Periodic Functions

# Inverse Trigonometric Functions

### Learning Objectives

In this section, you will:

- Understand and use the inverse sine, cosine, and tangent functions.
- Find the exact value of expressions involving the inverse sine, cosine, and tangent functions.
- Use a calculator to evaluate inverse trigonometric functions.
- Find exact values of composite functions with inverse trigonometric functions.

For any right triangle, given one other angle and the length of one side, we can figure out what the other angles and sides are. But what if we are given only two sides of a right triangle? We need a procedure that leads us from a ratio of sides to an angle. This is where the notion of an inverse to a trigonometric function comes into play. In this section, we will explore the inverse trigonometric functions.

### Understanding and Using the Inverse Sine, Cosine, and Tangent Functions

In order to use inverse trigonometric functions, we need to understand that an inverse trigonometric function “undoes” what the original trigonometric function “does,” as is the case with any other function and its inverse. In other words, the domain of the inverse function is the range of the original function, and vice versa, as summarized in (Figure).

For example, ifthen we would writeBe aware thatdoes not meanThe following examples illustrate the inverse trigonometric functions:

- Sincethen
- Sincethen
- Sincethen

In previous sections, we evaluated the trigonometric functions at various angles, but at times we need to know what angle would yield a specific sine, cosine, or tangent value. For this, we need inverse functions. Recall that, for a one-to-one function, ifthen an inverse function would satisfy

Bear in mind that the sine, cosine, and tangent functions are not one-to-one functions. The graph of each function would fail the horizontal line test. In fact, no periodic function can be one-to-one because each output in its range corresponds to at least one input in every period, and there are an infinite number of periods. As with other functions that are not one-to-one, we will need to restrict the domain of each function to yield a new function that is one-to-one. We choose a domain for each function that includes the number 0. (Figure) shows the graph of the sine function limited toand the graph of the cosine function limited to

(Figure) shows the graph of the tangent function limited to

These conventional choices for the restricted domain are somewhat arbitrary, but they have important, helpful characteristics. Each domain includes the origin and some positive values, and most importantly, each results in a one-to-one function that is invertible. The conventional choice for the restricted domain of the tangent function also has the useful property that it extends from one vertical asymptote to the next instead of being divided into two parts by an asymptote.

On these restricted domains, we can define the inverse trigonometric functions.

- The inverse sine functionmeansThe inverse sine function is sometimes called the arcsine function, and notated
- The inverse cosine functionmeansThe inverse cosine function is sometimes called the arccosine function, and notated
- The inverse tangent functionmeansThe inverse tangent function is sometimes called the arctangent function, and notated

The graphs of the inverse functions are shown in (Figure), (Figure), and (Figure). Notice that the output of each of these inverse functions is a *number, *an angle in radian measure. We see thathas domainand range[latex]{\mathrm{cos}}^{-1}x\,[/latex]has domainand rangeandhas domain of all real numbers and rangeTo find the domain and range of inverse trigonometric functions, switch the domain and range of the original functions. Each graph of the inverse trigonometric function is a reflection of the graph of the original function about the line

### Relations for Inverse Sine, Cosine, and Tangent Functions

For angles in the intervalifthen

For angles in the intervalifthen

For angles in the intervalifthen

### Writing a Relation for an Inverse Function

Givenwrite a relation involving the inverse sine.

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Use the relation for the inverse sine. Ifthen.

In this problem,and

### Try It

Givenwrite a relation involving the inverse cosine.

[hidden-answer a=”fs-id1165135176654″]

[/hidden-answer]

### Finding the Exact Value of Expressions Involving the Inverse Sine, Cosine, and Tangent Functions

Now that we can identify inverse functions, we will learn to evaluate them. For most values in their domains, we must evaluate the inverse trigonometric functions by using a calculator, interpolating from a table, or using some other numerical technique. Just as we did with the original trigonometric functions, we can give exact values for the inverse functions when we are using the special angles, specifically(30°),(45°), and(60°), and their reflections into other quadrants.

