{"id":7610,"date":"2021-06-08T21:57:00","date_gmt":"2021-06-08T21:57:00","guid":{"rendered":"https:\/\/opentextbc.ca\/introductorychemistry\/chapter\/some-definitions\/"},"modified":"2021-10-06T20:21:23","modified_gmt":"2021-10-06T20:21:23","slug":"some-definitions","status":"publish","type":"chapter","link":"https:\/\/opentextbc.ca\/introductorychemistry\/chapter\/some-definitions\/","title":{"raw":"Some Definitions","rendered":"Some Definitions"},"content":{"raw":"<div class=\"textbox textbox--learning-objectives\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Learning Objectives<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n<ol>\r\n \t<li>Learn some terminology involving solutions.<\/li>\r\n \t<li>Recognize which terminology is qualitative and which terminology is quantitative.<\/li>\r\n \t<li>Explain why certain substances dissolve in other substances.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\nThe major component of a solution is called the <strong>solvent<\/strong>. The minor component of a solution is called the <strong>solute<\/strong>. By major and minor we mean whichever component has the greater presence by mass or by moles. Sometimes this becomes confusing, especially with substances with very different molar masses. However, here we will confine the discussion to solutions for which the major component and the minor component are obvious.\r\n\r\nSolutions exist for every possible phase of the solute and the solvent. Salt water, for example, is a solution of solid NaCl in liquid water; soda water is a solution of gaseous CO<sub>2<\/sub> in liquid water, while air is a solution of a gaseous solute (O<sub>2<\/sub>) in a gaseous solvent (N<sub>2<\/sub>). In all cases, however, the overall phase of the solution is the same phase as the solvent.\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example 11.19<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nA solution is made by dissolving 1.00 g of sucrose (C<sub>12<\/sub>H<sub>22<\/sub>O<sub>11<\/sub>) in 100.0 g of liquid water. Identify the solvent and solute in the resulting solution.\r\n\r\n<em>Solution<\/em>\r\nEither by mass or by moles, the obvious minor component is sucrose, so it is the solute. Water \u2014 the majority component \u2014 is the solvent. The fact that the resulting solution is the same phase as water also suggests that water is the solvent.\r\n\r\n<em>Test Yourself<\/em>\r\n\r\nA solution is made by dissolving 3.33 g of HCl(g) in 40.0 g of liquid methyl alcohol (CH<sub>3<\/sub>OH). Identify the solvent and solute in the resulting solution.\r\n\r\n<em>Answer<\/em>\r\nThe solute is HCl(g); the solvent is CH<sub>3<\/sub>OH.\r\n\r\n<\/div>\r\n<\/div>\r\nOne important concept of solutions is in defining how much solute is dissolved in a given amount of solvent. This concept is called <strong>concentration<\/strong>. Various words are used to describe the relative amounts of solute. <strong>Dilute<\/strong>\u00a0describes a solution that has very little solute, while <strong>concentrated<\/strong> describes a solution that has a lot of solute. One problem is that these terms are qualitative; they describe more or less but not exactly how much.\r\n\r\nIn most cases, only a certain maximum amount of solute can be dissolved in a given amount of solvent. This maximum amount is called the <strong>solubility<\/strong>\u00a0of the solute. It is usually expressed in terms of the amount of solute that can dissolve in 100 g of the solvent at a given temperature. Table 11.5 \"Solubilities of Some Ionic Compounds\" lists the solubilities of some simple ionic compounds. These solubilities vary widely: NaCl can dissolve up to 31.6 g per 100 g of H<sub>2<\/sub>O, while AgCl can dissolve only 0.00019 g per 100 g of H<sub>2<\/sub>O.