{"id":1350,"date":"2021-12-02T19:37:36","date_gmt":"2021-12-03T00:37:36","guid":{"rendered":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/chapter\/6-3-scientific-notation-homework-assignment\/"},"modified":"2023-08-30T14:52:59","modified_gmt":"2023-08-30T18:52:59","slug":"scientific-notation-homework-assignment","status":"publish","type":"chapter","link":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/chapter\/scientific-notation-homework-assignment\/","title":{"raw":"6.3 Scientific Notation (Homework Assignment)","rendered":"6.3 Scientific Notation (Homework Assignment)"},"content":{"raw":"Scientific notation is a convenient notation system used to represent large and small numbers. Examples of these are the mass of the sun or the mass of an electron in kilograms. Simplifying basic operations such as multiplication and division with these numbers requires using exponential properties.\r\n\r\nScientific notation has two parts: a number between one and nine and a power of ten, by which that number is multiplied.\r\n<p style=\"text-align: center;\">[latex]\\text{Scientific notation: }a \\times 10^b, \\text{ where }1 \\le a \\le 9[\/latex]<\/p>\r\nThe exponent tells how many times to multiply by 10. Each multiple of 10 shifts the decimal point one place. To decide which direction to move the decimal (left or right), recall that positive exponents means there is big number (larger than ten) and negative exponents means there is a small number (less than one).\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example 6.3.1<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nConvert 14,200 to scientific notation.\r\n<p style=\"text-align: center;\">[latex]\\begin{array}{rl}\r\n1.42&amp;\\text{Put a decimal after the first nonzero number} \\\\\r\n\\times 10^4 &amp; \\text{The exponent is how many times the decimal moved} \\\\\r\n1.42 \\times 10^4&amp; \\text{Combine to yield the solution}\r\n\\end{array}[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example 6.3.2<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nConvert 0.0028 to scientific notation.\r\n<p style=\"text-align: center;\">[latex]\\begin{array}{rl}\r\n2.8&amp;\\text{Put a decimal after the first nonzero number} \\\\\r\n\\times 10^{-3}&amp;\\text{The exponent is how many times the decimal moved} \\\\\r\n2.8\\times 10^{-3}&amp;\\text{Combine to yield the solution}\r\n\\end{array}[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example 6.3.3<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nConvert 3.21 \u00d7 10<sup>5<\/sup> to standard notation.\r\n\r\nStarting with 3.21, Shift the decimal 5 places to the right, or multiply 3.21 by 10<sup>5<\/sup>.\r\n\r\n321,000 is the solution.\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example 6.3.4<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nConvert 7.4 \u00d7 10<sup>\u22123<\/sup> to standard notation\r\n\r\nShift the decimal 3 places to the left, or divide 6.4 by 10<sup>3<\/sup>.\r\n\r\n0.0074 is the solution.\r\n\r\n<\/div>\r\n<\/div>\r\nWorking with scientific notation is easier than working with other exponential notation, since the base of the exponent is always 10. This means that the exponents can be treated separately from any other numbers. For instance:\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example 6.3.5<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nMultiply (2.1 \u00d7 10<sup>\u22127<\/sup>)(3.7 \u00d7 10<sup>5<\/sup>).\r\n\r\nFirst, multiply the numbers 2.1 and 3.7, which equals 7.77.\r\n\r\nSecond, use the product rule of exponents to simplify the expression 10<sup>\u22127<\/sup> \u00d7 10<sup>5<\/sup>,\u00a0which yields 10<sup>\u22122<\/sup>.\r\n<p class=\"p17\">Combine these terms to yield the solution 7.77 \u00d7 10<sup>\u22122<\/sup>.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example 6.3.6<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n(4.96 \u00d7 10<sup>4<\/sup>) \u00f7 (3.1 \u00d7 10<sup>\u22123<\/sup>)\r\n\r\nFirst, divide: 4.96 \u00f7 3.1 = 1.6\r\n\r\nSecond, subtract the exponents (it is a division): 10<sup>4\u2212 \u22123<\/sup> = 10<sup>4 + 3<\/sup> = 10<sup>7<\/sup>\r\n\r\nCombine these to yield the solution 1.6 \u00d7 10<sup>7<\/sup>.