### How To

**Given a “special” input value, evaluate an inverse trigonometric function.**

- Find anglefor which the original trigonometric function has an output equal to the given input for the inverse trigonometric function.
- Ifis not in the defined range of the inverse, find another anglethat is in the defined range and has the same sine, cosine, or tangent asdepending on which corresponds to the given inverse function.

### Evaluating Inverse Trigonometric Functions for Special Input Values

Evaluate each of the following.

[reveal-answer q=”33620″]Show Solution[/reveal-answer]

[hidden-answer a=”33620″]

- Evaluatingis the same as determining the angle that would have a sine value ofIn other words, what anglewould satisfyThere are multiple values that would satisfy this relationship, such asandbut we know we need the angle in the intervalso the answer will beRemember that the inverse is a function, so for each input, we will get exactly one output.
- To evaluatewe know thatandboth have a sine value ofbut neither is in the intervalFor that, we need the negative angle coterminal with[latex]{\text{sin}}^{-1}\left(-\frac{\sqrt{2}}{2}\right)=-\frac{\pi }{4}.\,[/latex]
- To evaluatewe are looking for an angle in the intervalwith a cosine value ofThe angle that satisfies this is
- Evaluatingwe are looking for an angle in the intervalwith a tangent value of 1. The correct angle is

[/hidden-answer]

### Try It

Evaluate each of the following.

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a.b.c. d.

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### Using a Calculator to Evaluate Inverse Trigonometric Functions

To evaluate inverse trigonometric functions that do not involve the special angles discussed previously, we will need to use a calculator or other type of technology. Most scientific calculators and calculator-emulating applications have specific keys or buttons for the inverse sine, cosine, and tangent functions. These may be labeled, for example, SIN

, ARCSIN, or ASIN.

In the previous chapter, we worked with trigonometry on a right triangle to solve for the sides of a triangle given one side and an additional angle. Using the inverse trigonometric functions, we can solve for the angles of a right triangle given two sides, and we can use a calculator to find the values to several decimal places.

In these examples and exercises, the answers will be interpreted as angles and we will useas the independent variable. The value displayed on the calculator may be in degrees or radians, so be sure to set the mode appropriate to the application.

### Evaluating the Inverse Sine on a Calculator

Evaluateusing a calculator.

[hidden-answer a=”fs-id1165135486002″]Because the output of the inverse function is an angle, the calculator will give us a degree value if in degree mode and a radian value if in radian mode. Calculators also use the same domain restrictions on the angles as we are using.

In radian mode,In degree mode,Note that in calculus and beyond we will use radians in almost all cases.

[/hidden-answer]

### Try It

Evaluateusing a calculator.

[hidden-answer a=”fs-id1165131896087″]

1.9823 or 113.578°

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### How To

**Given two sides of a right triangle like the one shown in (Figure), find an angle.
**

- If one given side is the hypotenuse of lengthand the side of lengthadjacent to the desired angle is given, use the equation
- If one given side is the hypotenuse of lengthand the side of lengthopposite to the desired angle is given, use the equation
- If the two legs (the sides adjacent to the right angle) are given, then use the equation

### Applying the Inverse Cosine to a Right Triangle

Solve the triangle in (Figure) for the angle

[hidden-answer a=”fs-id1165135646119″]

Because we know the hypotenuse and the side adjacent to the angle, it makes sense for us to use the cosine function.

### Try It

Solve the triangle in (Figure) for the angle

[hidden-answer a=”fs-id1165135242701″]

radians

[/hidden-answer]

### Finding Exact Values of Composite Functions with Inverse Trigonometric Functions

There are times when we need to compose a trigonometric function with an inverse trigonometric function. In these cases, we can usually find exact values for the resulting expressions without resorting to a calculator. Even when the input to the composite function is a variable or an expression, we can often find an expression for the output. To help sort out different cases, letandbe two different trigonometric functions belonging to the setand letandbe their inverses.

