{"id":1576,"date":"2021-12-02T19:38:35","date_gmt":"2021-12-03T00:38:35","guid":{"rendered":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/back-matter\/answer-key-chapter-1-2\/"},"modified":"2023-08-31T19:46:54","modified_gmt":"2023-08-31T23:46:54","slug":"answer-key-chapter-1-2","status":"publish","type":"back-matter","link":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/back-matter\/answer-key-chapter-1-2\/","title":{"raw":"Answer Key 1.2","rendered":"Answer Key 1.2"},"content":{"raw":"
    \r\n \t
  1. [latex]\\dfrac{42}{12}\\div\\dfrac{6}{6} = \\dfrac{7}{2}[\/latex]<\/li>\r\n \t
  2. [latex]\\dfrac{25}{20}\\div\\dfrac{5}{5} = \\dfrac{5}{4}[\/latex]<\/li>\r\n \t
  3. [latex]\\dfrac{35}{25}\\div\\dfrac{5}{5} = \\dfrac{7}{5}[\/latex]<\/li>\r\n \t
  4. [latex]\\dfrac{24}{8}\\div\\dfrac{8}{8} = 3[\/latex]<\/li>\r\n \t
  5. [latex]\\dfrac{54}{36}\\div\\dfrac{9}{9} = \\dfrac{6}{4}\\div\\dfrac{2}{2} = \\dfrac{3}{2}[\/latex]<\/li>\r\n \t
  6. [latex]\\dfrac{30}{24}\\div \\dfrac{6}{6} = \\dfrac{5}{4}[\/latex]<\/li>\r\n \t
  7. [latex]\\dfrac{45}{36}\\div \\dfrac{9}{9} = \\dfrac{5}{4}[\/latex]<\/li>\r\n \t
  8. [latex]\\dfrac{36}{27}\\div\\dfrac{9}{9} = \\dfrac{4}{3}[\/latex]<\/li>\r\n \t
  9. [latex]\\dfrac{27}{18}\\div\\dfrac{9}{9} = \\dfrac{3}{2}[\/latex]<\/li>\r\n \t
  10. [latex]\\dfrac{48}{18}\\div\\dfrac{6}{6} = \\dfrac{8}{3}[\/latex]<\/li>\r\n \t
  11. [latex]\\dfrac{40}{16}\\div\\dfrac{8}{8} = \\dfrac{5}{2}[\/latex]<\/li>\r\n \t
  12. [latex]\\dfrac{48}{42}\\div \\dfrac{6}{6} = \\dfrac{8}{7}[\/latex]<\/li>\r\n \t
  13. [latex]\\dfrac{63}{18}\\div\\dfrac{9}{9} = \\dfrac{7}{2}[\/latex]<\/li>\r\n \t
  14. [latex]\\dfrac{16}{12}\\div\\dfrac{4}{4} = \\dfrac{4}{3}[\/latex]<\/li>\r\n \t
  15. [latex]\\dfrac{80}{60} \\div\\dfrac{20}{20} = \\dfrac{4}{3}[\/latex]<\/li>\r\n \t
  16. [latex]\\dfrac{72}{48}\\div\\dfrac{12}{12} = \\dfrac{6}{4}\\div\\dfrac{2}{2} = \\dfrac{3}{2}[\/latex]<\/li>\r\n \t
  17. [latex]\\dfrac{72}{60}\\div\\dfrac{12}{12} = \\dfrac{6}{5}[\/latex]<\/li>\r\n \t
  18. [latex]\\dfrac{126}{108}\\div\\dfrac{9}{9} = \\dfrac{14}{12}\\div\\dfrac{2}{2} = \\dfrac{7}{6}[\/latex]<\/li>\r\n \t
  19. [latex]\\cancel{9} \\cdot \\dfrac{8}{\\cancel{9}} = 8[\/latex]<\/li>\r\n \t
  20. [latex]\\cancel{-2}-1\\cdot -\\dfrac{5}{\\cancel{6}3}=\\dfrac{5}{3}[\/latex]<\/li>\r\n \t
  21. [latex]2 \\cdot -\\dfrac{2}{9} = -\\dfrac{4}{9}[\/latex]<\/li>\r\n \t
  22. [latex]-2\\cdot \\dfrac{1}{3}=-\\dfrac{2}{3}[\/latex]<\/li>\r\n \t
  23. [latex]\\cancel{-2}-1\\cdot \\dfrac{13}{\\cancel{8}4}=-\\dfrac{13}{4}[\/latex]<\/li>\r\n \t
