{"id":28,"date":"2021-07-29T16:09:52","date_gmt":"2021-07-29T16:09:52","guid":{"rendered":"https:\/\/opentextbc.ca\/alfm6\/chapter\/rates\/"},"modified":"2025-12-16T22:34:17","modified_gmt":"2025-12-16T22:34:17","slug":"rates","status":"publish","type":"chapter","link":"https:\/\/opentextbc.ca\/alfm6\/chapter\/rates\/","title":{"raw":"Topic B: Rates","rendered":"Topic B: Rates"},"content":{"raw":"When a ratio is used to compare two different units (e.g., apples and oranges, or metres and hours), it is called a rate. The denominator must be 1.\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example A<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nA car can drive 725 km on 55 L of gas. What is the rate in km per L? The ratio of this is [latex]\\dfrac{725\\text{ km}}{55\\text{ L}}[\/latex]. Find the rate by making the denominator 1.\r\n<p style=\"text-align: center;\">Divide [latex]\\dfrac{725}{55} \\div \\left(\\dfrac{55}{55}\\right) = \\dfrac{725\\div55}{55\\div55}=\\dfrac{13.18}{1}=13.18[\/latex]<\/p>\r\nThe rate is <strong>13.18 km\/L<\/strong>.\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example B<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nSue bought 10 lb of oranges for $4.99. What is the rate in cents per pound? The ratio is [latex]\\dfrac{$4.99}{10\\text{ lb}}=\\dfrac{499\\text{ cents}}{10 \\text{ lb}}[\/latex]. Find the rate by making the denominator 1.\r\n<p style=\"text-align: center;\">Divide [latex] \\dfrac{499}{10} \\div \\left(\\dfrac{10}{10}\\right) =\\dfrac{499\\div10}{10\\div10}=\\dfrac{49.9}{1}=49.9[\/latex]<\/p>\r\nThe rate is <strong>49.9 \u00a2\/lb<\/strong>.\r\n\r\n<\/div>\r\n<\/div>\r\nWhen talking about rate, use the word \"per.\"\r\n\r\nIn example A, say, \u201cThe fuel economy of the car is 13.18 kilometres per litre.\u201d\r\n\r\nIn example B, say, \u201cThe oranges cost 49.9 cents per pound.\u201d\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example C<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nIt takes 60 ounces of grass seed to plant 30 m<sup>2<\/sup> of lawn. What is the rate in ounces per square metre (m<sup>2<\/sup>)? The ratio is [latex]\\dfrac{60\\text{ oz}}{30\\text{ m}^2}[\/latex]. Find the rate by making the denominator 1.\r\n<p style=\"text-align: center;\">Divide [latex]\\dfrac{60}{30} \\div \\left(\\dfrac{30}{30}\\right) = \\dfrac{60\\div30}{30\\div30}=\\dfrac{2}{1}=2[\/latex]<\/p>\r\nThe rate is <strong>2 oz\/m<sup>2<\/sup><\/strong>, or <strong>2 ounces per square metre<\/strong>.\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Exercise 1<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nWrite the following ratios as rates, comparing distance to time.\r\n<ol type=\"A\">\r\n \t<li>120 km, 3 hours<\/li>\r\n \t<li>27 km, 9 hours<\/li>\r\n \t<li>203 km, 29 seconds<\/li>\r\n \t<li>444 km, 48 seconds<\/li>\r\n<\/ol>\r\n<strong>Answers to Exercise 1<\/strong>\r\n<ol type=\"A\">\r\n \t<li>40 km\/hour<\/li>\r\n \t<li>3 km\/hour<\/li>\r\n \t<li>7 km\/second<\/li>\r\n \t<li>9.25 km\/second<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Exercise 2<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nWrite the following ratios as rates.\r\n<ol type=\"A\">\r\n \t<li>A leaky faucet can lose 52 litres of water in a week. What is the rate of litres lost per day? (round to two decimal places)<\/li>\r\n \t<li>A ratio of distance travelled to time is called speed. What is the rate (speed) in kilometres per hour (km\/h)?\r\n<ol type=\"i\">\r\n \t<li>45 km, 3 hours<\/li>\r\n \t<li>129 km, 1.5 hours<\/li>\r\n \t<li>65 km, 13 hours<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Vancouver Island has a population of 734,860, and a land mass of 32,134 square kilometres. What is the rate of number of people per square kilometre? (This is called population density.) Round your answer to the nearest whole number.<\/li>\r\n \t<li>At rest, the heart beat of a mouse is 30,000 beats per 60 minutes. What is the rate of beats per minute?