\r\n<table class=\"aligncenter\" style=\"border-spacing: 0px;\" cellspacing=\"0px\" cellpadding=\"0\"><caption>Table 11.5 Solubilities of Some Ionic Compounds<\/caption>\r\n<thead>\r\n<tr>\r\n<th>Solute<\/th>\r\n<th align=\"right\">Solubility (g per 100 g of H<sub class=\"subscript\">2<\/sub>O at 25\u00b0C)<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>AgCl<\/td>\r\n<td align=\"right\">0.00019<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>CaCO<sub class=\"subscript\">3<\/sub><\/td>\r\n<td align=\"right\">0.0006<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>KBr<\/td>\r\n<td align=\"right\">70.7<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>NaCl<\/td>\r\n<td align=\"right\">36.1<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>NaNO<sub class=\"subscript\">3<\/sub><\/td>\r\n<td align=\"right\">94.6<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\nWhen the maximum amount of solute has been dissolved in a given amount of solvent, we say that the solution is <strong>saturated<\/strong>\u00a0with solute. When less than the maximum amount of solute is dissolved in a given amount of solute, the solution is <strong>unsaturated<\/strong>. These terms are also qualitative terms because each solute has its own solubility. A solution of 0.00019 g of AgCl per 100 g of H<sub>2<\/sub>O may be saturated, but with so little solute dissolved, it is also rather dilute. A solution of 36.1 g of NaCl in 100 g of H<sub>2<\/sub>O is also saturated but rather concentrated. Ideally, we need more precise ways of specifying the amount of solute in a solution. We introduced such ways in the section <a class=\"internal\" href=\"\/introductorychemistry\/chapter\/quantitative-units-of-concentration\/\">\"Quantitative Units of Concentration\"<\/a>.\r\n\r\nIn some circumstances, it is possible to dissolve more than the maximum amount of a solute in a solution. Usually, this happens by heating the solvent, dissolving more solute than would normally dissolve at regular temperatures, and letting the solution cool down slowly and carefully. Such solutions are called <strong>supersaturated<\/strong>\u00a0solutions and are not stable; given an opportunity (such as dropping a crystal of solute in the solution), the excess solute will precipitate from the solution.\r\n\r\nIt should be obvious that some solutes dissolve in certain solvents but not others. NaCl, for example, dissolves in water but not in vegetable oil. Beeswax dissolves in liquid hexane but not water. What is it that makes a solute soluble in some solvents but not others?\r\n\r\nThe answer is intermolecular interactions. The intermolecular interactions include London dispersion forces, dipole-dipole interactions, and hydrogen bonding (as described in <a class=\"internal\" href=\"\/introductorychemistry\/part\/chapter-10-solids-and-liquids\/\">Chapter 10 \"Solids and Liquids\"<\/a>). From experimental studies, it has been determined that if molecules of a solute experience the same intermolecular forces that the solvent does, the solute will likely dissolve in that solvent. So, NaCl \u2014 a very polar substance because it is composed of ions \u2014 dissolves in water, which is very polar, but not in oil, which is generally nonpolar. Nonpolar wax dissolves in nonpolar hexane but not in polar water. This concept leads to the general rule that \u201clike dissolves like\u201d for predicting whether a solute is soluble in a given solvent. However, this is a general rule, not an absolute statement, so it must be applied with care.\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example 11.20<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nWould I<sub>2<\/sub> be more soluble in CCl<sub>4<\/sub> or H<sub>2<\/sub>O? Explain your answer.\r\n\r\n<em>Solution<\/em>\r\nI<sub>2<\/sub> is nonpolar. Of the two solvents, CCl<sub>4<\/sub> is nonpolar and H<sub>2<\/sub>O is polar, so I<sub>2<\/sub> would be expected to be more soluble in CCl<sub>4<\/sub>.\r\n\r\n<em>Test Yourself<\/em>\r\nWould C<sub>3<\/sub>H<sub>7<\/sub>OH be more soluble in CCl<sub>4<\/sub> or H<sub>2<\/sub>O? Explain your answer.