  24. [latex]\\dfrac{3}{2} \\cdot \\dfrac{1}{2} = \\dfrac {3}{4}[\/latex]<\/li>\r\n \t
  25. [latex]-\\dfrac{\\cancel{6}3}{5}\\cdot -\\dfrac{11}{\\cancel{8}4}=\\dfrac{33}{20}[\/latex]<\/li>\r\n \t
  26. [latex]-\\dfrac{3}{7} \\cdot -\\dfrac{11}{8} = \\dfrac{33}{56}[\/latex]<\/li>\r\n \t
  27. [latex]\\cancel{8}4 \\cdot \\dfrac{1}{\\cancel{2}1} = 4[\/latex]<\/li>\r\n \t
  28. [latex]-2 \\cdot -\\dfrac{9}{7} = \\dfrac{18}{7}[\/latex]<\/li>\r\n \t
  29. [latex]\\dfrac{\\cancel{2}1}{\\cancel{3}1} \\cdot \\dfrac{\\cancel{3}1}{\\cancel{4}2} = \\dfrac {1}{2}[\/latex]<\/li>\r\n \t
  30. [latex]-\\dfrac{17}{\\cancel{9}3} \\cdot -\\dfrac{\\cancel{3}1}{5} = \\dfrac{17}{15}[\/latex]<\/li>\r\n \t
  31. [latex]\\cancel{2}1 \\cdot \\dfrac{3}{\\cancel{2}1} = 3[\/latex]<\/li>\r\n \t
  32. [latex]\\dfrac{17}{\\cancel{9}3} \\cdot -\\dfrac{\\cancel{3}1}{5} = -\\dfrac{17}{15}[\/latex]<\/li>\r\n \t
  33. [latex]\\dfrac{1}{2} \\cdot -\\dfrac{7}{5} = -\\dfrac{7}{10}[\/latex]<\/li>\r\n \t
  34. [latex]\\dfrac{1}{2} \\cdot \\dfrac{5}{7} = \\dfrac{5}{14}[\/latex]<\/li>\r\n \t
  35. [latex]\\dfrac{\\cancel{5}1}{2} \\cdot -\\dfrac{0}{\\cancel{5}1} = -\\dfrac{0}{2}\\text{ or }0[\/latex]<\/li>\r\n \t
  36. [latex]\\underbrace{\\dfrac{6}{0}}_{\\text{undefined}} \\cdot \\hspace{0.25in}\\dfrac{6}{7} = \\text{no solution}[\/latex]<\/li>\r\n \t
  37. [latex]-2 \\cdot \\dfrac{4}{7} = -\\dfrac{8}{7}[\/latex]<\/li>\r\n \t
  38. [latex]-\\dfrac{\\cancel{12}4}{7} \\cdot -\\dfrac{5}{\\cancel{9}3} = \\dfrac{20}{21}[\/latex]<\/li>\r\n \t
  39. [latex]-\\dfrac{1}{9} \\cdot -\\dfrac{2}{1} = \\dfrac{2}{9}[\/latex]<\/li>\r\n \t
  40. [latex]-2 \\cdot -\\dfrac{2}{3} = \\dfrac{4}{3}[\/latex]<\/li>\r\n \t
  41. [latex]-\\dfrac{3}{2} \\cdot \\dfrac{7}{13} = -\\dfrac{21}{26}[\/latex]<\/li>\r\n \t
  42. [latex]\\dfrac{5}{3} \\cdot \\dfrac{5}{7} = \\dfrac{25}{21}[\/latex]<\/li>\r\n \t
  43. [latex]-1 \\cdot \\dfrac{3}{2} = -\\dfrac{3}{2}[\/latex]<\/li>\r\n \t
  44. [latex]\\dfrac{\\cancel{10}5}{9} \\cdot -\\dfrac{1}{\\cancel{6}3} = -\\dfrac{5}{27}[\/latex]<\/li>\r\n \t
  45. [latex]\\dfrac{8}{9} \\cdot \\dfrac{5}{1} = \\dfrac{40}{9}[\/latex]<\/li>\r\n \t
  46. [latex]\\dfrac{1}{\\cancel{6}2} \\cdot -\\dfrac{\\cancel{3}1}{5} = -\\dfrac{1}{10}[\/latex]<\/li>\r\n \t
  47. [latex]-\\dfrac{9}{7} \\cdot \\dfrac{5}{1} = -\\dfrac{45}{7}[\/latex]<\/li>\r\n \t
  48. [latex]-\\dfrac{13}{\\cancel{8}1} \\cdot -\\dfrac{\\cancel{8}1}{15} = \\dfrac{13}{15}[\/latex]<\/li>\r\n \t
  49. [latex]-\\dfrac{2}{9} \\cdot -\\dfrac{2}{3} = \\dfrac{4}{27}[\/latex]<\/li>\r\n \t
