{"id":1982,"date":"2021-12-02T19:40:19","date_gmt":"2021-12-03T00:40:19","guid":{"rendered":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/back-matter\/answer-key-10-4\/"},"modified":"2022-11-02T10:38:54","modified_gmt":"2022-11-02T14:38:54","slug":"answer-key-10-4","status":"publish","type":"back-matter","link":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/back-matter\/answer-key-10-4\/","title":{"raw":"Answer Key 10.4","rendered":"Answer Key 10.4"},"content":{"raw":"<ol type=\"a\">\n \t<li>[latex]2^2-4(4)(-5)\\Rightarrow 4+80=84\\hspace{0.25in} \\therefore 2\\text{ real solutions}[\/latex]<\/li>\n \t<li>[latex](-6)^2-4(9)(1)\\Rightarrow 36-36=0\\hspace{0.25in} \\therefore 1\\text{ real solution}[\/latex]<\/li>\n \t<li>[latex](3)^2-4(2)(-5)\\Rightarrow 9+40=49\\hspace{0.25in} \\therefore 2\\text{ real solutions}[\/latex]<\/li>\n \t<li>[latex]3x^2+5x-3\\Rightarrow (5)^2-4(3)(-3)\\Rightarrow 25+36=61\\hspace{0.25in} \\therefore 2\\text{ real solutions}[\/latex]<\/li>\n \t<li>[latex]3x^2+5x-2\\Rightarrow (5)^2-4(3)(-2)\\Rightarrow 25+24=49\\hspace{0.25in} \\therefore 2\\text{ real solutions}[\/latex]<\/li>\n \t<li>[latex](-8)^2-4(1)(16)\\Rightarrow 64-64=0\\hspace{0.25in} \\therefore 1\\text{ real solution}[\/latex]<\/li>\n \t<li>[latex]a^2+10a-56\\Rightarrow (10)^2-4(1)(-56)\\Rightarrow 100+224=324\\hspace{0.25in} \\therefore 2\\text{ real solutions}[\/latex]<\/li>\n \t<li>[latex]x^2-4x+4\\Rightarrow (-4)^2-4(1)(4)\\Rightarrow 16-16=0\\hspace{0.25in} \\therefore 1\\text{ real solution}[\/latex]<\/li>\n \t<li>[latex]5x^2-10x+26\\Rightarrow (-10)^2-4(5)(26)\\Rightarrow 100-520=-420[\/latex]\n[latex] \\therefore2\\text{ non-real solutions}[\/latex]<\/li>\n \t<li>[latex]n^2-10n+21\\Rightarrow (-10)^2-4(1)(21)\\Rightarrow 100-84=16[\/latex]\n[latex] \\therefore2\\text{ real solutions}[\/latex]<\/li>\n<\/ol>\n&nbsp;\n<ol>\n \t<li>[latex]\\phantom{a}[\/latex]\n[latex]\\begin{array}[t]{rrl}\na&amp;=&amp;\\phantom{-}4 \\\\\nb&amp;=&amp;\\phantom{-}3 \\\\\nc&amp;=&amp;-6 \\\\ \\\\\na&amp;=&amp;\\dfrac{-3\\pm \\sqrt{3^2-4(4)(-6)}}{2(4)} \\\\ \\\\\na&amp;=&amp;\\dfrac{-3\\pm \\sqrt{9+96}}{8} \\\\ \\\\\na&amp;=&amp;\\dfrac{-3\\pm \\sqrt{105}}{8}\n\\end{array}[\/latex]<\/li>\n \t<li>[latex]\\phantom{a}[\/latex]\n[latex]\\begin{array}[t]{rrl}\na&amp;=&amp;\\phantom{-}3 \\\\\nb&amp;=&amp;\\phantom{-}2 \\\\\nc&amp;=&amp;-3 \\\\ \\\\\nk&amp;=&amp;\\dfrac{-2\\pm \\sqrt{2^2-4(3)(-3)}}{2(3)} \\\\ \\\\\nk&amp;=&amp;\\dfrac{-2\\pm \\sqrt{4+36}}{6} \\\\ \\\\\nk&amp;=&amp;\\dfrac{-2\\pm \\sqrt{40}}{6} \\\\ \\\\\nk&amp;=&amp;\\dfrac{-2\\pm 2\\sqrt{10}}{6} \\Rightarrow \\dfrac{-1\\pm \\sqrt{10}}{3}\n\\end{array}[\/latex]<\/li>\n \t<li>[latex]\\phantom{a}[\/latex]\n[latex]\\begin{array}[t]{rrl}\na&amp;=&amp;\\phantom{-}2 \\\\\nb&amp;=&amp;-8 \\\\\nc&amp;=&amp;-2 \\\\ \\\\\nx&amp;=&amp;\\dfrac{-(-8)\\pm \\sqrt{(-8)^2-4(2)(-2)}}{2(2)} \\\\ \\\\\nx&amp;=&amp;\\dfrac{8\\pm \\sqrt{64+16}}{4} \\\\ \\\\\nx&amp;=&amp;\\dfrac{8\\pm \\sqrt{80}}{4} \\\\ \\\\\nx&amp;=&amp;\\dfrac{8\\pm 4\\sqrt{5}}{4}\\Rightarrow 2\\pm \\sqrt{5}\n\\end{array}[\/latex]<\/li>\n \t<li>[latex]\\phantom{a}[\/latex]\n[latex]\\begin{array}[t]{rrl}\na&amp;=&amp;\\phantom{-}6 \\\\\nb&amp;=&amp;\\phantom{-}8 \\\\\nc&amp;=&amp;-1 \\\\ \\\\\nn&amp;=&amp;\\dfrac{-8\\pm \\sqrt{8^2-4(6)(-1)}}{2(6)} \\\\ \\\\\nn&amp;=&amp;\\dfrac{-8\\pm \\sqrt{64+24}}{12} \\\\ \\\\\nn&amp;=&amp;\\dfrac{-8\\pm \\sqrt{88}}{12} \\\\ \\\\\nn&amp;=&amp;\\dfrac{-8\\pm 2\\sqrt{22}}{12}\\Rightarrow \\dfrac{-4\\pm \\sqrt{22}}{6}\n\\end{array}[\/latex]<\/li>\n \t<li>[latex]\\phantom{a}[\/latex]\n[latex]\\begin{array}[t]{rrl}\na&amp;=&amp;\\phantom{-}2 \\\\\nb&amp;=&amp;-3 \\\\\nc&amp;=&amp;\\phantom{-}6 \\\\ \\\\\nm&amp;=&amp;\\dfrac{-(-3)\\pm \\sqrt{(-3)^2-4(2)(6)}}{2(2)} \\\\ \\\\\nm&amp;=&amp;\\dfrac{3\\pm \\sqrt{9-48}}{4} \\\\ \\\\\nm&amp;=&amp;\\dfrac{3\\pm \\sqrt{-39}}{4} \\\\ \\\\\n\\end{array}[\/latex]\nA negative square root means there are 2 non-real solutions or no real solution.<\/li>\n \t<li>[latex]\\phantom{a}[\/latex]\n[latex]\\begin{array}[t]{rrl}\na&amp;=&amp;5 \\\\\nb&amp;=&amp;2 \\\\\nc&amp;=&amp;6 \\\\ \\\\\np&amp;=&amp;\\dfrac{-2\\pm \\sqrt{2^2-4(5)(6)}}{2(5)} \\\\ \\\\\np&amp;=&amp;\\dfrac{-2\\pm \\sqrt{4-120}}{10} \\\\ \\\\\np&amp;=&amp;\\dfrac{-2\\pm \\sqrt{-116}}{10}\n\\end{array}[\/latex]\nA negative square root means there are 2 non-real solutions or no real solution.<\/li>\n \t<li>[latex]\\phantom{a}[\/latex]\n[latex]\\begin{array}[t]{rrl}\na&amp;=&amp;\\phantom{-}3 \\\\\nb&amp;=&amp;-2 \\\\\nc&amp;=&amp;-1 \\\\ \\\\\nr&amp;=&amp;\\dfrac{-(-2)\\pm \\sqrt{(-2)^2-4(3)(-1)}}{2(3)} \\\\ \\\\\nr&amp;=&amp;\\dfrac{2\\pm \\sqrt{4+12}}{6} \\\\ \\\\\nr&amp;=&amp;\\dfrac{2\\pm \\sqrt{16}}{6} \\\\ \\\\\nr&amp;=&amp;\\dfrac{2\\pm 4}{6} \\Rightarrow 1, -\\dfrac{1}{3}\n\\end{array}[\/latex]<\/li>\n \t<li>[latex]\\phantom{a}[\/latex]\n[latex]\\begin{array}[t]{rrl}\na&amp;=&amp;\\phantom{-0}2 \\\\\nb&amp;=&amp;-\\phantom{0}2 \\\\\nc&amp;=&amp;-15 \\\\ \\\\\nx&amp;=&amp;\\dfrac{-(-2)\\pm \\sqrt{(-2)^2-4(2)(-15)}}{2(2)} \\\\ \\\\\nx&amp;=&amp;\\dfrac{2\\pm \\sqrt{4+120}}{4} \\\\ \\\\\nx&amp;=&amp;\\dfrac{2\\pm \\sqrt{124}}{4} \\\\ \\\\\nx&amp;=&amp;\\dfrac{2\\pm 2\\sqrt{31}}{4} \\Rightarrow \\dfrac{1\\pm \\sqrt{31}}{2}\n\\end{array}[\/latex]<\/li>\n \t<li>[latex]\\phantom{a}[\/latex]\n[latex]\\begin{array}[t]{rrl}\na&amp;=&amp;\\phantom{0}4 \\\\\nb&amp;=&amp;-3 \\\\\nc&amp;=&amp;10 \\\\ \\\\\nn&amp;=&amp;\\dfrac{-(-3)\\pm \\sqrt{(-3)^2-4(4)(10)}}{2(4)} \\\\ \\\\\nn&amp;=&amp;\\dfrac{3\\pm \\sqrt{9-160}}{8} \\\\ \\\\\nn&amp;=&amp;\\dfrac{3\\pm \\sqrt{-151}}{8} \\\\ \\\\\n\\end{array}[\/latex]\n[latex]\\therefore[\/latex]\u00a02 non-real solutions<\/li>\n \t<li>[latex]\\phantom{a}[\/latex]\n[latex]\\begin{array}[t]{rrl}\na&amp;=&amp;1 \\\\\nb&amp;=&amp;6 \\\\\nc&amp;=&amp;9 \\\\ \\\\\nb&amp;=&amp;\\dfrac{-6\\pm \\sqrt{6^2-4(1)(9)}}{2(1)} \\\\ \\\\\nb&amp;=&amp;\\dfrac{-6\\pm 0\\cancel{\\sqrt{36-36}}}{2} \\\\ \\\\\nb&amp;=&amp;\\dfrac{-6}{2}\\Rightarrow -3\n\\end{array}[\/latex]<\/li>\n \t<li>[latex]\\phantom{a}[\/latex]\n[latex]\\begin{array}[t]{rrrrrrrrrrr}\nv^2&amp;-&amp;4v&amp;-&amp;5&amp;=&amp;-8&amp;&amp;&amp;&amp; \\\\\n&amp;&amp;&amp;+&amp;8&amp;&amp;+8&amp;&amp;&amp;&amp; \\\\\n\\hline\n&amp;&amp;&amp;&amp;0&amp;=&amp;v^2&amp;-&amp;4v&amp;+&amp;3\n\\end{array}[\/latex][latex]\\begin{array}{rrl}\na&amp;=&amp;\\phantom{-}1 \\\\\nb&amp;=&amp;-4 \\\\\nc&amp;=&amp;\\phantom{-}3 \\\\ \\\\\nv&amp;=&amp;\\dfrac{-(-4)\\pm \\sqrt{(-4)^2-4(1)(3)}}{2(1)} \\\\ \\\\\nv&amp;=&amp;\\dfrac{4\\pm \\sqrt{16-12}}{2} \\\\ \\\\\nv&amp;=&amp;\\dfrac{4\\pm \\sqrt{4}}{2} \\\\ \\\\\nv&amp;=&amp;\\dfrac{4\\pm 2}{2}\\Rightarrow 2 \\pm 1 \\\\ \\\\\nv&amp;=&amp;3, 1\n\\end{array}[\/latex]<\/li>\n \t<li>[latex]\\phantom{a}[\/latex]\n[latex]\\begin{array}[t]{rrrrrrrrrrr}\nx^2&amp;+&amp;2x&amp;+&amp;6&amp;=&amp;4&amp;&amp;&amp;&amp; \\\\\n&amp;&amp;&amp;-&amp;4&amp;&amp;-4&amp;&amp;&amp;&amp; \\\\\n\\hline\n&amp;&amp;&amp;&amp;0&amp;=&amp;x^2&amp;+&amp;2x&amp;+&amp;2\n\\end{array}\\\\ \\begin{array}{rrl}\na&amp;=&amp;1 \\\\\nb&amp;=&amp;2 \\\\\nc&amp;=&amp;2 \\\\ \\\\\nx&amp;=&amp;\\dfrac{-2\\pm \\sqrt{2^2-4(1)(2)}}{2(1)} \\\\ \\\\\nx&amp;=&amp;\\dfrac{-2\\pm \\sqrt{4-8}}{2} \\\\ \\\\\nx&amp;=&amp;\\dfrac{-2\\pm \\sqrt{-4}}{2}\n\\end{array}[\/latex][latex]\\therefore[\/latex] 