#### Evaluating Compositions of the Form *f*(*f*^{−1}(*y*)) and *f*^{−1}(*f*(*x*))

For any trigonometric function,for allin the proper domain for the given function. This follows from the definition of the inverse and from the fact that the range ofwas defined to be identical to the domain ofHowever, we have to be a little more careful with expressions of the form

### Compositions of a trigonometric function and its inverse

**Is it correct that
**

*No. This equation is correct ifbelongs to the restricted domainbut sine is defined for all real input values, and foroutside the restricted interval, the equation is not correct because its inverse always returns a value inThe situation is similar for cosine and tangent and their inverses. For example,
*

**Given an expression of the form f ^{−1}(f(θ)) whereevaluate.**

- Ifis in the restricted domain of
- If not, then find an anglewithin the restricted domain ofsuch thatThen

### Using Inverse Trigonometric Functions

Evaluate the following:

[hidden-answer a=”fs-id1165134069364″]

- so
- butso
- so
- butbecause cosine is an even function.
- so

[/hidden-answer]

### Try It

Evaluate

[hidden-answer a=”fs-id1165135543133″]

[/hidden-answer]

#### Evaluating Compositions of the Form *f*^{−1}(*g*(*x*))

Now that we can compose a trigonometric function with its inverse, we can explore how to evaluate a composition of a trigonometric function and the inverse of another trigonometric function. We will begin with compositions of the formFor special values ofwe can exactly evaluate the inner function and then the outer, inverse function. However, we can find a more general approach by considering the relation between the two acute angles of a right triangle where one ismaking the otherConsider the sine and cosine of each angle of the right triangle in (Figure).

Becausewe haveifIfis not in this domain, then we need to find another angle that has the same cosine asand does belong to the restricted domain; we then subtract this angle fromSimilarly,soifThese are just the function-cofunction relationships presented in another way.

**Given functions of the formandevaluate them.**

- Ifthen
- Ifthen find another anglesuch that
- Ifthen
- Ifthen find another anglesuch that

### Evaluating the Composition of an Inverse Sine with a Cosine

Evaluate

- by direct evaluation.
- by the method described previously.

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- Here, we can directly evaluate the inside of the composition.
Now, we can evaluate the inverse function as we did earlier.

- We haveand

[/hidden-answer]

### Try It

Evaluate

[hidden-answer a=”534902″][/hidden-answer]

#### Evaluating Compositions of the Form *f*(*g*^{−1}(*x*))

To evaluate compositions of the formwhereandare any two of the functions sine, cosine, or tangent andis any input in the domain ofwe have exact formulas, such asWhen we need to use them, we can derive these formulas by using the trigonometric relations between the angles and sides of a right triangle, together with the use of Pythagoras’s relation between the lengths of the sides. We can use the Pythagorean identity,to solve for one when given the other. We can also use the inverse trigonometric functions to find compositions involving algebraic expressions.

### Evaluating the Composition of a Sine with an Inverse Cosine

Find an exact value for

[hidden-answer a=”fs-id1165135521197″]

Beginning with the inside, we can say there is some angle such thatwhich meansand we are looking forWe can use the Pythagorean identity to do this.

Sinceis in quadrant I,must be positive, so the solution isSee (Figure).

We know that the inverse cosine always gives an angle on the intervalso we know that the sine of that angle must be positive; therefore[/hidden-answer]

### Try It

Evaluate

[hidden-answer a=”fs-id1165134183828″]

[/hidden-answer]

### Evaluating the Composition of a Sine with an Inverse Tangent

Find an exact value for

[hidden-answer a=”fs-id1165137898214″]

While we could use a similar technique as in (Figure), we will demonstrate a different technique here. From the inside, we know there is an angle such thatWe can envision this as the opposite and adjacent sides on a right triangle, as shown in (Figure).

Using the Pythagorean Theorem, we can find the hypotenuse of this triangle.

Now, we can evaluate the sine of the angle as the opposite side divided by the hypotenuse.

This gives us our desired composition.

### Try It

Evaluate

[hidden-answer a=”fs-id1165134168380″]

[/hidden-answer]

### Finding the Cosine of the Inverse Sine of an Algebraic Expression

Find a simplified expression forfor

[hidden-answer a=”fs-id1165134422226″]

We know there is an anglesuch that

Because we know that the inverse sine must give an angle on the intervalwe can deduce that the cosine of that angle must be positive.