\r\n\r\n<em>Answer<\/em>\r\nH<sub>2<\/sub>O, because both experience hydrogen bonding.\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--key-takeaways\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Key Takeaways<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n<ul>\r\n \t<li>Solutions are composed of a solvent (major component) and a solute (minor component).<\/li>\r\n \t<li>Concentration is the expression of the amount of solute in a given amount of solvent and can be described by several qualitative terms.<\/li>\r\n \t<li>Solubility is a specific amount of solute that can dissolve in a given amount of solvent.<\/li>\r\n \t<li>\u201cLike dissolves like\u201d is a useful rule for deciding if a solute will be soluble in a solvent.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Exercises<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n<h1>Questions<\/h1>\r\n<ol>\r\n \t<li>Define <em>solute<\/em> and <em>solvent<\/em>.<\/li>\r\n \t<li>Define <em>saturated<\/em>, <em>unsaturated<\/em>, and <em>supersaturated<\/em>.<\/li>\r\n \t<li>A solution is prepared by combining 2.09 g of CO<sub>2<\/sub> and 35.5 g of H<sub>2<\/sub>O. Identify the solute and solvent.<\/li>\r\n \t<li>A solution is prepared by combining 10.3 g of Hg(\u2113) and 45.0 g of Ag(s). Identify the solute and solvent.<\/li>\r\n \t<li>Use Table 11.5 \u201cSolubilities of Some Ionic Compounds\u201d to decide if a solution containing 45.0 g of NaCl per 100 g of H<sub>2<\/sub>O is unsaturated, saturated, or supersaturated.<\/li>\r\n \t<li>Use Table 11.5 to decide if a solution containing 0.000092 g of AgCl per 100 g of H<sub>2<\/sub>O is unsaturated, saturated, or supersaturated.<\/li>\r\n \t<li>Would the solution in Exercise 5 be described as dilute or concentrated? Explain your answer.<\/li>\r\n \t<li>Would the solution in Exercise 6 be described as dilute or concentrated? Explain your answer.<\/li>\r\n \t<li>Identify a solute from Table 11.5 whose saturated solution can be described as dilute.<\/li>\r\n \t<li>Identify a solute from Table 11.5 whose saturated solution can be described as concentrated.<\/li>\r\n \t<li>Which solvent is Br<sub>2<\/sub> more likely soluble in \u2014 CH<sub>3<\/sub>OH or C<sub>6<\/sub>H<sub>6<\/sub>?<\/li>\r\n \t<li>Which solvent is NaOH more likely soluble in \u2014 CH<sub>3<\/sub>OH or C<sub>6<\/sub>H<sub>6<\/sub>?<\/li>\r\n \t<li>Compounds with the formula C<sub><em>n<\/em><\/sub>H<sub><em>2n +\u00a01<\/em><\/sub>OH are soluble in H2O when <em>n<\/em> is small but not when <em>n<\/em> is large. Suggest an explanation for this phenomenon.<\/li>\r\n \t<li>Glucose has the following structure:\r\n<p style=\"text-align: center;\"><img class=\" wp-image-609 aligncenter\" src=\"https:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2021\/06\/Glucose1-1.png\" alt=\"Glucose\" width=\"321\" height=\"224\" \/><\/p>\r\n<p style=\"text-align: left;\">What parts of the molecule indicate that this substance is soluble in water?<\/p>\r\n<\/li>\r\n<\/ol>\r\n<h1>Answers<\/h1>\r\n<ol>\r\n \t<li>The solvent is the majority component of a solution, whereas the solute is the minority component of a solution.<\/li>\r\n<\/ol>\r\n<ol start=\"3\">\r\n \t<li>solute: CO<sub>2<\/sub>; solvent: H<sub>2<\/sub>O<\/li>\r\n<\/ol>\r\n<ol start=\"5\">\r\n \t<li>supersaturated<\/li>\r\n<\/ol>\r\n<ol start=\"7\">\r\n \t<li>concentrated, because there is a lot of solute<\/li>\r\n<\/ol>\r\n<ol start=\"9\">\r\n \t<li>AgCl or CaCO<sub>3<\/sub><\/li>\r\n<\/ol>\r\n<ol start=\"11\">\r\n \t<li>C<sub>6<\/sub>H<sub>6<\/sub><\/li>\r\n<\/ol>\r\n<ol start=\"13\">\r\n \t<li>The nonpolar end dominates intermolecular forces when <em>n<\/em> is large.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>","rendered":"<div class=\"textbox textbox--learning-objectives\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Learning Objectives<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<ol>\n<li>Learn some terminology involving solutions.