2 non-real solutions<\/li>\n<\/ol>","rendered":"<ol type=\"a\">\n<li>[latex]2^2-4(4)(-5)\\Rightarrow 4+80=84\\hspace{0.25in} \\therefore 2\\text{ real solutions}[\/latex]<\/li>\n<li>[latex](-6)^2-4(9)(1)\\Rightarrow 36-36=0\\hspace{0.25in} \\therefore 1\\text{ real solution}[\/latex]<\/li>\n<li>[latex](3)^2-4(2)(-5)\\Rightarrow 9+40=49\\hspace{0.25in} \\therefore 2\\text{ real solutions}[\/latex]<\/li>\n<li>[latex]3x^2+5x-3\\Rightarrow (5)^2-4(3)(-3)\\Rightarrow 25+36=61\\hspace{0.25in} \\therefore 2\\text{ real solutions}[\/latex]<\/li>\n<li>[latex]3x^2+5x-2\\Rightarrow (5)^2-4(3)(-2)\\Rightarrow 25+24=49\\hspace{0.25in} \\therefore 2\\text{ real solutions}[\/latex]<\/li>\n<li>[latex](-8)^2-4(1)(16)\\Rightarrow 64-64=0\\hspace{0.25in} \\therefore 1\\text{ real solution}[\/latex]<\/li>\n<li>[latex]a^2+10a-56\\Rightarrow (10)^2-4(1)(-56)\\Rightarrow 100+224=324\\hspace{0.25in} \\therefore 2\\text{ real solutions}[\/latex]<\/li>\n<li>[latex]x^2-4x+4\\Rightarrow (-4)^2-4(1)(4)\\Rightarrow 16-16=0\\hspace{0.25in} \\therefore 1\\text{ real solution}[\/latex]<\/li>\n<li>[latex]5x^2-10x+26\\Rightarrow (-10)^2-4(5)(26)\\Rightarrow 100-520=-420[\/latex]<br \/>\n[latex]\\therefore2\\text{ non-real solutions}[\/latex]<\/li>\n<li>[latex]n^2-10n+21\\Rightarrow (-10)^2-4(1)(21)\\Rightarrow 100-84=16[\/latex]<br \/>\n[latex]\\therefore2\\text{ real solutions}[\/latex]<\/li>\n<\/ol>\n<p>&nbsp;<\/p>\n<ol>\n<li>[latex]\\phantom{a}[\/latex]<br \/>\n[latex]\\begin{array}[t]{rrl} a&=&\\phantom{-}4 \\\\ b&=&\\phantom{-}3 \\\\ c&=&-6 \\\\ \\\\ a&=&\\dfrac{-3\\pm \\sqrt{3^2-4(4)(-6)}}{2(4)} \\\\ \\\\ a&=&\\dfrac{-3\\pm \\sqrt{9+96}}{8} \\\\ \\\\ a&=&\\dfrac{-3\\pm \\sqrt{105}}{8} \\end{array}[\/latex]<\/li>\n<li>[latex]\\phantom{a}[\/latex]<br \/>\n[latex]\\begin{array}[t]{rrl} a&=&\\phantom{-}3 \\\\ b&=&\\phantom{-}2 \\\\ c&=&-3 \\\\ \\\\ k&=&\\dfrac{-2\\pm \\sqrt{2^2-4(3)(-3)}}{2(3)} \\\\ \\\\ k&=&\\dfrac{-2\\pm \\sqrt{4+36}}{6} \\\\ \\\\ k&=&\\dfrac{-2\\pm \\sqrt{40}}{6} \\\\ \\\\ k&=&\\dfrac{-2\\pm 2\\sqrt{10}}{6} \\Rightarrow \\dfrac{-1\\pm \\sqrt{10}}{3} \\end{array}[\/latex]<\/li>\n<li>[latex]\\phantom{a}[\/latex]<br \/>\n[latex]\\begin{array}[t]{rrl} a&=&\\phantom{-}2 \\\\ b&=&-8 \\\\ c&=&-2 \\\\ \\\\ x&=&\\dfrac{-(-8)\\pm \\sqrt{(-8)^2-4(2)(-2)}}{2(2)} \\\\ \\\\ x&=&\\dfrac{8\\pm \\sqrt{64+16}}{4} \\\\ \\\\ x&=&\\dfrac{8\\pm \\sqrt{80}}{4} \\\\ \\\\ x&=&\\dfrac{8\\pm 4\\sqrt{5}}{4}\\Rightarrow 