{"id":2022,"date":"2021-12-02T19:40:31","date_gmt":"2021-12-03T00:40:31","guid":{"rendered":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/back-matter\/answer-key-11-4\/"},"modified":"2023-08-22T16:46:14","modified_gmt":"2023-08-22T20:46:14","slug":"answer-key-11-4","status":"publish","type":"back-matter","link":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/back-matter\/answer-key-11-4\/","title":{"raw":"Answer Key 11.4","rendered":"Answer Key 11.4"},"content":{"raw":"
    \r\n \t
  1. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrrrrrrr}\r\n&1&-&2n&=&1&-&3n \\\\\r\n-&1&+&3n&&-1&+&3n \\\\\r\n\\hline\r\n&&&n&=&0&&\r\n\\end{array}[\/latex]<\/li>\r\n \t
  2. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n4^{2x}&=&4^{-2} \\\\ \\\\\r\n\\dfrac{2x}{2}&=&\\dfrac{-2}{2} \\\\ \\\\\r\nx&=&-1\r\n\\end{array}[\/latex]<\/li>\r\n \t
  3. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n4^{2a}&=&4^0 \\\\\r\n2a&=&0 \\\\\r\na&=&0\r\n\\end{array}[\/latex]<\/li>\r\n \t
  4. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(4^2)^{-3p}&=&(4^3)^{3p} \\\\\r\n4^{-6p}&=&4^{9p} \\\\\r\n-6p&=&\\phantom{+}9p \\\\\r\n+6p&&+6p \\\\\r\n\\hline\r\n0&=&15p \\\\ \\\\\r\np&=&0\r\n\\end{array}[\/latex]<\/li>\r\n \t
  5. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(5^{-2})^{-k}&=&(5^3)^{-2k-2} \\\\\r\n5^{2k}&=&5^{-6k-6} \\\\\r\n2k&=&-6k-6 \\\\\r\n+6k&&+6k \\\\\r\n\\hline\r\n8k&=&-6 \\\\ \\\\\r\nk&=&-\\dfrac{6}{8}\\Rightarrow -\\dfrac{3}{4}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  6. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(5)^{4(-n-2)}&=&(5)^{-3} \\\\\r\n5^{-4n-8}&=&5^{-3} \\\\\r\n-4n-8&=&-3 \\\\\r\n4n+8&=&\\phantom{-}3 \\\\\r\n-8&&-8 \\\\\r\n\\hline\r\n4n&=&-5 \\\\ \\\\\r\nn&=&-\\dfrac{5}{4}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  7. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n6^{2m+1}&=&6^{-2} \\\\\r\n2m+1&=&-2 \\\\\r\n-1&&-1 \\\\\r\n\\hline\r\n2m&=&-3 \\\\ \\\\\r\nm&=&-\\dfrac{3}{2}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  8. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n2r-3&=&\\phantom{-}r-3 \\\\\r\n-r+3&&-r+3 \\\\\r\n\\hline\r\nr&=&0\r\n\\end{array}[\/latex]<\/li>\r\n \t
  9. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n6^{-3x}&=&6^2 \\\\\r\n\\therefore -3x&=&2 \\\\\r\nx&=&-\\dfrac{2}{3}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  10. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n2n&=&-n \\\\\r\n+n&&+n \\\\\r\n\\hline\r\n3n&=&0 \\\\ \\\\\r\nn&=&0\r\n\\end{array}[\/latex]<\/li>\r\n \t
  11. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(2^6)^b&=&2^5 \\\\\r\n6b&=&5 \\\\ \\\\\r\nb&=&\\dfrac{5}{6}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  12. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(6^3)^{-3v}&=&(6^2)^{3v} \\\\\r\n6^{-9v}&=&6^{6v} \\\\\r\n-9v&=&6v \\\\\r\n+9v&&+9v \\\\\r\n\\hline\r\n0&=&15v \\\\ \\\\\r\nv&=&0\r\n\\end{array}[\/latex]<\/li>\r\n \t
  13. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(4^{-1})^x&=&4^2 \\\\\r\n4^{-x}&=&4^2 \\\\\r\n\\therefore -x&=&2 \\\\\r\nx&=&-2\r\n\\end{array}[\/latex]<\/li>\r\n \t
  14. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(3^3)^{-2n-1}&=&3^2 \\\\\r\n3^{-6n-3}&=&3^2 \\\\\r\n-6n-3&=&2 \\\\\r\n+3&=&+3 \\\\\r\n\\hline\r\n-6n&=&5 \\\\ \\\\\r\nn&=&-\\dfrac{5}{6}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  15. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n\\therefore 3a&=&3 \\\\\r\na&=&1\r\n\\end{array}[\/latex]<\/li>\r\n \t