<\/li>\n<li>Recognize which terminology is qualitative and which terminology is quantitative.<\/li>\n<li>Explain why certain substances dissolve in other substances.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p>The major component of a solution is called the <strong>solvent<\/strong>. The minor component of a solution is called the <strong>solute<\/strong>. By major and minor we mean whichever component has the greater presence by mass or by moles. Sometimes this becomes confusing, especially with substances with very different molar masses. However, here we will confine the discussion to solutions for which the major component and the minor component are obvious.<\/p>\n<p>Solutions exist for every possible phase of the solute and the solvent. Salt water, for example, is a solution of solid NaCl in liquid water; soda water is a solution of gaseous CO<sub>2<\/sub> in liquid water, while air is a solution of a gaseous solute (O<sub>2<\/sub>) in a gaseous solvent (N<sub>2<\/sub>). In all cases, however, the overall phase of the solution is the same phase as the solvent.<\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example 11.19<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>A solution is made by dissolving 1.00 g of sucrose (C<sub>12<\/sub>H<sub>22<\/sub>O<sub>11<\/sub>) in 100.0 g of liquid water. Identify the solvent and solute in the resulting solution.<\/p>\n<p><em>Solution<\/em><br \/>\nEither by mass or by moles, the obvious minor component is sucrose, so it is the solute. Water \u2014 the majority component \u2014 is the solvent. The fact that the resulting solution is the same phase as water also suggests that water is the solvent.<\/p>\n<p><em>Test Yourself<\/em><\/p>\n<p>A solution is made by dissolving 3.33 g of HCl(g) in 40.0 g of liquid methyl alcohol (CH<sub>3<\/sub>OH). Identify the solvent and solute in the resulting solution.<\/p>\n<p><em>Answer<\/em><br \/>\nThe solute is HCl(g); the solvent is CH<sub>3<\/sub>OH.<\/p>\n<\/div>\n<\/div>\n<p>One important concept of solutions is in defining how much solute is dissolved in a given amount of solvent. This concept is called <strong>concentration<\/strong>. Various words are used to describe the relative amounts of solute. <strong>Dilute<\/strong>\u00a0describes a solution that has very little solute, while <strong>concentrated<\/strong> describes a solution that has a lot of solute. One problem is that these terms are qualitative; they describe more or less but not exactly how much.<\/p>\n<p>In most cases, only a certain maximum amount of solute can be dissolved in a given amount of solvent. This maximum amount is called the <strong>solubility<\/strong>\u00a0of the solute. It is usually expressed in terms of the amount of solute that can dissolve in 100 g of the solvent at a given temperature. Table 11.5 &#8220;Solubilities of Some Ionic Compounds&#8221; lists the solubilities of some simple ionic compounds. These solubilities vary widely: NaCl can dissolve up to 31.6 g per 100 g of H<sub>2<\/sub>O, while AgCl can dissolve only 0.00019 g per 100 g of H<sub>2<\/sub>O.<\/p>\n<table class=\"aligncenter\" style=\"border-spacing: 0px; border-spacing: 0pxpx;\" cellpadding=\"0\">\n<caption>Table 11.5 Solubilities of Some Ionic Compounds<\/caption>\n<thead>\n<tr>\n<th>Solute<\/th>\n<th align=\"right\">Solubility (g per 100 g of H<sub class=\"subscript\">2<\/sub>O at 25\u00b0C)<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>AgCl<\/td>\n<td align=\"right\">0.00019<\/td>\n<\/tr>\n<tr>\n<td>CaCO<sub class=\"subscript\">3<\/sub><\/td>\n<td align=\"right\">0.0006<\/td>\n<\/tr>\n<tr>\n<td>KBr<\/td>\n<td align=\"right\">70.7<\/td>\n<\/tr>\n<tr>\n<td>NaCl<\/td>\n<td align=\"right\">36.1<\/td>\n<\/tr>\n<tr>\n<td>NaNO<sub class=\"subscript\">3<\/sub><\/td>\n<td align=\"right\">94.6<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>When