{"id":7304,"date":"2021-06-08T21:55:36","date_gmt":"2021-06-08T21:55:36","guid":{"rendered":"https:\/\/opentextbc.ca\/introductorychemistry\/chapter\/end-of-chapter-2-material\/"},"modified":"2021-09-21T22:41:29","modified_gmt":"2021-09-21T22:41:29","slug":"end-of-chapter-2-material","status":"publish","type":"chapter","link":"https:\/\/opentextbc.ca\/introductorychemistry\/chapter\/end-of-chapter-2-material\/","title":{"raw":"End-of-Chapter Material","rendered":"End-of-Chapter Material"},"content":{"raw":"[latexpage]\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Additional Exercises<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n<ol>\r\n \t<li>Evaluate 0.00000000552 \u00d7 0.0000000006188 and express the answer in scientific notation. You may have to rewrite the original numbers in scientific notation first.<\/li>\r\n \t<li>Evaluate 333,999,500,000 \u00f7 0.00000000003396 and express the answer in scientific notation. You may need to rewrite the original numbers in scientific notation first.<\/li>\r\n \t<li>Express the number 6.022 \u00d7 10<sup>23<\/sup> in standard notation.<\/li>\r\n \t<li>Express the number 6.626 \u00d7 10<sup>\u221234<\/sup> in standard notation.<\/li>\r\n \t<li>When powers of 10 are multiplied together, the powers are added together. For example,\r\n10<sup>2<\/sup> \u00d7 10<sup>3<\/sup> = 10<sup>2+3<\/sup> = 10<sup>5<\/sup>. With this in mind, can you evaluate (4.506 \u00d7 10<sup>4<\/sup>) \u00d7 (1.003 \u00d7 10<sup>2<\/sup>) without entering scientific notation into your calculator?<\/li>\r\n \t<li>When powers of 10 are divided into each other, the bottom exponent is subtracted from the top exponent. For example, 10<sup>5<\/sup> \u00f7 10<sup>3<\/sup> = 10<sup>5\u22123<\/sup> = 10<sup>2<\/sup>. With this in mind, can you evaluate\r\n(8.552 \u00d7 10<sup>6<\/sup>) \u00f7 (3.129 \u00d7 10<sup>3<\/sup>) without entering scientific notation into your calculator?<\/li>\r\n \t<li>Consider the quantity two dozen eggs. Is the number in this quantity \u201ctwo\u201d or \u201ctwo dozen\u201d? Justify your choice.<\/li>\r\n \t<li>Consider the quantity two dozen eggs. Is the unit in this quantity \u201ceggs\u201d or \u201cdozen eggs\u201d? Justify your choice.<\/li>\r\n \t<li>Fill in the blank: 1 km = ______________ \u03bcm.<\/li>\r\n \t<li>Fill in the blank: 1 Ms = ______________ ns.<\/li>\r\n \t<li>Fill in the blank: 1 cL = ______________ ML.<\/li>\r\n \t<li>Fill in the blank: 1 mg = ______________ kg.<\/li>\r\n \t<li>Express 67.3 km\/h in metres\/second.<\/li>\r\n \t<li>Express 0.00444 m\/s in kilometres\/hour.<\/li>\r\n \t<li>Using the idea that 1.602 km = 1.000 mi, convert a speed of 60.0 mi\/h into kilometres\/hour.<\/li>\r\n \t<li>Using the idea that 1.602 km = 1.000 mi, convert a speed of 60.0 km\/h into miles\/hour.<\/li>\r\n \t<li>Convert 52.09 km\/h into metres\/second.<\/li>\r\n \t<li>Convert 2.155 m\/s into kilometres\/hour.<\/li>\r\n \t<li>Use the formulas for converting degrees Fahrenheit into degrees Celsius to determine the relative size of the Fahrenheit degree over the Celsius degree.<\/li>\r\n \t<li>Use the formulas for converting degrees Celsius into kelvins to determine the relative size of the Celsius degree over kelvins.