### Try It

Find a simplified expression forfor

[hidden-answer a=”fs-id1165137846318″]

[/hidden-answer]

Access this online resource for additional instruction and practice with inverse trigonometric functions.

Visit this website for additional practice questions from Learningpod.

### Key Concepts

- An inverse function is one that “undoes” another function. The domain of an inverse function is the range of the original function and the range of an inverse function is the domain of the original function.
- Because the trigonometric functions are not one-to-one on their natural domains, inverse trigonometric functions are defined for restricted domains.
- For any trigonometric functionifthenHowever,only impliesifis in the restricted domain ofSee (Figure).
- Special angles are the outputs of inverse trigonometric functions for special input values; for example,See (Figure).
- A calculator will return an angle within the restricted domain of the original trigonometric function. See (Figure).
- Inverse functions allow us to find an angle when given two sides of a right triangle. See (Figure).
- In function composition, if the inside function is an inverse trigonometric function, then there are exact expressions; for example,See (Figure).
- If the inside function is a trigonometric function, then the only possible combinations areifandif See (Figure) and (Figure).
- When evaluating the composition of a trigonometric function with an inverse trigonometric function, draw a reference triangle to assist in determining the ratio of sides that represents the output of the trigonometric function. See (Figure).
- When evaluating the composition of a trigonometric function with an inverse trigonometric function, you may use trig identities to assist in determining the ratio of sides. See (Figure).

### Section Exercises

#### Verbal

Why do the functionsandhave different ranges?

[hidden-answer a=”fs-id1165135316170″]

The functionis one-to-one onthus, this interval is the range of the inverse function of[latex]f\left(x\right)={\mathrm{sin}}^{-1}x.\,[/latex]The functionis one-to-one on thus, this interval is the range of the inverse function of

[/hidden-answer]

Since the functionsandare inverse functions, why isnot equal to

Explain the meaning of

[hidden-answer a=”fs-id1165134301579″]

is the radian measure of an angle betweenandwhose sine is 0.5.

[/hidden-answer]

Most calculators do not have a key to evaluateExplain how this can be done using the cosine function or the inverse cosine function.

Why must the domain of the sine function,be restricted tofor the inverse sine function to exist?

[hidden-answer a=”fs-id1165133307043″]

In order for any function to have an inverse, the function must be one-to-one and must pass the horizontal line test. The regular sine function is not one-to-one unless its domain is restricted in some way. Mathematicians have agreed to restrict the sine function to the intervalso that it is one-to-one and possesses an inverse.

[/hidden-answer]

Discuss why this statement is incorrect:for all

Determine whether the following statement is true or false and explain your answer:

[hidden-answer a=”fs-id1165135539031″]

True . The angle,that equals,, will be a second quadrant angle with reference angle,, whereequals,. Sinceis the reference angle for,and=–

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#### Algebraic

For the following exercises, evaluate the expressions.

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[hidden-answer a=”fs-id1165131963241″]

[/hidden-answer]

[hidden-answer a=”fs-id1165135407285″]

[/hidden-answer]

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For the following exercises, use a calculator to evaluate each expression. Express answers to the nearest hundredth.

[hidden-answer a=”fs-id1165134212021″]

1.98

[/hidden-answer]

[hidden-answer a=”fs-id1165134149965″]

0.93

[/hidden-answer]

[hidden-answer a=”fs-id1165135672744″]

1.41

[/hidden-answer]

For the following exercises, find the anglein the given right triangle. Round answers to the nearest hundredth.

[hidden-answer a=”fs-id1165135672822″]

0.56 radians

[/hidden-answer]

For the following exercises, find the exact value, if possible, without a calculator. If it is not possible, explain why.

[hidden-answer a=”fs-id1165135186154″]

0

[/hidden-answer]

[hidden-answer a=”fs-id1165132005277″]

0.71

[/hidden-answer]

[hidden-answer a=”fs-id1165133362041″]

-0.71

[/hidden-answer]

[hidden-answer a=”fs-id1165134248752″]

[/hidden-answer]

[hidden-answer a=”fs-id1165134261735″]

0.8

[/hidden-answer]

[hidden-answer a=”fs-id1165132947330″]

[/hidden-answer]

For the following exercises, find the exact value of the expression in terms of

with the help of a reference triangle.

