li>0.063<\/li>\n<li>0.1419<\/li>\n<li>0.0182<\/li>\n<li>0.4221<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<h1>Multiplying by 10, 100, 1<span style=\"margin-left: 0.25em;\">000<\/span>, 10<span style=\"margin-left: 0.25em;\">000<\/span>&#8230;<\/h1>\n<p>There is a pattern that you can see when we multiply by a decimal number by 10, 100, 1<span style=\"margin-left: 0.25em;\">000<\/span>, 10<span style=\"margin-left: 0.25em;\">000<\/span>, and so on. Look at the following example and try to find the pattern:<\/p>\n<p class=\"indent\">45.9264 \u00d7 10 = 459.264<\/p>\n<p class=\"indent\">45.9264 \u00d7 100 = 4<span style=\"margin-left: 0.25em;\">592.64<\/span><\/p>\n<p class=\"indent\">45.9264 \u00d7 1<span style=\"margin-left: 0.25em;\">000<\/span> = 45<span style=\"margin-left: 0.25em;\">926.4<\/span><\/p>\n<p class=\"indent\">45.9264 \u00d7 10<span style=\"margin-left: 0.25em;\">000<\/span> = 459<span style=\"margin-left: 0.25em;\">264<\/span><\/p>\n<p>Do you see a pattern?<\/p>\n<div class=\"textbox\">When <strong>multiplying<\/strong> by 10, 100, 1<span style=\"margin-left: 0.25em;\">000<\/span>, 10<span style=\"margin-left: 0.25em;\">000<\/span>, etc., count the zeros in the 10, 100, 1<span style=\"margin-left: 0.25em;\">000<\/span>, etc. and move the decimal point that same number of places to the right.<\/div>\n<h2>Multiply by Ten<\/h2>\n<p>When you multiply by ten, move the decimal point one place to the right. Remember that every whole number can have a decimal point at the right.<\/p>\n<div>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example J<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<ol class=\"twocolumn\" type=\"a\">\n<li>.37 \u00d7 10 = 3.7<\/li>\n<li>13 \u00d7 10 = 130<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Exercise 6<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<ol class=\"threecolumn\" type=\"a\">\n<li>2.2 \u00d7 10 =<\/li>\n<li>6.67 \u00d7 10 =<\/li>\n<li>2.1 \u00d7 100 =<\/li>\n<\/ol>\n<p><strong>Answers to Exercise 6<\/strong><\/p>\n<ol class=\"threecolumn\" type=\"a\">\n<li>22<\/li>\n<li>66.7<\/li>\n<li>210<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<h2>Multiply by 100<\/h2>\n<p>When you multiply by 100, move the decimal point two places to the right. Note that zeros may be needed at the end of the numeral.<\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example K<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<ol class=\"twocolumn\" type=\"a\">\n<li>4.2 \u00d7 100 = 420.<\/li>\n<li>6 \u00d7 100 = 600.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Exercise 7<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<ol class=\"threecolumn\" type=\"a\">\n<li>5.67 \u00d7 100 =<\/li>\n<li>92.737 \u00d7 100 =<\/li>\n<li>25 \u00d7 100 =<\/li>\n<\/ol>\n<p><strong>Answers:<\/strong><\/p>\n<ol class=\"threecolumn\" type=\"a\">\n<li>567<\/li>\n<li>9<span style=\"margin-left: 0.25em;\">273.7<\/span><\/li>\n<li>2<span style=\"margin-left: 0.25em;\">500<\/span><\/li>\n<\/ol>\n<\/div>\n<\/div>\n<h2>Multiply by 1000<\/h2>\n<p>To multiply by 1000, move the decimal point three places to the right.<\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example L<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>4.2 \u00d7 1000 = 4200.<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Exercise 7<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<ol class=\"twocolumn\" type=\"a\">\n<li>6.721 \u00d7 1000 =<\/li>\n<li>1.56 \u00d7 1000 =<\/li>\n<li>0.7246 \u00d7 1000 =<\/li>\n<li>2.1 \u00d7 1000 =<\/li>\n<\/ol>\n<p><strong>Answers to Exercise 7<br \/>\n<\/strong><\/p>\n<ol class=\"twocolumn\" type=\"a\">\n<li>6<span style=\"margin-left: 0.25em;\">721<\/span><\/li>\n<li>1<span style=\"margin-left: 0.25em;\">560<\/span><\/li>\n<li>724.6<\/li>\n<li>2<span style=\"margin-left: 0.25em;\">100<\/span><\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Exercise 8<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Write the products using the short method you now know.