  50. [latex]-\\dfrac{4}{5} \\cdot -\\dfrac{8}{13} = \\dfrac{32}{65}[\/latex]<\/li>\r\n \t
  51. [latex]\\dfrac{1}{\\cancel{10}5} \\cdot \\dfrac{\\cancel{2}1}{3} = \\dfrac{1}{15}[\/latex]<\/li>\r\n \t
  52. [latex]\\dfrac{\\cancel{5}1}{\\cancel{3}1} \\cdot \\dfrac{\\cancel{3}1}{\\cancel{5}1} = 1[\/latex]<\/li>\r\n \t
  53. [latex]\\dfrac{1}{3}-\\dfrac{4}{3} = -\\dfrac{3}{3}\\text{ or }-1[\/latex]<\/li>\r\n \t
  54. [latex]\\dfrac{1}{7}-\\dfrac{11}{7} = -\\dfrac{10}{7}[\/latex]<\/li>\r\n \t
  55. [latex]\\dfrac{3}{7} - \\dfrac{1}{7} = \\dfrac{2}{7}[\/latex]<\/li>\r\n \t
  56. [latex]\\dfrac{1}{3} + \\dfrac{5}{3} = \\dfrac{6}{3}\\text{ or }2[\/latex]<\/li>\r\n \t
  57. [latex]\\dfrac{11}{6} + \\dfrac{7}{6} = \\dfrac{18}{6}\\text{ or }3[\/latex]<\/li>\r\n \t
  58. [latex] -2 - \\dfrac{15}{8} \\Rightarrow -\\dfrac{16}{8} - \\dfrac{15}{8} = -\\dfrac{31}{8}[\/latex]<\/li>\r\n \t
  59. [latex]\\dfrac{3}{5}+ \\dfrac{5}{4} \\Rightarrow \\dfrac{12}{20} + \\dfrac{25}{20} = \\dfrac {37}{20}[\/latex]<\/li>\r\n \t
  60. [latex]-1- \\dfrac{2}{3} \\Rightarrow -\\dfrac{3}{3} - \\dfrac{2}{3} = -\\dfrac{5}{3}[\/latex]<\/li>\r\n \t
  61. [latex]\\dfrac{2}{5}+ \\dfrac{5}{4} \\Rightarrow \\dfrac{8}{20} + \\dfrac{25}{20} = \\dfrac {33}{20}[\/latex]<\/li>\r\n \t
  62. [latex]\\dfrac{12}{7} - \\dfrac{9}{7} = \\dfrac{3}{7}[\/latex]<\/li>\r\n \t
  63. [latex]\\dfrac{9}{8}- \\dfrac{2}{7} \\Rightarrow \\dfrac {63}{56} - \\dfrac{16}{56} = \\dfrac {47}{56}[\/latex]<\/li>\r\n \t
  64. [latex]-2+ \\dfrac{5}{6} \\Rightarrow -\\dfrac{12}{6} + \\dfrac{5}{6} = -\\dfrac{7}{6}[\/latex]<\/li>\r\n \t
  65. [latex]1-\\dfrac{1}{3} \\Rightarrow \\dfrac{3}{3} - \\dfrac{1}{3} = \\dfrac{2}{3}[\/latex]<\/li>\r\n \t
  66. [latex]\\dfrac{1}{2} - \\dfrac{11}{6} \\Rightarrow \\dfrac{3}{6} - \\dfrac {11}{6} = -\\dfrac{8}{6} \\text{ or } -\\dfrac{4}{3}[\/latex]<\/li>\r\n \t
  67. [latex]-\\dfrac{1}{2} + \\dfrac{3}{2} = \\dfrac{2}{2}\\text{ or }1[\/latex]<\/li>\r\n \t
  68. [latex]\\dfrac{11}{8} - \\dfrac{1}{22} \\Rightarrow \\dfrac{121}{88} - \\dfrac{4}{88} = \\dfrac{117}{88}[\/latex]<\/li>\r\n \t
  69. [latex]\\dfrac{1}{5} + \\dfrac{3}{4} \\Rightarrow \\dfrac{4}{20} + \\dfrac {15}{20} = \\dfrac {19}{20}[\/latex]<\/li>\r\n \t
  70. [latex]\\dfrac{6}{5} - \\dfrac{8}{5} = -\\dfrac{2}{5}[\/latex]<\/li>\r\n<\/ol>","rendered":"
      \n
    1. [latex]\\dfrac{42}{12}\\div\\dfrac{6}{6} = \\dfrac{7}{2}[\/latex]<\/li>\n
    2. [latex]\\dfrac{25}{20}\\div\\dfrac{5}{5} = \\dfrac{5}{4}[\/latex]<\/li>\n
    3. [latex]\\dfrac{35}{25}\\div\\dfrac{5}{5} = \\dfrac{7}{5}[\/latex]<\/li>\n