\r\n\r\n<\/div>\r\n<\/div>\r\n<h1>Questions<\/h1>\r\nFor questions 1 to 6, write each number in scientific notation.\r\n<ol class=\"twocolumn\">\r\n \t<li>885.3<\/li>\r\n \t<li>0.000744<\/li>\r\n \t<li>0.081<\/li>\r\n \t<li>1.09<\/li>\r\n \t<li>0.039<\/li>\r\n \t<li>15,000<\/li>\r\n<\/ol>\r\nFor questions 7 to 12, write each number in standard notation.\r\n<ol class=\"twocolumn\" start=\"7\">\r\n \t<li>8.7\u00a0\u00d7 10<sup>5<\/sup><\/li>\r\n \t<li>2.56 \u00d7 10<sup>2<\/sup><\/li>\r\n \t<li>9 \u00d7 10<sup>\u22124<\/sup><\/li>\r\n \t<li>5 \u00d7 10<sup>4<\/sup><\/li>\r\n \t<li>2 \u00d7 10<sup>0<\/sup><\/li>\r\n \t<li>6 \u00d7 10<sup>\u22125<\/sup><\/li>\r\n<\/ol>\r\nFor questions 13 to 20, simplify each expression and write each answer in scientific notation.\r\n<ol class=\"twocolumn\" start=\"13\">\r\n \t<li>(7 \u00d7 10<sup>\u22121<\/sup>)(2 \u00d7 10<sup>\u22123<\/sup>)<\/li>\r\n \t<li>(2 \u00d7 10<sup>\u22126<\/sup>)(8.8 \u00d7 10<sup>\u22125<\/sup>)<\/li>\r\n \t<li>(5.26 \u00d7 10<sup>\u22125<\/sup>)(3.16 \u00d7 10<sup>\u22122<\/sup>)<\/li>\r\n \t<li>(5.1 \u00d7 10<sup>6<\/sup>)(9.84 \u00d7 10<sup>\u22121<\/sup>)<\/li>\r\n \t<li>[latex]\\dfrac{(2.6 \\times 10^{-2})(6 \\times 10^{-2})}{(4.9 \\times 10^1)(2.7 \\times 10^{-3})}[\/latex]<\/li>\r\n \t<li>[latex]\\dfrac{(7.4 \\times 10^4)(1.7 \\times 10^{-4})}{(7.2 \\times 10^{-1})(7.32 \\times 10^{-1})}[\/latex]<\/li>\r\n \t<li>[latex]\\dfrac{(5.33 \\times 10^{-6})(9.62 \\times 10^{-2})}{(5.5 \\times 10^{-5})^2}[\/latex]<\/li>\r\n \t<li>[latex]\\dfrac{(3.2 \\times 10^{-3})(5.02 \\times 10^0)}{(9.6 \\times 10^3)^{-4}}[\/latex]<\/li>\r\n<\/ol>\r\n<a class=\"internal\" href=\"https:\/\/opentextbc.ca\/intermediatealgebraberg\/back-matter\/answer-key-6-3\/\">Answer Key 6.3<\/a>","rendered":"<p>Scientific notation is a convenient notation system used to represent large and small numbers. Examples of these are the mass of the sun or the mass of an electron in kilograms. Simplifying basic operations such as multiplication and division with these numbers requires using exponential properties.<\/p>\n<p>Scientific notation has two parts: a number between one and nine and a power of ten, by which that number is multiplied.<\/p>\n<p style=\"text-align: center;\">[latex]\\text{Scientific notation: }a \\times 10^b, \\text{ where }1 \\le a \\le 9[\/latex]<\/p>\n<p>The exponent tells how many times to multiply by 10. Each multiple of 10 shifts the decimal point one place. To decide which direction to move the decimal (left or right), recall that positive exponents means there is big number (larger than ten) and negative exponents means there is a small number (less than one).<\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example 6.3.1<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Convert 14,200 to scientific notation.<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{array}{rl}  1.42&\\text{Put a decimal after the first nonzero number} \\\\  \\times 10^4 & \\text{The exponent is how many times the decimal moved} \\\\  1.42 \\times 10^4& \\text{Combine to yield the solution}  \\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example 6.3.2<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Convert 0.0028 to scientific notation.<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{array}{rl}  2.8&\\text{Put a decimal after the first nonzero number} \\\\  \\times 10^{-3}&\\text{The exponent is how many times the decimal moved} \\\\  2.8\\times 10^{-3}&\\text{Combine to yield the solution}  \\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example 6.3.3<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Convert 3.21 \u00d7 10<sup>5<\/sup> to standard notation.<\/p>\n<p>Starting with 3.21, Shift the decimal 5 places to the right, or multiply 3.21 by 10<sup>5<\/sup>.<\/p>\n<p>321,000 is the solution.<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example 6.3.4<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Convert 7.4 \u00d7 10<sup>\u22123<\/sup> to standard notation<\/p>\n<p>Shift the decimal 3 places to the left, or divide 6.4 by 10<sup>3<\/sup>.