<\/p>\n<ol class=\"twocolumn\" type=\"a\">\n<li>0.4 \u00d7 10 =<\/li>\n<li>0.27 \u00d7 10 =<\/li>\n<li>10 \u00d7 0.926 =<\/li>\n<li>10 \u00d7 0.09 =<\/li>\n<li>0.62 \u00d7100 =<\/li>\n<li>0.119 \u00d7 100 =<\/li>\n<li>100 \u00d7 2.03 =<\/li>\n<li>100 \u00d7 0.345 =<\/li>\n<li>1.934 \u00d7 1000 =<\/li>\n<li>28.9 \u00d7 100 =<\/li>\n<\/ol>\n<p><strong>Answers to Exercise 8<\/strong><\/p>\n<ol class=\"twocolumn\" type=\"a\">\n<li>4<\/li>\n<li>2.7<\/li>\n<li>9.26<\/li>\n<li>0.9<\/li>\n<li>62<\/li>\n<li>11.9<\/li>\n<li>203<\/li>\n<li>34.5<\/li>\n<li>1<span style=\"margin-left: 0.25em;\">934<\/span><\/li>\n<li>2<span style=\"margin-left: 0.25em;\">890<\/span><\/li>\n<\/ol>\n<\/div>\n<\/div>\n<h1>Multiplying Decimals to Determine Area<\/h1>\n<p>The area of an object is: the measurement of the amount of space the object surface covers. Area is described in square units.<\/p>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Exercise 9<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Find the area of the rectangles described below. The measures of the length (l) and width (w) have been given. You should draw and label a sketch for each.<\/p>\n<ol class=\"twocolumn bigspace\" type=\"a\">\n<li>l = 10.5 cm<br \/>\nw = 6.6 cm<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-436\" src=\"https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2023\/01\/8a.png\" alt=\"\" width=\"206\" height=\"116\" srcset=\"https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2023\/01\/8a.png 206w, https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2023\/01\/8a-65x37.png 65w\" sizes=\"auto, (max-width: 206px) 100vw, 206px\" \/><br \/>\nA = l \u00d7 w<br \/>\nA = 10.5 \u00d7 6.6 cm<br \/>\nA =<\/li>\n<li>l = 100.04 km<br \/>\nw = 70.2 km<\/li>\n<li>l = 15.5 mm<br \/>\nw = 10.5 mm<\/li>\n<li>l = 9.75 cm<br \/>\nw = 3.5 cm<\/li>\n<li>l = 40.43 km<br \/>\nw = 10.9 km<\/li>\n<li>l = 19.6 cm<br \/>\nw = 2.8 cm<\/li>\n<\/ol>\n<p><strong>Answers to Exercise 9<\/strong><\/p>\n<ol class=\"twocolumn\" type=\"a\">\n<li>69.3 cm<sup>2 <\/sup><\/li>\n<li>7022.808 km<sup>2 <\/sup><\/li>\n<li>162.75 mm<sup>2<\/sup><\/li>\n<li>34.125 cm<sup>2 <\/sup><\/li>\n<li>440.687 km<sup>2 <\/sup><\/li>\n<li>54.88 cm<sup>2<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Exercise 10<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Find the area of each square described in the questions below. Even though this is a simple square, it is still good practice to draw the picture.<\/p>\n<p>Remember, all four sides of a square are the same length.<\/p>\n<ol class=\"twocolumn\" type=\"a\">\n<li>A <sub>square<\/sub>, if \u00a0s = 5 cm<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-438\" src=\"https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2023\/01\/9sq.png\" alt=\"\" width=\"110\" height=\"73\" srcset=\"https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2023\/01\/9sq.png 110w, https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2023\/01\/9sq-65x43.png 65w\" sizes=\"auto, (max-width: 110px) 100vw, 110px\" \/><\/li>\n<li>A <sub>square<\/sub>, if \u00a0s = 12.5 km<\/li>\n<li>A <sub>square<\/sub>, if \u00a0s = 1.4 km<\/li>\n<li>A <sub>square<\/sub>, if \u00a0s = 25.4 cm<\/li>\n<\/ol>\n<p><strong>Answers to Exercise 10<\/strong><\/p>\n<ol class=\"twocolumn\" type=\"a\">\n<li>25 cm<sup>2 <\/sup><\/li>\n<li>156.25 km<sup>2<\/sup><\/li>\n<li>1.96 km<sup>2<\/sup><\/li>\n<li>645.16 cm<sup>2<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/div>\n<h1>Word Problems Using Multiplication of Decimals<\/h1>\n<p>Multiplication problems usually give information about one thing and ask you to find a total amount for several of the same things. Look for this pattern in the following problems. Also look for key words.