    4. [latex]\\dfrac{24}{8}\\div\\dfrac{8}{8} = 3[\/latex]<\/li>\n
    5. [latex]\\dfrac{54}{36}\\div\\dfrac{9}{9} = \\dfrac{6}{4}\\div\\dfrac{2}{2} = \\dfrac{3}{2}[\/latex]<\/li>\n
    6. [latex]\\dfrac{30}{24}\\div \\dfrac{6}{6} = \\dfrac{5}{4}[\/latex]<\/li>\n
    7. [latex]\\dfrac{45}{36}\\div \\dfrac{9}{9} = \\dfrac{5}{4}[\/latex]<\/li>\n
    8. [latex]\\dfrac{36}{27}\\div\\dfrac{9}{9} = \\dfrac{4}{3}[\/latex]<\/li>\n
    9. [latex]\\dfrac{27}{18}\\div\\dfrac{9}{9} = \\dfrac{3}{2}[\/latex]<\/li>\n
    10. [latex]\\dfrac{48}{18}\\div\\dfrac{6}{6} = \\dfrac{8}{3}[\/latex]<\/li>\n
    11. [latex]\\dfrac{40}{16}\\div\\dfrac{8}{8} = \\dfrac{5}{2}[\/latex]<\/li>\n
    12. [latex]\\dfrac{48}{42}\\div \\dfrac{6}{6} = \\dfrac{8}{7}[\/latex]<\/li>\n
    13. [latex]\\dfrac{63}{18}\\div\\dfrac{9}{9} = \\dfrac{7}{2}[\/latex]<\/li>\n
    14. [latex]\\dfrac{16}{12}\\div\\dfrac{4}{4} = \\dfrac{4}{3}[\/latex]<\/li>\n
    15. [latex]\\dfrac{80}{60} \\div\\dfrac{20}{20} = \\dfrac{4}{3}[\/latex]<\/li>\n
    16. [latex]\\dfrac{72}{48}\\div\\dfrac{12}{12} = \\dfrac{6}{4}\\div\\dfrac{2}{2} = \\dfrac{3}{2}[\/latex]<\/li>\n
    17. [latex]\\dfrac{72}{60}\\div\\dfrac{12}{12} = \\dfrac{6}{5}[\/latex]<\/li>\n
    18. [latex]\\dfrac{126}{108}\\div\\dfrac{9}{9} = \\dfrac{14}{12}\\div\\dfrac{2}{2} = \\dfrac{7}{6}[\/latex]<\/li>\n
    19. [latex]\\cancel{9} \\cdot \\dfrac{8}{\\cancel{9}} = 8[\/latex]<\/li>\n
    20. [latex]\\cancel{-2}-1\\cdot -\\dfrac{5}{\\cancel{6}3}=\\dfrac{5}{3}[\/latex]<\/li>\n
    21. [latex]2 \\cdot -\\dfrac{2}{9} = -\\dfrac{4}{9}[\/latex]<\/li>\n
    22. [latex]-2\\cdot \\dfrac{1}{3}=-\\dfrac{2}{3}[\/latex]<\/li>\n
    23. [latex]\\cancel{-2}-1\\cdot \\dfrac{13}{\\cancel{8}4}=-\\dfrac{13}{4}[\/latex]<\/li>\n
    24. [latex]\\dfrac{3}{2} \\cdot \\dfrac{1}{2} = \\dfrac {3}{4}[\/latex]<\/li>\n
    25. [latex]-\\dfrac{\\cancel{6}3}{5}\\cdot -\\dfrac{11}{\\cancel{8}4}=\\dfrac{33}{20}[\/latex]<\/li>\n
    26. [latex]-\\dfrac{3}{7} \\cdot -\\dfrac{11}{8} = \\dfrac{33}{56}[\/latex]<\/li>\n
    27. [latex]\\cancel{8}4 \\cdot \\dfrac{1}{\\cancel{2}1} = 4[\/latex]<\/li>\n
    28. [latex]-2 \\cdot -\\dfrac{9}{7} = \\dfrac{18}{7}[\/latex]<\/li>\n
    29. [latex]\\dfrac{\\cancel{2}1}{\\cancel{3}1} \\cdot \\dfrac{\\cancel{3}1}{\\cancel{4}2} = \\dfrac {1}{2}[\/latex]<\/li>\n
    30. [latex]-\\dfrac{17}{\\cancel{9}3} \\cdot -\\dfrac{\\cancel{3}1}{5} = \\dfrac{17}{15}[\/latex]<\/li>\n
    31. [latex]\\cancel{2}1 \\cdot \\dfrac{3}{\\cancel{2}1} = 3[\/latex]<\/li>\n
    32. [latex]\\dfrac{17}{\\cancel{9}3} \\cdot -\\dfrac{\\cancel{3}1}{5} = -\\dfrac{17}{15}[\/latex]<\/li>\n