the maximum amount of solute has been dissolved in a given amount of solvent, we say that the solution is <strong>saturated<\/strong>\u00a0with solute. When less than the maximum amount of solute is dissolved in a given amount of solute, the solution is <strong>unsaturated<\/strong>. These terms are also qualitative terms because each solute has its own solubility. A solution of 0.00019 g of AgCl per 100 g of H<sub>2<\/sub>O may be saturated, but with so little solute dissolved, it is also rather dilute. A solution of 36.1 g of NaCl in 100 g of H<sub>2<\/sub>O is also saturated but rather concentrated. Ideally, we need more precise ways of specifying the amount of solute in a solution. We introduced such ways in the section <a class=\"internal\" href=\"\/introductorychemistry\/chapter\/quantitative-units-of-concentration\/\">&#8220;Quantitative Units of Concentration&#8221;<\/a>.<\/p>\n<p>In some circumstances, it is possible to dissolve more than the maximum amount of a solute in a solution. Usually, this happens by heating the solvent, dissolving more solute than would normally dissolve at regular temperatures, and letting the solution cool down slowly and carefully. Such solutions are called <strong>supersaturated<\/strong>\u00a0solutions and are not stable; given an opportunity (such as dropping a crystal of solute in the solution), the excess solute will precipitate from the solution.<\/p>\n<p>It should be obvious that some solutes dissolve in certain solvents but not others. NaCl, for example, dissolves in water but not in vegetable oil. Beeswax dissolves in liquid hexane but not water. What is it that makes a solute soluble in some solvents but not others?<\/p>\n<p>The answer is intermolecular interactions. The intermolecular interactions include London dispersion forces, dipole-dipole interactions, and hydrogen bonding (as described in <a class=\"internal\" href=\"\/introductorychemistry\/part\/chapter-10-solids-and-liquids\/\">Chapter 10 &#8220;Solids and Liquids&#8221;<\/a>). From experimental studies, it has been determined that if molecules of a solute experience the same intermolecular forces that the solvent does, the solute will likely dissolve in that solvent. So, NaCl \u2014 a very polar substance because it is composed of ions \u2014 dissolves in water, which is very polar, but not in oil, which is generally nonpolar. Nonpolar wax dissolves in nonpolar hexane but not in polar water. This concept leads to the general rule that \u201clike dissolves like\u201d for predicting whether a solute is soluble in a given solvent. However, this is a general rule, not an absolute statement, so it must be applied with care.<\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example 11.20<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Would I<sub>2<\/sub> be more soluble in CCl<sub>4<\/sub> or H<sub>2<\/sub>O? Explain your answer.<\/p>\n<p><em>Solution<\/em><br \/>\nI<sub>2<\/sub> is nonpolar. Of the two solvents, CCl<sub>4<\/sub> is nonpolar and H<sub>2<\/sub>O is polar, so I<sub>2<\/sub> would be expected to be more soluble in CCl<sub>4<\/sub>.<\/p>\n<p><em>Test Yourself<\/em><br \/>\nWould C<sub>3<\/sub>H<sub>7<\/sub>OH be more soluble in CCl<sub>4<\/sub> or H<sub>2<\/sub>O? Explain your answer.<\/p>\n<p><em>Answer<\/em><br \/>\nH<sub>2<\/sub>O, because both experience hydrogen bonding.<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--key-takeaways\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Key Takeaways<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<ul>\n<li>Solutions are composed of a solvent (major component) and a solute (minor component).<\/li>\n<li>Concentration is the expression of the amount of solute in a given amount of solvent and can be described by several qualitative terms.<\/li>\n<li>Solubility is a specific amount of solute that can dissolve in a given amount of solvent.