<\/li>\r\n \t<li>What is the mass of 12.67 L of mercury?<\/li>\r\n \t<li>What is the mass of 0.663 m<sup>3<\/sup> of air?<\/li>\r\n \t<li>What is the volume of 2.884 kg of gold?<\/li>\r\n \t<li>What is the volume of 40.99 kg of cork? Assume a density of 0.22 g\/cm<sup>3<\/sup>.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Answers<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n<ol>\r\n \t<li>3.42 \u00d7 10<sup>\u221218<\/sup><\/li>\r\n<\/ol>\r\n<ol start=\"3\">\r\n \t<li>602,200,000,000,000,000,000,000<\/li>\r\n<\/ol>\r\n<ol start=\"5\">\r\n \t<li>4.520 \u00d7 10<sup>6<\/sup><\/li>\r\n<\/ol>\r\n<ol start=\"7\">\r\n \t<li>The quantity is two; dozen is the unit.<\/li>\r\n<\/ol>\r\n<ol start=\"9\">\r\n \t<li>1,000,000,000<\/li>\r\n<\/ol>\r\n<ol start=\"11\">\r\n \t<li>[latex]\\dfrac{1}{100,000,000}[\/latex]<\/li>\r\n<\/ol>\r\n<ol start=\"13\">\r\n \t<li>18.7 m\/s<\/li>\r\n<\/ol>\r\n<ol start=\"15\">\r\n \t<li>96.1 km\/h<\/li>\r\n<\/ol>\r\n<ol start=\"17\">\r\n \t<li>14.47 m\/s<\/li>\r\n<\/ol>\r\n<ol start=\"19\">\r\n \t<li>One Fahrenheit degree is nine-fifths the size of a Celsius degree.<\/li>\r\n<\/ol>\r\n<ol start=\"21\">\r\n \t<li>1.72 \u00d7 10<sup>5<\/sup> g<\/li>\r\n<\/ol>\r\n<ol start=\"23\">\r\n \t<li>149 mL<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>","rendered":"<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Additional Exercises<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<ol>\n<li>Evaluate 0.00000000552 \u00d7 0.0000000006188 and express the answer in scientific notation. You may have to rewrite the original numbers in scientific notation first.<\/li>\n<li>Evaluate 333,999,500,000 \u00f7 0.00000000003396 and express the answer in scientific notation. You may need to rewrite the original numbers in scientific notation first.<\/li>\n<li>Express the number 6.022 \u00d7 10<sup>23<\/sup> in standard notation.<\/li>\n<li>Express the number 6.626 \u00d7 10<sup>\u221234<\/sup> in standard notation.<\/li>\n<li>When powers of 10 are multiplied together, the powers are added together. For example,<br \/>\n10<sup>2<\/sup> \u00d7 10<sup>3<\/sup> = 10<sup>2+3<\/sup> = 10<sup>5<\/sup>. With this in mind, can you evaluate (4.506 \u00d7 10<sup>4<\/sup>) \u00d7 (1.003 \u00d7 10<sup>2<\/sup>) without entering scientific notation into your calculator?<\/li>\n<li>When powers of 10 are divided into each other, the bottom exponent is subtracted from the top exponent. For example, 10<sup>5<\/sup> \u00f7 10<sup>3<\/sup> = 10<sup>5\u22123<\/sup> = 10<sup>2<\/sup>. With this in mind, can you evaluate<br \/>\n(8.552 \u00d7 10<sup>6<\/sup>) \u00f7 (3.129 \u00d7 10<sup>3<\/sup>) without entering scientific notation into your calculator?<\/li>\n<li>Consider the quantity two dozen eggs. Is the number in this quantity \u201ctwo\u201d or \u201ctwo dozen\u201d? Justify your choice.<\/li>\n<li>Consider the quantity two dozen eggs. Is the unit in this quantity \u201ceggs\u201d or \u201cdozen eggs\u201d? Justify your choice.<\/li>\n<li>Fill in the blank: 1 km = ______________ \u03bcm.<\/li>\n<li>Fill in the blank: 1 Ms = ______________ ns.<\/li>\n<li>Fill in the blank: 1 cL = ______________ ML.<\/li>\n<li>Fill in the blank: 1 mg = ______________ kg.