<\/p>\n<p>Some key words which point to multiplication include:<\/p>\n<ul class=\"twocolumn\">\n<li><a class=\"glossary-term\" aria-haspopup=\"dialog\" aria-describedby=\"definition\" href=\"#term_428_697\">product<\/a><\/li>\n<li><a class=\"glossary-term\" aria-haspopup=\"dialog\" aria-describedby=\"definition\" href=\"#term_428_727\">total<\/a><\/li>\n<li>altogether<\/li>\n<li>of<\/li>\n<\/ul>\n<p>Multiplication by a decimal or fraction often uses the word &#8220;of&#8221; in word problems.<\/p>\n<p>\u201cOf\u201d usually means multiply one number by another number.<\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example M<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Kathy spends 0.25 <strong>of<\/strong> her salary on rent. Her salary is $1445 a month. How much is her rent?<\/p>\n<p>0.25 \u00d7 $1445 = $361.25<\/p>\n<p>She spends $361.25 on rent every month.<\/p>\n<\/div>\n<\/div>\n<p>Remember, it can be very useful to draw a picture to help yourself visualize the problem.<\/p>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Exercise 11<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Solve these problems. Do an estimation first.<\/p>\n<ol type=\"a\">\n<li>One crate of juice costs $11.73. How much will five crates cost?\n<ul>\n<li>Estimation: $11.73\u00a0 \u2248\u00a0 $12, 12 \u00d7 5 = 60<\/li>\n<li>Actual Solution:<\/li>\n<li>Answer:<\/li>\n<\/ul>\n<\/li>\n<li>It takes Maria 0.75 hours to install a bathroom sink. The owner of the Ramada Hotel wants her to install 35 new sinks. How many hours of labour will Maria charge the hotel for this job?\n<ul>\n<li>Estimation:<\/li>\n<li>Actual Solution:<\/li>\n<li>Answer:<\/li>\n<\/ul>\n<\/li>\n<li>Find the longest hallway in your learning centre. Stand at one end and count how many steps you take until you reach the other end. Write that number here.\n<ol class=\"space\" type=\"i\">\n<li>How many steps would you take if you walked down your hallway 4.5 times?<\/li>\n<li>How many steps would you take if you walked down your hallway 33.68 times?<\/li>\n<\/ol>\n<\/li>\n<li>Jessica\u2019s 4\u00d74 truck averages 15.75 kilometres per litre of gas (km\/L). How far could her truck travel with 52 L of gas?\n<ul>\n<li>Estimation:<\/li>\n<li>Actual Solution:<\/li>\n<li>Answer:<\/li>\n<\/ul>\n<\/li>\n<li>The distance between Jackie\u2019s work place and her home is 4.3 kilometres. She walks to work in the morning and then walks back to her home at the end of the work day, five days a week. How far does she walk each week?\n<ul>\n<li>Estimation:<\/li>\n<li>Actual Solution:<\/li>\n<li>Answer:<\/li>\n<\/ul>\n<\/li>\n<li>A new subdivision is being built outside of Terrace. There are 21 new houses. Each house needs 25.2 metric tons of crushed rock for the driveway. How much crushed rock will be used to build all the driveways?\n<ul>\n<li>Estimation:<\/li>\n<li>Actual Solution:<\/li>\n<li>Answer:<\/li>\n<\/ul>\n<\/li>\n<li>Union workers who work on statutory holidays are paid double time and a half. This is 2.5 times their regular pay.\n<ol type=\"i\">\n<li>The employees at the coal terminal earn $17.37 per hour. How much are they paid per hour if they work on a statutory holiday?<\/li>\n<li>Jesse worked a 7.5 hour shift at the coal terminal on Labour Day last year. What were his earnings for that day?