<\/li>\n<li>\u201cLike dissolves like\u201d is a useful rule for deciding if a solute will be soluble in a solvent.<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Exercises<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<h1>Questions<\/h1>\n<ol>\n<li>Define <em>solute<\/em> and <em>solvent<\/em>.<\/li>\n<li>Define <em>saturated<\/em>, <em>unsaturated<\/em>, and <em>supersaturated<\/em>.<\/li>\n<li>A solution is prepared by combining 2.09 g of CO<sub>2<\/sub> and 35.5 g of H<sub>2<\/sub>O. Identify the solute and solvent.<\/li>\n<li>A solution is prepared by combining 10.3 g of Hg(\u2113) and 45.0 g of Ag(s). Identify the solute and solvent.<\/li>\n<li>Use Table 11.5 \u201cSolubilities of Some Ionic Compounds\u201d to decide if a solution containing 45.0 g of NaCl per 100 g of H<sub>2<\/sub>O is unsaturated, saturated, or supersaturated.<\/li>\n<li>Use Table 11.5 to decide if a solution containing 0.000092 g of AgCl per 100 g of H<sub>2<\/sub>O is unsaturated, saturated, or supersaturated.<\/li>\n<li>Would the solution in Exercise 5 be described as dilute or concentrated? Explain your answer.<\/li>\n<li>Would the solution in Exercise 6 be described as dilute or concentrated? Explain your answer.<\/li>\n<li>Identify a solute from Table 11.5 whose saturated solution can be described as dilute.<\/li>\n<li>Identify a solute from Table 11.5 whose saturated solution can be described as concentrated.<\/li>\n<li>Which solvent is Br<sub>2<\/sub> more likely soluble in \u2014 CH<sub>3<\/sub>OH or C<sub>6<\/sub>H<sub>6<\/sub>?<\/li>\n<li>Which solvent is NaOH more likely soluble in \u2014 CH<sub>3<\/sub>OH or C<sub>6<\/sub>H<sub>6<\/sub>?<\/li>\n<li>Compounds with the formula C<sub><em>n<\/em><\/sub>H<sub><em>2n +\u00a01<\/em><\/sub>OH are soluble in H2O when <em>n<\/em> is small but not when <em>n<\/em> is large. Suggest an explanation for this phenomenon.<\/li>\n<li>Glucose has the following structure:\n<p style=\"text-align: center;\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-609 aligncenter\" src=\"https:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2021\/06\/Glucose1-1.png\" alt=\"Glucose\" width=\"321\" height=\"224\" \/><\/p>\n<p style=\"text-align: left;\">What parts of the molecule indicate that this substance is soluble in water?<\/p>\n<\/li>\n<\/ol>\n<h1>Answers<\/h1>\n<ol>\n<li>The solvent is the majority component of a solution, whereas the solute is the minority component of a solution.<\/li>\n<\/ol>\n<ol start=\"3\">\n<li>solute: CO<sub>2<\/sub>; solvent: H<sub>2<\/sub>O<\/li>\n<\/ol>\n<ol start=\"5\">\n<li>supersaturated<\/li>\n<\/ol>\n<ol start=\"7\">\n<li>concentrated, because there is a lot of solute<\/li>\n<\/ol>\n<ol start=\"9\">\n<li>AgCl or CaCO<sub>3<\/sub><\/li>\n<\/ol>\n<ol start=\"11\">\n<li>C<sub>6<\/sub>H<sub>6<\/sub><\/li>\n<\/ol>\n<ol start=\"13\">\n<li>The nonpolar end dominates intermolecular forces when <em>n<\/em> is large.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n","protected":false},"author":90,"menu_order":5,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-7610","chapter","type-chapter","status-publish","hentry"],"part":7571,"_links":{"self":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7610","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/users\/90"}],"version-history":[{"count":7,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7610\/revisions"}],"predecessor-version":[{"id":8910,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7610\/revisions\/8910"}],"part":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/parts\/7571"}],"metadata":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7610\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/media?parent=7610"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=7610"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/contributor?post=7610"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/license?post=7610"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}