  16. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n4^{-3v}&=&4^3 \\\\\r\n\\therefore -3v&=&3 \\\\\r\nv&=&-1\r\n\\end{array}[\/latex]<\/li>\r\n \t
  17. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(6^2)^{3x}&=&\\phantom{-}(6^3)^{2x+1} \\\\\r\n6^{6x}&=&\\phantom{-}6^{6x+3} \\\\\r\n\\therefore 6x&=&\\phantom{-}6x+3 \\\\\r\n-6x&&-6x \\\\\r\n\\hline\r\n0&=&3 \\Rightarrow \\text{no solution}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  18. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(4^3)^{x+2}&=&4^2 \\\\\r\n4^{3x+6}&=&4^2 \\\\\r\n\\therefore 3x+6 & =&\\phantom{-}2 \\\\\r\n-6&&-6 \\\\\r\n\\hline\r\n3x&=&-4 \\\\ \\\\\r\nx&=&-\\dfrac{4}{3}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  19. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(3^2)^{2n+3}&=&3^5 \\\\\r\n3^{4n+6}&=&3^5 \\\\\r\n\\therefore 4n+6&=&\\phantom{-}5 \\\\\r\n-6&&-6 \\\\\r\n\\hline\r\n4n&=&-1 \\\\ \\\\\r\nn&=&-\\dfrac{1}{4}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  20. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(4^2)^{2k}&=&4^{-3} \\\\\r\n4^{4k}&=&4^{-3} \\\\\r\n\\therefore 4k&=&-3 \\\\ \\\\\r\nk&=&-\\dfrac{3}{4}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  21. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n3x-2&=&\\phantom{-}3x+1 \\\\\r\n-3x+2&&-3x+2 \\\\\r\n\\hline\r\n0&=&\\phantom{-}3\\Rightarrow \\text{no solution}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  22. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(2^5)^p&=&(3^2)^{-3p} \\\\\r\n\\therefore 5p&=&-6p \\\\\r\n+6p&&+6p \\\\\r\n\\hline\r\n11p&=&0 \\\\ \\\\\r\np&=&0\r\n\\end{array}[\/latex]<\/li>\r\n \t
  23. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n-2x&=&3 \\\\\r\nx&=&-\\dfrac{3}{2}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  24. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n2n&=&2-3n \\\\\r\n+3n&&\\phantom{2}+3n \\\\\r\n\\hline\r\n5n&=&2 \\\\ \\\\\r\nn&=&\\dfrac{2}{5}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  25. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\nm+2&=&-m \\\\\r\n+m-2&=&+m-2 \\\\\r\n\\hline\r\n2m&=&-2 \\\\ \\\\\r\nm&=&-1\r\n\\end{array}[\/latex]<\/li>\r\n \t
  26. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(5^4)^{2x}&=&5^2 \\\\\r\n5^{8x}&=&5^2 \\\\\r\n\\therefore 8x&=&2 \\\\ \\\\\r\nx&=&\\dfrac{1}{4}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  27. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(6^{-2})^{b-1}&=&6^3 \\\\\r\n6^{-2b+2}&=&6^3 \\\\\r\n\\therefore -2b+2&=&\\phantom{-}3 \\\\\r\n-2&& -2 \\\\\r\n\\hline\r\n-2b&=&\\phantom{-}1 \\\\ \\\\\r\nb&=&-\\dfrac{1}{2}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  28. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(6^3)^{2n}&=&6^2 \\\\\r\n6^{6n}&=&6^2 \\\\\r\n\\therefore 6n&=&2 \\\\ \\\\\r\nn&=&\\dfrac{1}{3}\r\n\\end{array}[\/latex]<\/li>\r\n \t
  29. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n2-2x&=&\\phantom{-}2 \\\\\r\n-2\\phantom{-2x}&=&-2 \\\\\r\n\\hline\r\n-2x&=&0 \\\\ \\\\\r\nx&=&0\r\n\\end{array}[\/latex]<\/li>\r\n \t
  30. [latex]\\phantom{a}[\/latex]\r\n[latex]\\begin{array}[t]{rrl}\r\n(2^{-2})^{3v-2}&=&\\phantom{-}(2^6)^{1-v} \\\\\r\n2^{-6v+4}&=&\\phantom{-}2^{6-6v} \\\\\r\n\\therefore -6v+4&=&\\phantom{-}6-6v \\\\\r\n+6v-4&& -4+6v \\\\\r\n\\hline\r\n0&=&\\phantom{-}2\\Rightarrow \\text{No solution}\r\n\\end{array}[\/latex]<\/li>\r\n<\/ol>","rendered":"
      \n