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[/hidden-answer]

[hidden-answer a=”fs-id1165135252184″]

[/hidden-answer]

[hidden-answer a=”fs-id1165134081072″]

[/hidden-answer]

#### Extensions

For the following exercises, evaluate the expression without using a calculator. Give the exact value.

For the following exercises, find the function if

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[hidden-answer a=”fs-id1165135532667″]

[/hidden-answer]

[hidden-answer a=”fs-id1165134199402″]

[/hidden-answer]

#### Graphical

Graphand state the domain and range of the function.

Graphand state the domain and range of the function.

[reveal-answer q=”991185″]Show Solution[/reveal-answer]

[hidden-answer a=”991185″]

domainrange

[/hidden-answer]

Graph one cycle ofand state the domain and range of the function.

For what value ofdoesUse a graphing calculator to approximate the answer.

[hidden-answer a=”fs-id1165134312084″]

approximately

[/hidden-answer]

For what value ofdoesUse a graphing calculator to approximate the answer.

#### Real-World Applications

Suppose a 13-foot ladder is leaning against a building, reaching to the bottom of a second-ﬂoor window 12 feet above the ground. What angle, in radians, does the ladder make with the building?

[hidden-answer a=”fs-id1165134167554″]

0.395 radians

[/hidden-answer]

Suppose you drive 0.6 miles on a road so that the vertical distance changes from 0 to 150 feet. What is the angle of elevation of the road?

An isosceles triangle has two congruent sides of length 9 inches. The remaining side has a length of 8 inches. Find the angle that a side of 9 inches makes with the 8-inch side.

[hidden-answer a=”fs-id1165135330858″]

1.11 radians

[/hidden-answer]

Without using a calculator, approximate the value ofExplain why your answer is reasonable.

A truss for the roof of a house is constructed from two identical right triangles. Each has a base of 12 feet and height of 4 feet. Find the measure of the acute angle adjacent to the 4-foot side.

[hidden-answer a=”fs-id1165135330917″]

1.25 radians

[/hidden-answer]

The linepasses through the origin in the *x*,*y*-plane. What is the measure of the angle that the line makes with the positive *x*-axis?

The linepasses through the origin in the *x*,*y*-plane. What is the measure of the angle that the line makes with the negative *x*-axis?

[hidden-answer a=”fs-id1165134301450″]

0.405 radians

[/hidden-answer]

What percentage grade should a road have if the angle of elevation of the road is 4 degrees? (The percentage grade is defined as the change in the altitude of the road over a 100-foot horizontal distance. For example a 5% grade means that the road rises 5 feet for every 100 feet of horizontal distance.)

A 20-foot ladder leans up against the side of a building so that the foot of the ladder is 10 feet from the base of the building. If specifications call for the ladder’s angle of elevation to be between 35 and 45 degrees, does the placement of this ladder satisfy safety specifications?

[hidden-answer a=”fs-id1165134301481″]

No. The angle the ladder makes with the horizontal is 60 degrees.

[/hidden-answer]

Suppose a 15-foot ladder leans against the side of a house so that the angle of elevation of the ladder is 42 degrees. How far is the foot of the ladder from the side of the house?

### Chapter Review Exercises

#### Graphs of the Sine and Cosine Functions

For the following exercises, graph the functions for two periods and determine the amplitude or stretching factor, period, midline equation, and asymptotes.

[hidden-answer a=”fs-id1165135532597″]

amplitude: 3; period:midline:no asymptotes

[/hidden-answer]

[hidden-answer a=”fs-id1165135613593″]

amplitude: 3; period:midline:no asymptotes

[/hidden-answer]

[hidden-answer a=”fs-id1165135640504″]

amplitude: 3; period:midline:no asymptotes

[/hidden-answer]

[hidden-answer a=”fs-id1165135328757″]

amplitude: 6; period:midline:no asymptotes

[/hidden-answer]

#### Graphs of the Other Trigonometric Functions

For the following exercises, graph the functions for two periods and determine the amplitude or stretching factor, period,

midline equation, and asymptotes.