<\/li>\n<\/ol>\n<\/li>\n<li>Lucy\u2019s aunt in Hartley Bay has a large 50.5 m square vegetable garden. Lucy is going to help her aunt build a barbed wire fence to keep the deer out. The fence will be made with four strands of barbed wire. How much barbed wire should Lucy buy for her aunt? The fence will look like this:<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-188\" src=\"https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2022\/12\/image152-e1672954935821.jpeg\" alt=\"Three fence posts and four lines of barbed wire stretched between the posts.\" width=\"300\" height=\"102\" srcset=\"https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2022\/12\/image152-e1672954935821.jpeg 597w, https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2022\/12\/image152-e1672954935821-300x102.jpeg 300w, https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2022\/12\/image152-e1672954935821-65x22.jpeg 65w, https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2022\/12\/image152-e1672954935821-225x77.jpeg 225w, https:\/\/opentextbc.ca\/alfm4\/wp-content\/uploads\/sites\/421\/2022\/12\/image152-e1672954935821-350x119.jpeg 350w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/p>\n<ul>\n<li>Draw a picture:<\/li>\n<li>Estimation:<\/li>\n<li>Actual Solution:<\/li>\n<li>Answer:<\/li>\n<\/ul>\n<\/li>\n<li>The directions on a carpet shampoo say one bottle will clean 50 m<sup>2<\/sup> of carpet. Joyce wants to clean the wall-to-wall carpet in three rooms. The living room is 6 m by 4.5 m, the bedroom is 3 m by 4 m, and the hall is 1.2 m by 5 m. How many bottles of carpet shampoo should she buy? (This is a two-part question: Calculate the area of each of the rooms and then find the total area to be cleaned. Remember, Joyce cannot buy a partial bottle!)\n<ul>\n<li>Draw a picture:<\/li>\n<li>Estimation:<\/li>\n<li>Actual Solution:<\/li>\n<li>Answer:<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<p><strong>Answers to Exercise 11<\/strong><\/p>\n<ol type=\"a\">\n<li>Estimation: $12 \u00d7 5 \u2248 $60<br \/>\nActual Solution: $11.73 \u00d7 5 =\u00a0 $58.65<br \/>\nFive packages of juice will cost $58.65<\/li>\n<li>Estimation: 1 \u00d7 35 \u2248 35 hours<br \/>\nActual Solution: 0.75 \u00d7 35 = 26.25 hours<br \/>\nIt will take Maria 26.25 hours to install the sinks.<\/li>\n<li>Answers will vary. Please ask your instructor to check your work.<\/li>\n<li>Estimation: 16 km \u00d7 50 L \u2248 800 km<br \/>\nActual Solution: 15.75 km \u00d7 52 L = 819 km<br \/>\nThe truck could travel 819 km.<\/li>\n<li>Estimation: 4 km \u00d7 10 (5 trips there and 5 trips home) \u2248 40 km<br \/>\nActual Solution: 4.3 km \u00d7 10 = 43 km<br \/>\nJackie walks 43 km each week.<\/li>\n<li>Estimation: 25 t \u00d7 20 \u2248 500 t<br \/>\nActual Solution: 25.2 t \u00d7 21 = 529.2 t<br \/>\nThere will be 529.2 metric tons of crushed rock used for the driveways.<\/li>\n<li>Union workers:\n<ol type=\"i\">\n<li>$17.37 \u00d7 2.5 = $43.425 per hour<\/li>\n<li>$43.425 \u00d7 7.5 hours = $325.69.<br \/>\nJesse earned $325.69 on Labour Day.<\/li>\n<\/ol>\n<\/li>\n<li>Estimation: 50 + 50 + 50 + 50 \u2248 200 m, 200 m \u00d7 4 \u2248 800 m<br \/>\nActual Solution: 50.5 m \u00d7 4 = 202 m, 202 m \u00d7 4 = 808 m.<br \/>\nLucy should buy 808 m of barbed wire.<\/li>\n<li><strong>Estimation:\u00a0<\/strong><br \/>\n6 m \u00d7 5 m \u2248 30 m<sup>2<\/sup><br \/>\n3 m \u00d7 4 m \u2248 12 m<sup>2<\/sup><br \/>\n1 m \u00d7 5 m \u2248 5 m<sup>2<\/sup><br \/>\n30 m<sup>2<\/sup> + 12 m<sup>2<\/sup> + 5 m<sup>2<\/sup> \u2248 47 m<sup>2<\/sup><br \/>\n<strong>Actual Solution:\u00a0<\/strong><br \/>\n6 m \u00d7 4.5 m = 27 m<sup>2<\/sup><br \/>\n3 m \u00d7 4 m = 12 m<sup>2<\/sup><br \/>\n1.2 m \u00d7 5 m = 6 m<sup>2<\/sup><br \/>\n27 m<sup>2<\/sup> + 12 m<sup>2<\/sup> + 6 m<sup>2<\/sup> = 45 m<sup>2<\/sup><br \/>\nJoyce should buy just one bottle of carpet cleaner.