    1. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrrrrrrr} &1&-&2n&=&1&-&3n \\\\ -&1&+&3n&&-1&+&3n \\\\ \\hline &&&n&=&0&& \\end{array}[\/latex]<\/li>\n
    2. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} 4^{2x}&=&4^{-2} \\\\ \\\\ \\dfrac{2x}{2}&=&\\dfrac{-2}{2} \\\\ \\\\ x&=&-1 \\end{array}[\/latex]<\/li>\n
    3. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} 4^{2a}&=&4^0 \\\\ 2a&=&0 \\\\ a&=&0 \\end{array}[\/latex]<\/li>\n
    4. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (4^2)^{-3p}&=&(4^3)^{3p} \\\\ 4^{-6p}&=&4^{9p} \\\\ -6p&=&\\phantom{+}9p \\\\ +6p&&+6p \\\\ \\hline 0&=&15p \\\\ \\\\ p&=&0 \\end{array}[\/latex]<\/li>\n
    5. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (5^{-2})^{-k}&=&(5^3)^{-2k-2} \\\\ 5^{2k}&=&5^{-6k-6} \\\\ 2k&=&-6k-6 \\\\ +6k&&+6k \\\\ \\hline 8k&=&-6 \\\\ \\\\ k&=&-\\dfrac{6}{8}\\Rightarrow -\\dfrac{3}{4} \\end{array}[\/latex]<\/li>\n
    6. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (5)^{4(-n-2)}&=&(5)^{-3} \\\\ 5^{-4n-8}&=&5^{-3} \\\\ -4n-8&=&-3 \\\\ 4n+8&=&\\phantom{-}3 \\\\ -8&&-8 \\\\ \\hline 4n&=&-5 \\\\ \\\\ n&=&-\\dfrac{5}{4} \\end{array}[\/latex]<\/li>\n
    7. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} 6^{2m+1}&=&6^{-2} \\\\ 2m+1&=&-2 \\\\ -1&&-1 \\\\ \\hline 2m&=&-3 \\\\ \\\\ m&=&-\\dfrac{3}{2} \\end{array}[\/latex]<\/li>\n
    8. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} 2r-3&=&\\phantom{-}r-3 \\\\ -r+3&&-r+3 \\\\ \\hline r&=&0 \\end{array}[\/latex]<\/li>\n
    9. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} 6^{-3x}&=&6^2 \\\\ \\therefore -3x&=&2 \\\\ x&=&-\\dfrac{2}{3} \\end{array}[\/latex]<\/li>\n
    10. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} 2n&=&-n \\\\ +n&&+n \\\\ \\hline 3n&=&0 \\\\ \\\\ n&=&0 \\end{array}[\/latex]<\/li>\n
    11. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (2^6)^b&=&2^5 \\\\ 6b&=&5 \\\\ \\\\ b&=&\\dfrac{5}{6} \\end{array}[\/latex]<\/li>\n
    12. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (6^3)^{-3v}&=&(6^2)^{3v} \\\\ 6^{-9v}&=&6^{6v} \\\\ -9v&=&6v \\\\ +9v&&+9v \\\\ \\hline 0&=&15v \\\\ \\\\ v&=&0 \\end{array}[\/latex]<\/li>\n
    13. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (4^{-1})^x&=&4^2 \\\\ 4^{-x}&=&4^2 \\\\ \\therefore -x&=&2 \\\\ x&=&-2 \\end{array}[\/latex]<\/li>\n
    14. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (3^3)^{-2n-1}&=&3^2 \\\\ 3^{-6n-3}&=&3^2 \\\\ -6n-3&=&2 \\\\ +3&=&+3 \\\\ \\hline -6n&=&5 \\\\ \\\\ n&=&-\\dfrac{5}{6} \\end{array}[\/latex]<\/li>\n
    15. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} \\therefore 3a&=&3 \\\\ a&=&1 \\end{array}[\/latex]<\/li>\n
    16. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} 4^{-3v}&=&4^3 \\\\ \\therefore -3v&=&3 \\\\ v&=&-1 \\end{array}[\/latex]<\/li>\n
    17. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (6^2)^{3x}&=&\\phantom{-}(6^3)^{2x+1} \\\\ 6^{6x}&=&\\phantom{-}6^{6x+3} \\\\ \\therefore 6x&=&\\phantom{-}6x+3 \\\\ -6x&&-6x \\\\ \\hline 0&=&3 \\Rightarrow \\text{no solution} \\end{array}[\/latex]<\/li>\n
    18. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (4^3)^{x+2}&=&4^2 \\\\ 4^{3x+6}&=&4^2 \\\\ \\therefore 3x+6 & =&\\phantom{-}2 \\\\ -6&&-6 \\\\ \\hline 3x&=&-4 \\\\ \\\\ x&=&-\\dfrac{4}{3} \\end{array}[\/latex]<\/li>\n
    19. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (3^2)^{2n+3}&=&3^5 \\\\ 3^{4n+6}&=&3^5 \\\\ \\therefore 4n+6&=&\\phantom{-}5 \\\\ -6&&-6 \\\\ \\hline 4n&=&-1 \\\\ \\\\ n&=&-\\dfrac{1}{4} \\end{array}[\/latex]<\/li>\n