<\/li>\r\n<\/ol>\r\n<strong>Answers to Exercise 2<\/strong>\r\n<ol type=\"A\">\r\n \t<li>7.43 L\/day<\/li>\r\n \t<li>\r\n<ol type=\"i\">\r\n \t<li>15 km\/hour<\/li>\r\n \t<li>86 km\/hour<\/li>\r\n \t<li>5 km\/hour<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>23 people\/km<sup>2<\/sup><\/li>\r\n \t<li>500 beats\/minute<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<h1>Topic B: Self-Test<\/h1>\r\n<strong>Mark\u00a0 \u00a0 \u00a0 \u00a0\/7\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 Aim\u00a0 \u00a0 \u00a0 \u00a0 6\/7<\/strong>\r\n<ol type=\"A\">\r\n \t<li>Write the definition. <strong>(1 mark)<\/strong>\r\n<ol type=\"i\">\r\n \t<li>Rate<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Write the following ratios as rates. Round people to the nearest person. <strong>(6 marks)<\/strong>\r\n<ol type=\"i\">\r\n \t<li>12 cups water, 3 cups sugar<\/li>\r\n \t<li>72 metres, 24 seconds<\/li>\r\n \t<li>1,365,000 people, 4,000 km<sup>2<\/sup><\/li>\r\n \t<li>5,000 cars on the road, 250 bikes on the road<\/li>\r\n \t<li>12 cups of flour, 12 tsp. of baking powder<\/li>\r\n \t<li>8 litres of gas, 2 litres of oil<\/li>\r\n<\/ol>\r\n<\/li>\r\n<\/ol>\r\n<div class=\"textbox shaded\">\r\n<h2>Answers to Topic B Self-Test<\/h2>\r\n<ol type=\"A\">\r\n \t<li>A rate is used when a ratio compares two different kinds of measure, and when the denominator is 1.<\/li>\r\n \t<li>\r\n<ol type=\"i\">\r\n \t<li>4 cups of water\/cup of sugar<\/li>\r\n \t<li>3 m\/second<\/li>\r\n \t<li>341 people km<sup>2<\/sup><\/li>\r\n \t<li>20 cars\/bike<\/li>\r\n \t<li>1 cup flour\/tsp baking powder<\/li>\r\n \t<li>4 litres gas\/litre oil<\/li>\r\n<\/ol>\r\n<\/li>\r\n<\/ol>\r\n<\/div>","rendered":"<p>When a ratio is used to compare two different units (e.g., apples and oranges, or metres and hours), it is called a rate. The denominator must be 1.<\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example A<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>A car can drive 725 km on 55 L of gas. What is the rate in km per L? The ratio of this is [latex]\\dfrac{725\\text{ km}}{55\\text{ L}}[\/latex]. Find the rate by making the denominator 1.<\/p>\n<p style=\"text-align: center;\">Divide [latex]\\dfrac{725}{55} \\div \\left(\\dfrac{55}{55}\\right) = \\dfrac{725\\div55}{55\\div55}=\\dfrac{13.18}{1}=13.18[\/latex]<\/p>\n<p>The rate is <strong>13.18 km\/L<\/strong>.<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example B<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Sue bought 10 lb of oranges for $4.99. What is the rate in cents per pound? The ratio is [latex]\\dfrac{$4.99}{10\\text{ lb}}=\\dfrac{499\\text{ cents}}{10 \\text{ lb}}[\/latex]. Find the rate by making the denominator 1.<\/p>\n<p style=\"text-align: center;\">Divide [latex]\\dfrac{499}{10} \\div \\left(\\dfrac{10}{10}\\right) =\\dfrac{499\\div10}{10\\div10}=\\dfrac{49.9}{1}=49.9[\/latex]<\/p>\n<p>The rate is <strong>49.9 \u00a2\/lb<\/strong>.<\/p>\n<\/div>\n<\/div>\n<p>When talking about rate, use the word &#8220;per.&#8221;<\/p>\n<p>In example A, say, \u201cThe fuel economy of the car is 13.18 kilometres per litre.\u201d<\/p>\n<p>In example B, say, \u201cThe oranges cost 49.9 cents per pound.\u201d<\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example C<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>It takes 60 ounces of grass seed to plant 30 m<sup>2<\/sup> of lawn. What is the rate in ounces per square metre (m<sup>2<\/sup>)? The ratio is [latex]\\dfrac{60\\text{ oz}}{30\\text{ m}^2}[\/latex]. Find the rate by making the denominator 1.<\/p>\n<p style=\"text-align: center;\">Divide [latex]\\dfrac{60}{30} \\div \\left(\\dfrac{30}{30}\\right) = \\dfrac{60\\div30}{30\\div30}=\\dfrac{2}{1}=2[\/latex]<\/p>\n<p>The rate is <strong>2 oz\/m<sup>2<\/sup><\/strong>, or <strong>2 ounces per square metre<\/strong>.<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Exercise 1<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Write the following ratios as rates, comparing distance to time.