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<h1>Design Your Own House Project Part 2: Roofing Your House<\/h1>\n<p>Mark: \/16<\/p>\n<p>Use the graph paper house sketch that you made in the Design Your Own House Project Part 1 in <a href=\"https:\/\/opentextbc.ca\/alfm4\/chapter\/subtracting-decimals\/\">Unit 2 &#8211; Topic B: Subtracting Decimals<\/a> to do this activity.<\/p>\n<ol type=\"a\">\n<li>What is the area of your entire house? (area = length \u00d7 width) <strong>\/2<\/strong><\/li>\n<li>Your house has a flat roof and overhangs (meaning &#8220;sticks out past&#8221;) the edges of the house by 0.5 m. Add the overhang to the length and width of your house and find the area of the roof of your house. <strong>\/2<\/strong><\/li>\n<li>Before covering a roof, builders put down tarpaper, which keeps water out. Look at a hardware store flyer or go online and check prices for tarpaper.<strong> \/1<\/strong>\n<ul type=\"a\">\n<li>Choose one type of tarpaper and write down the cost per roll.<\/li>\n<\/ul>\n<\/li>\n<li>Use your answer for question a to figure out how many rolls will you need to cover the entire roof (remember, you cannot buy part of a roll). <strong>\/2<\/strong><\/li>\n<li>Using your answers for questions c and d, calculate what it would cost to cover the entire roof with tarpaper. <strong>\/2<\/strong><\/li>\n<li>Use a flyer or look at hardware stores online and choose a roofing material.\u00a0 <strong>\/1<\/strong>\n<ul type=\"a\">\n<li>Write down your choice.<\/li>\n<\/ul>\n<\/li>\n<li>Roofing shingles are often sold in <strong>bundles<\/strong> that will cover 3 m<sup>2<\/sup>. Metal roofing materials are sold in sheets that will cover 50 square feet, which is the equivalent of 15 m<sup>2<\/sup>. What is the price per bundle or sheet for the material you chose in question f?<strong> \/2<\/strong><\/li>\n<li>Using your answer from question a, calculate how many bundles or sheets of roofing material you will need to cover your roof. \/2<\/li>\n<li>Using your answers from questions g and h, calculate the total cost of roofing your house.<strong> \/2<\/strong><\/li>\n<\/ol>\n<p>When you have finished this project, put your graph paper somewhere safe, because you will be using it again at the end of Unit 5 Topic A.<\/p>\n<h2>Marking Checklist for House Project Part 2<\/h2>\n<p>Calculations:<\/p>\n<ul>\n<li>The area of the house has been calculated correctly.<\/li>\n<li>The area of the roof has been calculated correctly.<\/li>\n<li>The number of rolls of tarpaper has been calculated correctly.<\/li>\n<li>The cost of covering the roof in tarpaper has been calculated correctly.<\/li>\n<li>The number of bundles or sheets of roofing material has been calculated correctly.<\/li>\n<li>The total cost of roofing the house has been calculated correctly.<\/li>\n<\/ul>\n<h1>Topic A: Self-Test<\/h1>\n<p><strong>Mark \/6\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 Aim 5\/6<\/strong><\/p>\n<ol type=\"A\">\n<li>Find the product. (4 marks)\n<ol class=\"twocolumn space\" type=\"a\">\n<li>[latex]\\begin{array}[t]{rr}&66\\\\ \\times&0.7\\\\ \\hline\\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}[t]{rr}&7.25\\\\ \\times&12\\\\ \\hline\\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}[t]{rr}&6.5\\\\ \\times&0.6\\\\ \\hline\\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}[t]{rr}&19.5\\\\ \\times&0.07\\\\ \\hline\\\\ \\end{array}[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>Problems. (2 marks)\n<ol type=\"a\">\n<li>Rhonda bought a 3.4 kg roast at $2.89 per kilogram. What was the cost of her roast? (Round to the nearest cent.)\n<ul type=\"a\">\n<li>Estimation:<\/li>\n<li>Actual Solution:<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<h2>Answers for Topic A: Self Test<\/h2>\n<ol type=\"A\">\n<li>Find the product.