[hidden-answer a=”fs-id1165135203318″]

stretching factor: none; period:midline:asymptotes:whereis an integer

[/hidden-answer]

[hidden-answer a=”fs-id1165135182781″]

stretching factor: 3; period:midline:asymptotes:whereis an integer

[/hidden-answer]

For the following exercises, graph two full periods. Identify the period, the phase shift, the amplitude, and asymptotes.

[hidden-answer a=”fs-id1165134248895″]

amplitude: none; period:no phase shift; asymptotes:whereis an odd integer

[/hidden-answer]

[hidden-answer a=”fs-id1165133362252″]

amplitude: none; period:no phase shift; asymptotes:whereis an integer

[/hidden-answer]

[hidden-answer a=”fs-id1165135360235″]

amplitude: none; period:no phase shift; asymptotes:whereis an integer

[/hidden-answer]

For the following exercises, use this scenario: The population of a city has risen and fallen over a 20-year interval. Its population may be modeled by the following function:where the domain is the years since 1980 and the range is the population of the city.

What is the largest and smallest population the city may have?

[hidden-answer a=”fs-id1165134340034″]

largest: 20,000; smallest: 4,000

[/hidden-answer]

Graph the function on the domain of.

What are the amplitude, period, and phase shift for the function?

[hidden-answer a=”fs-id1165137893242″]

amplitude: 8,000; period: 10; phase shift: 0

[/hidden-answer]

Over this domain, when does the population reach 18,000? 13,000?

What is the predicted population in 2007? 2010?

[hidden-answer a=”fs-id1165137893267″]

In 2007, the predicted population is 4,413. In 2010, the population will be 11,924.

[/hidden-answer]

For the following exercises, suppose a weight is attached to a spring and bobs up and down, exhibiting symmetry.

Suppose the graph of the displacement function is shown in (Figure), where the values on the *x*-axis represent the time in seconds and the *y*-axis represents the displacement in inches. Give the equation that models the vertical displacement of the weight on the spring.

At time = 0, what is the displacement of the weight?

[hidden-answer a=”fs-id1165137893332″]

5 in.

[/hidden-answer]

At what time does the displacement from the equilibrium point equal zero?

What is the time required for the weight to return to its initial height of 5 inches? In other words, what is the period for the displacement function?

[hidden-answer a=”fs-id1165134086186″]

10 seconds

[/hidden-answer]

#### Inverse Trigonometric Functions

For the following exercises, find the exact value without the aid of a calculator.

[hidden-answer a=”fs-id1165134086300″]

[/hidden-answer]

[hidden-answer a=”fs-id1165134430420″]

[/hidden-answer]

[hidden-answer a=”fs-id1165135328715″]

[/hidden-answer]

[hidden-answer a=”fs-id1165135388815″]

No solution

[/hidden-answer]

[hidden-answer a=”fs-id1165134181894″]

[/hidden-answer]

Graphandon the intervaland explain any observations.

[hidden-answer a=”fs-id1165135388603″]

The graphs are not symmetrical with respect to the lineThey are symmetrical with respect to the-axis.

[/hidden-answer]

Graphandand explain any observations.

Graph the functionon the intervaland compare the graph to the graph ofon the same interval. Describe any observations.

[hidden-answer a=”fs-id1165135354967″]

The graphs appear to be identical.

[/hidden-answer]

### Chapter Practice Test

For the following exercises, sketch the graph of each function for two full periods. Determine the amplitude, the period, and the equation for the midline.