    33. [latex]\\dfrac{1}{2} \\cdot -\\dfrac{7}{5} = -\\dfrac{7}{10}[\/latex]<\/li>\n
    34. [latex]\\dfrac{1}{2} \\cdot \\dfrac{5}{7} = \\dfrac{5}{14}[\/latex]<\/li>\n
    35. [latex]\\dfrac{\\cancel{5}1}{2} \\cdot -\\dfrac{0}{\\cancel{5}1} = -\\dfrac{0}{2}\\text{ or }0[\/latex]<\/li>\n
    36. [latex]\\underbrace{\\dfrac{6}{0}}_{\\text{undefined}} \\cdot \\hspace{0.25in}\\dfrac{6}{7} = \\text{no solution}[\/latex]<\/li>\n
    37. [latex]-2 \\cdot \\dfrac{4}{7} = -\\dfrac{8}{7}[\/latex]<\/li>\n
    38. [latex]-\\dfrac{\\cancel{12}4}{7} \\cdot -\\dfrac{5}{\\cancel{9}3} = \\dfrac{20}{21}[\/latex]<\/li>\n
    39. [latex]-\\dfrac{1}{9} \\cdot -\\dfrac{2}{1} = \\dfrac{2}{9}[\/latex]<\/li>\n
    40. [latex]-2 \\cdot -\\dfrac{2}{3} = \\dfrac{4}{3}[\/latex]<\/li>\n
    41. [latex]-\\dfrac{3}{2} \\cdot \\dfrac{7}{13} = -\\dfrac{21}{26}[\/latex]<\/li>\n
    42. [latex]\\dfrac{5}{3} \\cdot \\dfrac{5}{7} = \\dfrac{25}{21}[\/latex]<\/li>\n
    43. [latex]-1 \\cdot \\dfrac{3}{2} = -\\dfrac{3}{2}[\/latex]<\/li>\n
    44. [latex]\\dfrac{\\cancel{10}5}{9} \\cdot -\\dfrac{1}{\\cancel{6}3} = -\\dfrac{5}{27}[\/latex]<\/li>\n
    45. [latex]\\dfrac{8}{9} \\cdot \\dfrac{5}{1} = \\dfrac{40}{9}[\/latex]<\/li>\n
    46. [latex]\\dfrac{1}{\\cancel{6}2} \\cdot -\\dfrac{\\cancel{3}1}{5} = -\\dfrac{1}{10}[\/latex]<\/li>\n
    47. [latex]-\\dfrac{9}{7} \\cdot \\dfrac{5}{1} = -\\dfrac{45}{7}[\/latex]<\/li>\n
    48. [latex]-\\dfrac{13}{\\cancel{8}1} \\cdot -\\dfrac{\\cancel{8}1}{15} = \\dfrac{13}{15}[\/latex]<\/li>\n
    49. [latex]-\\dfrac{2}{9} \\cdot -\\dfrac{2}{3} = \\dfrac{4}{27}[\/latex]<\/li>\n
    50. [latex]-\\dfrac{4}{5} \\cdot -\\dfrac{8}{13} = \\dfrac{32}{65}[\/latex]<\/li>\n
    51. [latex]\\dfrac{1}{\\cancel{10}5} \\cdot \\dfrac{\\cancel{2}1}{3} = \\dfrac{1}{15}[\/latex]<\/li>\n
    52. [latex]\\dfrac{\\cancel{5}1}{\\cancel{3}1} \\cdot \\dfrac{\\cancel{3}1}{\\cancel{5}1} = 1[\/latex]<\/li>\n
    53. [latex]\\dfrac{1}{3}-\\dfrac{4}{3} = -\\dfrac{3}{3}\\text{ or }-1[\/latex]<\/li>\n
    54. [latex]\\dfrac{1}{7}-\\dfrac{11}{7} = -\\dfrac{10}{7}[\/latex]<\/li>\n
    55. [latex]\\dfrac{3}{7} - \\dfrac{1}{7} = \\dfrac{2}{7}[\/latex]<\/li>\n
    56. [latex]\\dfrac{1}{3} + \\dfrac{5}{3} = \\dfrac{6}{3}\\text{ or }2[\/latex]<\/li>\n
    57. [latex]\\dfrac{11}{6} + \\dfrac{7}{6} = \\dfrac{18}{6}\\text{ or }3[\/latex]<\/li>\n
    58. [latex]-2 - \\dfrac{15}{8} \\Rightarrow -\\dfrac{16}{8} - \\dfrac{15}{8} = -\\dfrac{31}{8}[\/latex]<\/li>\n
    59. [latex]\\dfrac{3}{5}+ \\dfrac{5}{4} \\Rightarrow \\dfrac{12}{20} + \\dfrac{25}{20} = \\dfrac {37}{20}[\/latex]<\/li>\n