<\/li>\n<li>Express 67.3 km\/h in metres\/second.<\/li>\n<li>Express 0.00444 m\/s in kilometres\/hour.<\/li>\n<li>Using the idea that 1.602 km = 1.000 mi, convert a speed of 60.0 mi\/h into kilometres\/hour.<\/li>\n<li>Using the idea that 1.602 km = 1.000 mi, convert a speed of 60.0 km\/h into miles\/hour.<\/li>\n<li>Convert 52.09 km\/h into metres\/second.<\/li>\n<li>Convert 2.155 m\/s into kilometres\/hour.<\/li>\n<li>Use the formulas for converting degrees Fahrenheit into degrees Celsius to determine the relative size of the Fahrenheit degree over the Celsius degree.<\/li>\n<li>Use the formulas for converting degrees Celsius into kelvins to determine the relative size of the Celsius degree over kelvins.<\/li>\n<li>What is the mass of 12.67 L of mercury?<\/li>\n<li>What is the mass of 0.663 m<sup>3<\/sup> of air?<\/li>\n<li>What is the volume of 2.884 kg of gold?<\/li>\n<li>What is the volume of 40.99 kg of cork? Assume a density of 0.22 g\/cm<sup>3<\/sup>.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Answers<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<ol>\n<li>3.42 \u00d7 10<sup>\u221218<\/sup><\/li>\n<\/ol>\n<ol start=\"3\">\n<li>602,200,000,000,000,000,000,000<\/li>\n<\/ol>\n<ol start=\"5\">\n<li>4.520 \u00d7 10<sup>6<\/sup><\/li>\n<\/ol>\n<ol start=\"7\">\n<li>The quantity is two; dozen is the unit.<\/li>\n<\/ol>\n<ol start=\"9\">\n<li>1,000,000,000<\/li>\n<\/ol>\n<ol start=\"11\">\n<li><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/ql-cache\/quicklatex.com-f5e49a0fbc0ef7b9b8a66eeed09073b4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#92;&#100;&#102;&#114;&#97;&#99;&#123;&#49;&#125;&#123;&#49;&#48;&#48;&#44;&#48;&#48;&#48;&#44;&#48;&#48;&#48;&#125;\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"96\" style=\"vertical-align: -16px;\" \/><\/li>\n<\/ol>\n<ol start=\"13\">\n<li>18.7 m\/s<\/li>\n<\/ol>\n<ol start=\"15\">\n<li>96.1 km\/h<\/li>\n<\/ol>\n<ol start=\"17\">\n<li>14.47 m\/s<\/li>\n<\/ol>\n<ol start=\"19\">\n<li>One Fahrenheit degree is nine-fifths the size of a Celsius degree.<\/li>\n<\/ol>\n<ol start=\"21\">\n<li>1.72 \u00d7 10<sup>5<\/sup> g<\/li>\n<\/ol>\n<ol start=\"23\">\n<li>149 mL<\/li>\n<\/ol>\n<\/div>\n<\/div>\n","protected":false},"author":90,"menu_order":6,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-7304","chapter","type-chapter","status-publish","hentry"],"part":7281,"_links":{"self":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7304","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/users\/90"}],"version-history":[{"count":2,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7304\/revisions"}],"predecessor-version":[{"id":8290,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7304\/revisions\/8290"}],"part":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/parts\/7281"}],"metadata":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7304\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/media?parent=7304"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=7304"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/contributor?post=7304"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/license?post=7304"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}