[hidden-answer a=”fs-id1165134068899″]

amplitude: 0.5; period:midline

[/hidden-answer]

[hidden-answer a=”fs-id1165134069034″]

amplitude: 5; period:midline:

[/hidden-answer]

[hidden-answer a=”fs-id1165134254285″]

amplitude: 1; period:midline:

[/hidden-answer]

[hidden-answer a=”fs-id1165134116831″]

amplitude: 3; period:midline:

[/hidden-answer]

[hidden-answer a=”fs-id1165134567917″]

amplitude: none; period:midline:asymptotes:whereis an integer

[/hidden-answer]

[hidden-answer a=”fs-id1165135367680″]

amplitude: none; period:midline: asymptotes: whereis an integer

[/hidden-answer]

[hidden-answer a=”fs-id1165135618335″]

amplitude: none; period:midline:

[/hidden-answer]

For the following exercises, determine the amplitude, period, and midline of the graph, and then find a formula for the function.

Give in terms of a sine function.

Give in terms of a sine function.

[hidden-answer a=”fs-id1165134174374″]

amplitude: 2; period: 2; midline:[latex]f\left(x\right)=2\mathrm{sin}\left(\pi \left(x-1\right)\right)[/latex]

[/hidden-answer]

Give in terms of a tangent function.

For the following exercises, find the amplitude, period, phase shift, and midline.

[hidden-answer a=”fs-id1165135600332″]

amplitude: 1; period: 12; phase shift:midline

[/hidden-answer]

The outside temperature over the course of a day can be modeled as a sinusoidal function. Suppose you know the temperature is 68°F at midnight and the high and low temperatures during the day are 80°F and 56°F, respectively. Assumingis the number of hours since midnight, find a function for the temperature,in terms of

[hidden-answer a=”fs-id1165134195393″]

[/hidden-answer]

Water is pumped into a storage bin and empties according to a periodic rate. The depth of the water is 3 feet at its lowest at 2:00 a.m. and 71 feet at its highest, which occurs every 5 hours. Write a cosine function that models the depth of the water as a function of time, and then graph the function for one period.

For the following exercises, find the period and horizontal shift of each function.

[hidden-answer a=”fs-id1165134188920″]

period:horizontal shift:

[/hidden-answer]

Write the equation for the graph in (Figure) in terms of the secant function and give the period and phase shift.

[hidden-answer a=”fs-id1165134418845″]

period: 2; phase shift: 0

[/hidden-answer]

Iffind

Iffind

[hidden-answer a=”fs-id1165134129832″]

[/hidden-answer]

For the following exercises, graph the functions on the specified window and answer the questions.

Graphon the viewing windowbyApproximate the graph’s period.

Graphon the following domains in[latex]\left[0,1\right]\,[/latex]andSuppose this function models sound waves. Why would these views look so different?

[hidden-answer a=”fs-id1165134368153″]

The views are different because the period of the wave isOver a bigger domain, there will be more cycles of the graph.

[/hidden-answer]

Graphonand explain any observations.

For the following exercises, let

What is the largest possible value for

[hidden-answer a=”fs-id1165135436402″]

[/hidden-answer]

What is the smallest possible value for

Where is the function increasing on the interval

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On the approximate intervals

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For the following exercises, find and graph one period of the periodic function with the given amplitude, period, and phase shift.

Sine curve with amplitude 3, periodand phase shift

Cosine curve with amplitude 2, periodand phase shift

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For the following exercises, graph the function. Describe the graph and, wherever applicable, any periodic behavior, amplitude, asymptotes, or undefined points.

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This graph is periodic with a period of

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For the following exercises, find the exact value.

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For the following exercises, suppose

Evaluate the following expressions.

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Given (Figure), find the measure of angleto three decimal places. Answer in radians.

For the following exercises, determine whether the equation is true or false.

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False

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The grade of a road is 7%. This means that for every horizontal distance of 100 feet on the road, the vertical rise is 7 feet. Find the angle the road makes with the horizontal in radians.

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approximately 0.07 radians

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### Glossary

- arccosine
- another name for the inverse cosine;

- arcsine
- another name for the inverse sine;

- arctangent
- another name for the inverse tangent;

- inverse cosine function
- the functionwhich is the inverse of the cosine function and the angle that has a cosine equal to a given number

- inverse sine function
- the functionwhich is the inverse of the sine function and the angle that has a sine equal to a given number

- inverse tangent function
- the function which is the inverse of the tangent function and the angle that has a tangent equal to a given number