<\/p>\n<ol type=\"A\">\n<li>120 km, 3 hours<\/li>\n<li>27 km, 9 hours<\/li>\n<li>203 km, 29 seconds<\/li>\n<li>444 km, 48 seconds<\/li>\n<\/ol>\n<p><strong>Answers to Exercise 1<\/strong><\/p>\n<ol type=\"A\">\n<li>40 km\/hour<\/li>\n<li>3 km\/hour<\/li>\n<li>7 km\/second<\/li>\n<li>9.25 km\/second<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Exercise 2<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Write the following ratios as rates.<\/p>\n<ol type=\"A\">\n<li>A leaky faucet can lose 52 litres of water in a week. What is the rate of litres lost per day? (round to two decimal places)<\/li>\n<li>A ratio of distance travelled to time is called speed. What is the rate (speed) in kilometres per hour (km\/h)?\n<ol type=\"i\">\n<li>45 km, 3 hours<\/li>\n<li>129 km, 1.5 hours<\/li>\n<li>65 km, 13 hours<\/li>\n<\/ol>\n<\/li>\n<li>Vancouver Island has a population of 734,860, and a land mass of 32,134 square kilometres. What is the rate of number of people per square kilometre? (This is called population density.) Round your answer to the nearest whole number.<\/li>\n<li>At rest, the heart beat of a mouse is 30,000 beats per 60 minutes. What is the rate of beats per minute?<\/li>\n<\/ol>\n<p><strong>Answers to Exercise 2<\/strong><\/p>\n<ol type=\"A\">\n<li>7.43 L\/day<\/li>\n<li>\n<ol type=\"i\">\n<li>15 km\/hour<\/li>\n<li>86 km\/hour<\/li>\n<li>5 km\/hour<\/li>\n<\/ol>\n<\/li>\n<li>23 people\/km<sup>2<\/sup><\/li>\n<li>500 beats\/minute<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<h1>Topic B: Self-Test<\/h1>\n<p><strong>Mark\u00a0 \u00a0 \u00a0 \u00a0\/7\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 Aim\u00a0 \u00a0 \u00a0 \u00a0 6\/7<\/strong><\/p>\n<ol type=\"A\">\n<li>Write the definition. <strong>(1 mark)<\/strong>\n<ol type=\"i\">\n<li>Rate<\/li>\n<\/ol>\n<\/li>\n<li>Write the following ratios as rates. Round people to the nearest person. <strong>(6 marks)<\/strong>\n<ol type=\"i\">\n<li>12 cups water, 3 cups sugar<\/li>\n<li>72 metres, 24 seconds<\/li>\n<li>1,365,000 people, 4,000 km<sup>2<\/sup><\/li>\n<li>5,000 cars on the road, 250 bikes on the road<\/li>\n<li>12 cups of flour, 12 tsp. of baking powder<\/li>\n<li>8 litres of gas, 2 litres of oil<\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<div class=\"textbox shaded\">\n<h2>Answers to Topic B Self-Test<\/h2>\n<ol type=\"A\">\n<li>A rate is used when a ratio compares two different kinds of measure, and when the denominator is 1.<\/li>\n<li>\n<ol type=\"i\">\n<li>4 cups of water\/cup of sugar<\/li>\n<li>3 m\/second<\/li>\n<li>341 people km<sup>2<\/sup><\/li>\n<li>20 cars\/bike<\/li>\n<li>1 cup flour\/tsp baking powder<\/li>\n<li>4 litres gas\/litre oil<\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<\/div>\n","protected":false},"author":125,"menu_order":1,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-28","chapter","type-chapter","status-publish","hentry"],"part":21,"_links":{"self":[{"href":"https:\/\/opentextbc.ca\/alfm6\/wp-json\/pressbooks\/v2\/chapters\/28","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/opentextbc.ca\/alfm6\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/opentextbc.ca\/alfm6\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/opentextbc.ca\/alfm6\/wp-json\/wp\/v2\/users\/125"}],"version-history":[{"count":6,"href":"https:\/\/opentextbc.ca\/alfm6\/wp-json\/pressbooks\/v2\/chapters\/28\/revisions"}],"predecessor-version":[{"id":307,"href":"https:\/\/opentextbc.ca\/alfm6\/wp-json\/pressbooks\/v2\/chapters\/28\/revisions\/307"}],"part":[{"href":"https:\/\/opentextbc.ca\/alfm6\/wp-json\/pressbooks\/v2\/parts\/21"}],"metadata":[{"href":"https:\/\/opentextbc.ca\/alfm6\/wp-json\/pressbooks\/v2\/chapters\/28\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/opentextbc.ca\/alfm6\/wp-json\/wp\/v2\/media?parent=28"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/opentextbc.ca\/alfm6\/wp-json\/pressbooks\/v2\/chapter-type?post=28"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/opentextbc.ca\/alfm6\/wp-json\/wp\/v2\/contributor?post=28"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/opentextbc.ca\/alfm6\/wp-json\/wp\/v2\/license?post=28"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}