    60. [latex]-1- \\dfrac{2}{3} \\Rightarrow -\\dfrac{3}{3} - \\dfrac{2}{3} = -\\dfrac{5}{3}[\/latex]<\/li>\n
    61. [latex]\\dfrac{2}{5}+ \\dfrac{5}{4} \\Rightarrow \\dfrac{8}{20} + \\dfrac{25}{20} = \\dfrac {33}{20}[\/latex]<\/li>\n
    62. [latex]\\dfrac{12}{7} - \\dfrac{9}{7} = \\dfrac{3}{7}[\/latex]<\/li>\n
    63. [latex]\\dfrac{9}{8}- \\dfrac{2}{7} \\Rightarrow \\dfrac {63}{56} - \\dfrac{16}{56} = \\dfrac {47}{56}[\/latex]<\/li>\n
    64. [latex]-2+ \\dfrac{5}{6} \\Rightarrow -\\dfrac{12}{6} + \\dfrac{5}{6} = -\\dfrac{7}{6}[\/latex]<\/li>\n
    65. [latex]1-\\dfrac{1}{3} \\Rightarrow \\dfrac{3}{3} - \\dfrac{1}{3} = \\dfrac{2}{3}[\/latex]<\/li>\n
    66. [latex]\\dfrac{1}{2} - \\dfrac{11}{6} \\Rightarrow \\dfrac{3}{6} - \\dfrac {11}{6} = -\\dfrac{8}{6} \\text{ or } -\\dfrac{4}{3}[\/latex]<\/li>\n
    67. [latex]-\\dfrac{1}{2} + \\dfrac{3}{2} = \\dfrac{2}{2}\\text{ or }1[\/latex]<\/li>\n
    68. [latex]\\dfrac{11}{8} - \\dfrac{1}{22} \\Rightarrow \\dfrac{121}{88} - \\dfrac{4}{88} = \\dfrac{117}{88}[\/latex]<\/li>\n
    69. [latex]\\dfrac{1}{5} + \\dfrac{3}{4} \\Rightarrow \\dfrac{4}{20} + \\dfrac {15}{20} = \\dfrac {19}{20}[\/latex]<\/li>\n
    70. [latex]\\dfrac{6}{5} - \\dfrac{8}{5} = -\\dfrac{2}{5}[\/latex]<\/li>\n<\/ol>\n","protected":false},"author":90,"menu_order":10,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":"cc-by-nc-sa"},"back-matter-type":[],"contributor":[],"license":[56],"class_list":["post-1576","back-matter","type-back-matter","status-publish","hentry","license-cc-by-nc-sa"],"_links":{"self":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter\/1576","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter"}],"about":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/types\/back-matter"}],"author":[{"embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/users\/90"}],"version-history":[{"count":2,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter\/1576\/revisions"}],"predecessor-version":[{"id":2186,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter\/1576\/revisions\/2186"}],"metadata":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter\/1576\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/media?parent=1576"}],"wp:term":[{"taxonomy":"back-matter-type","embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter-type?post=1576"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/contributor?post=1576"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/license?post=1576"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}