2\\pm \\sqrt{5} \\end{array}[\/latex]<\/li>\n<li>[latex]\\phantom{a}[\/latex]<br \/>\n[latex]\\begin{array}[t]{rrl} a&=&\\phantom{-}6 \\\\ b&=&\\phantom{-}8 \\\\ c&=&-1 \\\\ \\\\ n&=&\\dfrac{-8\\pm \\sqrt{8^2-4(6)(-1)}}{2(6)} \\\\ \\\\ n&=&\\dfrac{-8\\pm \\sqrt{64+24}}{12} \\\\ \\\\ n&=&\\dfrac{-8\\pm \\sqrt{88}}{12} \\\\ \\\\ n&=&\\dfrac{-8\\pm 2\\sqrt{22}}{12}\\Rightarrow \\dfrac{-4\\pm \\sqrt{22}}{6} \\end{array}[\/latex]<\/li>\n<li>[latex]\\phantom{a}[\/latex]<br \/>\n[latex]\\begin{array}[t]{rrl} a&=&\\phantom{-}2 \\\\ b&=&-3 \\\\ c&=&\\phantom{-}6 \\\\ \\\\ m&=&\\dfrac{-(-3)\\pm \\sqrt{(-3)^2-4(2)(6)}}{2(2)} \\\\ \\\\ m&=&\\dfrac{3\\pm \\sqrt{9-48}}{4} \\\\ \\\\ m&=&\\dfrac{3\\pm \\sqrt{-39}}{4} \\\\ \\\\ \\end{array}[\/latex]<br \/>\nA negative square root means there are 2 non-real solutions or no real solution.<\/li>\n<li>[latex]\\phantom{a}[\/latex]<br \/>\n[latex]\\begin{array}[t]{rrl} a&=&5 \\\\ b&=&2 \\\\ c&=&6 \\\\ \\\\ p&=&\\dfrac{-2\\pm \\sqrt{2^2-4(5)(6)}}{2(5)} \\\\ \\\\ p&=&\\dfrac{-2\\pm \\sqrt{4-120}}{10} \\\\ \\\\ p&=&\\dfrac{-2\\pm \\sqrt{-116}}{10} \\end{array}[\/latex]<br \/>\nA negative square root means there are 2 non-real solutions or no real solution.<\/li>\n<li>[latex]\\phantom{a}[\/latex]<br \/>\n[latex]\\begin{array}[t]{rrl} a&=&\\phantom{-}3 \\\\ b&=&-2 \\\\ c&=&-1 \\\\ \\\\ r&=&\\dfrac{-(-2)\\pm \\sqrt{(-2)^2-4(3)(-1)}}{2(3)} \\\\ \\\\ r&=&\\dfrac{2\\pm \\sqrt{4+12}}{6} \\\\ \\\\ r&=&\\dfrac{2\\pm \\sqrt{16}}{6} \\\\ \\\\ r&=&\\dfrac{2\\pm 4}{6} \\Rightarrow 1, -\\dfrac{1}{3} \\end{array}[\/latex]<\/li>\n<li>[latex]\\phantom{a}[\/latex]<br \/>\n[latex]\\begin{array}[t]{rrl} a&=&\\phantom{-0}2 \\\\ b&=&-\\phantom{0}2 \\\\ c&=&-15 \\\\ \\\\ x&=&\\dfrac{-(-2)\\pm \\sqrt{(-2)^2-4(2)(-15)}}{2(2)} \\\\ \\\\ x&=&\\dfrac{2\\pm \\sqrt{4+120}}{4} \\\\ \\\\ x&=&\\dfrac{2\\pm \\sqrt{124}}{4} \\\\ \\\\ x&=&\\dfrac{2\\pm 2\\sqrt{31}}{4} \\Rightarrow \\dfrac{1\\pm \\sqrt{31}}{2} \\end{array}[\/latex]<\/li>\n<li>[latex]\\phantom{a}[\/latex]<br \/>\n[latex]\\begin{array}[t]{rrl} a&=&\\phantom{0}4 \\\\ b&=&-3 \\\\ c&=&10 \\\\ \\\\ n&=&\\dfrac{-(-3)\\pm \\sqrt{(-3)^2-4(4)(10)}}{2(4)} \\\\ \\\\ n&=&\\dfrac{3\\pm \\sqrt{9-160}}{8} \\\\ \\\\ n&=&\\dfrac{3\\pm \\sqrt{-151}}{8} \\\\ \\\\ \\end{array}[\/latex]<br \/>\n[latex]\\therefore[\/latex]\u00a02 non-real solutions<\/li>\n<li>[latex]\\phantom{a}[\/latex]<br \/>\n[latex]\\begin{array}[t]{rrl} a&=&1 \\\\ b&=&6 \\\\ c&=&9 \\\\ \\\\ b&=&\\dfrac{-6\\pm \\sqrt{6^2-4(1)(9)}}{2(1)} \\\\ \\\\ b&=&\\dfrac{-6\\pm 0\\cancel{\\sqrt{36-36}}}{2} \\\\ \\\\ b&=&\\dfrac{-6}{2}\\Rightarrow -3 \\end{array}[\/latex]<\/li>\n<li>[latex]\\phantom{a}[\/latex]<br \/>\n[latex]\\begin{array}[t]{rrrrrrrrrrr} v^2&-&4v&-&5&=&-8&&&& \\\\ &&&+&8&&+8&&&& \\\\ \\hline &&&&0&=&v^2&-&4v&+&3 \\end{array}[\/latex][latex]\\begin{array}{rrl} a&=&\\phantom{-}1 \\\\ b&=&-4 \\\\ c&=&\\phantom{-}3 \\\\ \\\\ v&=&\\dfrac{-(-4)\\pm \\sqrt{(-4)^2-4(1)(3)}}{2(1)} \\\\ \\\\ v&=&\\dfrac{4\\pm \\sqrt{16-12}}{2} \\\\ \\\\ v&=&\\dfrac{4\\pm \\sqrt{4}}{2} \\\\ \\\\ v&=&\\dfrac{4\\pm 2}{2}\\Rightarrow 2 \\pm 1 \\\\ \\\\ v&=&3, 1 \\end{array}[\/latex]<\/li>\n<li>[latex]\\phantom{a}[\/latex]<br \/>\n[latex]\\begin{array}[t]{rrrrrrrrrrr} x^2&+&2x&+&6&=&4&&&& \\\\ &&&-&4&&-4&&&& \\\\ \\hline &&&&0&=&x^2&+&2x&+&2 \\end{array}\\\\ \\begin{array}{rrl} a&=&1 \\\\ b&=&2 \\\\ c&=&2 \\\\ \\\\ x&=&\\dfrac{-2\\pm \\sqrt{2^2-4(1)(2)}}{2(1)} \\\\ \\\\ x&=&\\dfrac{-2\\pm \\sqrt{4-8}}{2} \\\\ \\\\ x&=&\\dfrac{-2\\pm \\sqrt{-4}}{2} \\end{array}[\/latex][latex]\\therefore[\/latex] 2 non-real solutions<\/li>\n<\/ol>\n","protected":false},"author":90,"menu_order":96,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":"cc-by-nc-sa"},"back-matter-type":[],"contributor":[],"license":[56],"class_list":["post-1982","back-matter","type-back-matter","status-publish","hentry","license-cc-by-nc-sa"],"_links":{"self":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter\/1982","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter"}],"about":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/types\/back-matter"}],"author":[{"embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/users\/90"}],"version-history":[{"count":1,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter\/1982\/revisions"}],"predecessor-version":[{"id":1983,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter\/1982\/revisions\/1983"}],"metadata":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter\/1982\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/media?parent=1982"}],"wp:term":[{"taxonomy":"back-matter-type","embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter-type?post=1982"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/contributor?post=1982"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/license?post=1982"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}