<\/p>\n<p>0.0074 is the solution.<\/p>\n<\/div>\n<\/div>\n<p>Working with scientific notation is easier than working with other exponential notation, since the base of the exponent is always 10. This means that the exponents can be treated separately from any other numbers. For instance:<\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example 6.3.5<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Multiply (2.1 \u00d7 10<sup>\u22127<\/sup>)(3.7 \u00d7 10<sup>5<\/sup>).<\/p>\n<p>First, multiply the numbers 2.1 and 3.7, which equals 7.77.<\/p>\n<p>Second, use the product rule of exponents to simplify the expression 10<sup>\u22127<\/sup> \u00d7 10<sup>5<\/sup>,\u00a0which yields 10<sup>\u22122<\/sup>.<\/p>\n<p class=\"p17\">Combine these terms to yield the solution 7.77 \u00d7 10<sup>\u22122<\/sup>.<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example 6.3.6<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>(4.96 \u00d7 10<sup>4<\/sup>) \u00f7 (3.1 \u00d7 10<sup>\u22123<\/sup>)<\/p>\n<p>First, divide: 4.96 \u00f7 3.1 = 1.6<\/p>\n<p>Second, subtract the exponents (it is a division): 10<sup>4\u2212 \u22123<\/sup> = 10<sup>4 + 3<\/sup> = 10<sup>7<\/sup><\/p>\n<p>Combine these to yield the solution 1.6 \u00d7 10<sup>7<\/sup>.<\/p>\n<\/div>\n<\/div>\n<h1>Questions<\/h1>\n<p>For questions 1 to 6, write each number in scientific notation.<\/p>\n<ol class=\"twocolumn\">\n<li>885.3<\/li>\n<li>0.000744<\/li>\n<li>0.081<\/li>\n<li>1.09<\/li>\n<li>0.039<\/li>\n<li>15,000<\/li>\n<\/ol>\n<p>For questions 7 to 12, write each number in standard notation.<\/p>\n<ol class=\"twocolumn\" start=\"7\">\n<li>8.7\u00a0\u00d7 10<sup>5<\/sup><\/li>\n<li>2.56 \u00d7 10<sup>2<\/sup><\/li>\n<li>9 \u00d7 10<sup>\u22124<\/sup><\/li>\n<li>5 \u00d7 10<sup>4<\/sup><\/li>\n<li>2 \u00d7 10<sup>0<\/sup><\/li>\n<li>6 \u00d7 10<sup>\u22125<\/sup><\/li>\n<\/ol>\n<p>For questions 13 to 20, simplify each expression and write each answer in scientific notation.<\/p>\n<ol class=\"twocolumn\" start=\"13\">\n<li>(7 \u00d7 10<sup>\u22121<\/sup>)(2 \u00d7 10<sup>\u22123<\/sup>)<\/li>\n<li>(2 \u00d7 10<sup>\u22126<\/sup>)(8.8 \u00d7 10<sup>\u22125<\/sup>)<\/li>\n<li>(5.26 \u00d7 10<sup>\u22125<\/sup>)(3.16 \u00d7 10<sup>\u22122<\/sup>)<\/li>\n<li>(5.1 \u00d7 10<sup>6<\/sup>)(9.84 \u00d7 10<sup>\u22121<\/sup>)<\/li>\n<li>[latex]\\dfrac{(2.6 \\times 10^{-2})(6 \\times 10^{-2})}{(4.9 \\times 10^1)(2.7 \\times 10^{-3})}[\/latex]<\/li>\n<li>[latex]\\dfrac{(7.4 \\times 10^4)(1.7 \\times 10^{-4})}{(7.2 \\times 10^{-1})(7.32 \\times 10^{-1})}[\/latex]<\/li>\n<li>[latex]\\dfrac{(5.33 \\times 10^{-6})(9.62 \\times 10^{-2})}{(5.5 \\times 10^{-5})^2}[\/latex]<\/li>\n<li>[latex]\\dfrac{(3.2 \\times 10^{-3})(5.02 \\times 10^0)}{(9.6 \\times 10^3)^{-4}}[\/latex]<\/li>\n<\/ol>\n<p><a class=\"internal\" href=\"https:\/\/opentextbc.ca\/intermediatealgebraberg\/back-matter\/answer-key-6-3\/\">Answer Key 6.3<\/a><\/p>\n","protected":false},"author":90,"menu_order":3,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":"cc-by-nc-sa"},"chapter-type":[],"contributor":[],"license":[56],"class_list":["post-1350","chapter","type-chapter","status-publish","hentry","license-cc-by-nc-sa"],"part":1344,"_links":{"self":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/chapters\/1350","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/users\/90"}],"version-history":[{"count":3,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/chapters\/1350\/revisions"}],"predecessor-version":[{"id":2112,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/chapters\/1350\/revisions\/2112"}],"part":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/parts\/1344"}],"metadata":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/chapters\/1350\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/media?parent=1350"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/pressbooks\/v2\/chapter-type?post=1350"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/contributor?post=1350"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/opentextbc.ca\/intermediatealgebraberg\/wp-json\/wp\/v2\/license?post=1350"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}