\n<ol class=\"twocolumn\" type=\"a\">\n<li>46.2<\/li>\n<li>87<\/li>\n<li>3.9<\/li>\n<li>1.365<\/li>\n<\/ol>\n<\/li>\n<li>Problems.\n<ol type=\"a\">\n<li>Estimate: 3 \u00d7 3 = $9<\/li>\n<li>Actual solution: 3.4 \u00d7 2.89 = 9.826 (round to nearest cent: $9.83). Rhonda paid $9.83 for her roast.<\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<div class=\"glossary\"><span class=\"screen-reader-text\" id=\"definition\">definition<\/span><template id=\"term_428_647\"><div class=\"glossary__definition\" role=\"dialog\" data-id=\"term_428_647\"><div tabindex=\"-1\"><p>Make an approximate answer. Use the sign \u2248 to mean approximately equal.<\/p>\n<\/div><button><span aria-hidden=\"true\">&times;<\/span><span class=\"screen-reader-text\">Close definition<\/span><\/button><\/div><\/template><template id=\"term_428_697\"><div class=\"glossary__definition\" role=\"dialog\" data-id=\"term_428_697\"><div tabindex=\"-1\"><p>The result of a multiplying question, the answer.<\/p>\n<\/div><button><span aria-hidden=\"true\">&times;<\/span><span class=\"screen-reader-text\">Close definition<\/span><\/button><\/div><\/template><template id=\"term_428_631\"><div class=\"glossary__definition\" role=\"dialog\" data-id=\"term_428_631\"><div tabindex=\"-1\"><p>Any of the ten numerals (0 to 9) are digits. This term comes from our ten fingers which are called digits. The numerals came to be called \"digits\" from the practice of counting on the fingers!<\/p>\n<\/div><button><span aria-hidden=\"true\">&times;<\/span><span class=\"screen-reader-text\">Close definition<\/span><\/button><\/div><\/template><template id=\"term_428_625\"><div class=\"glossary__definition\" role=\"dialog\" data-id=\"term_428_625\"><div tabindex=\"-1\"><p>The bottom number in a common fraction; tells into how many equal parts the whole thing has been divided.<\/p>\n<\/div><button><span aria-hidden=\"true\">&times;<\/span><span class=\"screen-reader-text\">Close definition<\/span><\/button><\/div><\/template><template id=\"term_428_727\"><div class=\"glossary__definition\" role=\"dialog\" data-id=\"term_428_727\"><div tabindex=\"-1\"><p>The amount altogether.<\/p>\n<\/div><button><span aria-hidden=\"true\">&times;<\/span><span class=\"screen-reader-text\">Close definition<\/span><\/button><\/div><\/template><\/div>","protected":false},"author":123,"menu_order":1,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-428","chapter","type-chapter","status-publish","hentry"],"part":426,"_links":{"self":[{"href":"https:\/\/opentextbc.ca\/alfm4\/wp-json\/pressbooks\/v2\/chapters\/428","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/opentextbc.ca\/alfm4\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/opentextbc.ca\/alfm4\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/opentextbc.ca\/alfm4\/wp-json\/wp\/v2\/users\/123"}],"version-history":[{"count":25,"href":"https:\/\/opentextbc.ca\/alfm4\/wp-json\/pressbooks\/v2\/chapters\/428\/revisions"}],"predecessor-version":[{"id":982,"href":"https:\/\/opentextbc.ca\/alfm4\/wp-json\/pressbooks\/v2\/chapters\/428\/revisions\/982"}],"part":[{"href":"https:\/\/opentextbc.ca\/alfm4\/wp-json\/pressbooks\/v2\/parts\/426"}],"metadata":[{"href":"https:\/\/opentextbc.ca\/alfm4\/wp-json\/pressbooks\/v2\/chapters\/428\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/opentextbc.ca\/alfm4\/wp-json\/wp\/v2\/media?parent=428"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/opentextbc.ca\/alfm4\/wp-json\/pressbooks\/v2\/chapter-type?post=428"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/opentextbc.ca\/alfm4\/wp-json\/wp\/v2\/contributor?post=428"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/opentextbc.ca\/alfm4\/wp-json\/wp\/v2\/license?post=428"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}