    20. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (4^2)^{2k}&=&4^{-3} \\\\ 4^{4k}&=&4^{-3} \\\\ \\therefore 4k&=&-3 \\\\ \\\\ k&=&-\\dfrac{3}{4} \\end{array}[\/latex]<\/li>\n
    21. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} 3x-2&=&\\phantom{-}3x+1 \\\\ -3x+2&&-3x+2 \\\\ \\hline 0&=&\\phantom{-}3\\Rightarrow \\text{no solution} \\end{array}[\/latex]<\/li>\n
    22. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (2^5)^p&=&(3^2)^{-3p} \\\\ \\therefore 5p&=&-6p \\\\ +6p&&+6p \\\\ \\hline 11p&=&0 \\\\ \\\\ p&=&0 \\end{array}[\/latex]<\/li>\n
    23. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} -2x&=&3 \\\\ x&=&-\\dfrac{3}{2} \\end{array}[\/latex]<\/li>\n
    24. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} 2n&=&2-3n \\\\ +3n&&\\phantom{2}+3n \\\\ \\hline 5n&=&2 \\\\ \\\\ n&=&\\dfrac{2}{5} \\end{array}[\/latex]<\/li>\n
    25. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} m+2&=&-m \\\\ +m-2&=&+m-2 \\\\ \\hline 2m&=&-2 \\\\ \\\\ m&=&-1 \\end{array}[\/latex]<\/li>\n
    26. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (5^4)^{2x}&=&5^2 \\\\ 5^{8x}&=&5^2 \\\\ \\therefore 8x&=&2 \\\\ \\\\ x&=&\\dfrac{1}{4} \\end{array}[\/latex]<\/li>\n
    27. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (6^{-2})^{b-1}&=&6^3 \\\\ 6^{-2b+2}&=&6^3 \\\\ \\therefore -2b+2&=&\\phantom{-}3 \\\\ -2&& -2 \\\\ \\hline -2b&=&\\phantom{-}1 \\\\ \\\\ b&=&-\\dfrac{1}{2} \\end{array}[\/latex]<\/li>\n
    28. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (6^3)^{2n}&=&6^2 \\\\ 6^{6n}&=&6^2 \\\\ \\therefore 6n&=&2 \\\\ \\\\ n&=&\\dfrac{1}{3} \\end{array}[\/latex]<\/li>\n
    29. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} 2-2x&=&\\phantom{-}2 \\\\ -2\\phantom{-2x}&=&-2 \\\\ \\hline -2x&=&0 \\\\ \\\\ x&=&0 \\end{array}[\/latex]<\/li>\n
    30. [latex]\\phantom{a}[\/latex]
      \n[latex]\\begin{array}[t]{rrl} (2^{-2})^{3v-2}&=&\\phantom{-}(2^6)^{1-v} \\\\ 2^{-6v+4}&=&\\phantom{-}2^{6-6v} \\\\ \\therefore -6v+4&=&\\phantom{-}6-6v \\\\ +6v-4&& -4+6v \\\\ \\hline 0&=&\\phantom{-}2\\Rightarrow \\text{No solution} \\end{array}[\/latex]<\/li>\n<\/ol>\n","protected":false},"author":90,"menu_order":110,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":"cc-by-nc-sa"},"back-matter-type":[],"contributor":[],"license":[56],"class_list":["post-2022","back-matter","type-back-matter","status-publish","hentry","license-cc-by-nc-sa"],"_links":{"self":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter\/2022","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter"}],"about":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/types\/back-matter"}],"author":[{"embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/users\/90"}],"version-history":[{"count":3,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter\/2022\/revisions"}],"predecessor-version":[{"id":2055,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter\/2022\/revisions\/2055"}],"metadata":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter\/2022\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/media?parent=2022"}],"wp:term":[{"taxonomy":"back-matter-type","embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/back-matter-type?post=2022"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/contributor?post=2022"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/license?post=2022"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}