{"id":7689,"date":"2021-06-08T21:57:18","date_gmt":"2021-06-08T21:57:18","guid":{"rendered":"https:\/\/opentextbc.ca\/introductorychemistry\/chapter\/end-of-chapter-13-material\/"},"modified":"2021-10-07T20:16:50","modified_gmt":"2021-10-07T20:16:50","slug":"end-of-chapter-13-material","status":"publish","type":"chapter","link":"https:\/\/opentextbc.ca\/introductorychemistry\/chapter\/end-of-chapter-13-material\/","title":{"raw":"End-of-Chapter Material","rendered":"End-of-Chapter Material"},"content":{"raw":"<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Additional Exercises<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n<ol>\r\n \t<li>What is the relationship between the <em>K<\/em><sub>sp<\/sub> expressions for a chemical reaction and its reverse chemical reaction?<\/li>\r\n \t<li>What is the relationship between the <em>K<\/em><sub>w<\/sub> value for H<sub>2<\/sub>O and its reverse chemical reaction?<\/li>\r\n \t<li>For the equilibrium\r\n<p style=\"text-align: center;\">PCl<sub>3<\/sub>(g)\u00a0+\u00a0Cl<sub>2<\/sub>(g) \u21c4 PCl<sub>5<\/sub>(g)\u00a0+\u00a060\u00a0kJ<\/p>\r\nlist four stresses that serve to increase the amount of PCl<sub>5<\/sub>.<\/li>\r\n \t<li>For the equilibrium\r\n<p style=\"text-align: center;\">N<sub>2<\/sub>O<sub>4<\/sub>\u00a0+\u00a057\u00a0kJ \u21c4 2NO<sub>2<\/sub><\/p>\r\nlist four stresses that serve to increase the amount of NO<sub>2<\/sub>.<\/li>\r\n \t<li>Does a very large <em>K<\/em><sub>eq<\/sub> favour the reactants or the products? Explain your answer.<\/li>\r\n \t<li>Is the <em>K<\/em><sub>eq<\/sub> for reactions that favour reactants large or small? Explain your answer.<\/li>\r\n \t<li>Show that <em>K<\/em><sub>a<\/sub> \u00d7 <em>K<\/em><sub>b<\/sub> = <em>K<\/em><sub>w<\/sub> by determining the expressions for these two reactions and multiplying them together.\r\n<p style=\"text-align: center;\">HX(aq) \u21c4 H<sup>+<\/sup>(aq) + X<sup>\u2013<\/sup>(aq)\r\nX<sup>\u2013<\/sup>(aq)\u00a0+\u00a0H<sub>2<\/sub>O(\u2113) \u21c4 HX(aq)\u00a0+\u00a0OH<sup>\u2013<\/sup>(aq)<\/p>\r\n<\/li>\r\n \t<li>Is the conjugate base of a strong acid weak or strong? Explain your answer.<\/li>\r\n \t<li>What is the solubility in moles per litre of AgCl? Use data from <a class=\"internal\" href=\"\/introductorychemistry\/chapter\/some-special-types-of-equilibria\/#table13.2\">Table 13.2 \u201cSolubility Product Constants for Slightly Soluble Ionic Compounds\u201d<\/a>.<\/li>\r\n \t<li>What is the solubility in moles per litre of Ca(OH)<sub>2<\/sub>? Use data from <a class=\"internal\" href=\"\/introductorychemistry\/chapter\/some-special-types-of-equilibria\/#table13.2\">Table 13.2<\/a>.<\/li>\r\n \t<li>Under what conditions is <em>K<\/em><sub>eq<\/sub> = <em>K<\/em><sub>P<\/sub>?<\/li>\r\n \t<li>Under what conditions is <em>K<\/em><sub>eq<\/sub> &gt; <em>K<\/em><sub>P<\/sub> when the temperature is 298 K?<\/li>\r\n \t<li>What is the pH of a saturated solution of Mg(OH)<sub>2<\/sub>? Use data from <a class=\"internal\" href=\"\/introductorychemistry\/chapter\/some-special-types-of-equilibria\/#table13.2\">Table 13.2<\/a>.<\/li>\r\n \t<li>What are the pH and the pOH of a saturated solution of Fe(OH)<sub>3<\/sub>? The <em>K<\/em><sub>sp<\/sub> of Fe(OH)<sub>3<\/sub> is 2.8 \u00d7 10<sup>\u221239<\/sup>.<\/li>\r\n \t<li>For a salt that has the general formula MX, an ICE chart shows that the <em>K<\/em><sub>sp<\/sub> is equal to <em>x<\/em><sup>2<\/sup>, where <em>x<\/em> is the concentration of the cation. What is the appropriate formula for the <em>K<\/em><sub>sp<\/sub> of a salt that has a general formula of MX<sub>2<\/sub>?<\/li>\r\n \t<li>Referring to Exercise 15, what is the appropriate formula for the <em>K<\/em><sub>sp<\/sub> of a salt that has a general formula of M<sub>2<\/sub>X<sub>3<\/sub> if the concentration of the cation is defined as 2<em>x<\/em>, rather than <em>x<\/em>?<\/li>\r\n \t<li>Consider a saturated solution of PbBr<sub>2<\/sub>(s). If [Pb<sup>2+<\/sup>] is 1.33 \u00d7 10<sup>\u22125<\/sup> M, find each of the following.\r\n<ol type=\"a\">\r\n \t<li>[Br\u2212]<\/li>\r\n \t<li>the <em>K<\/em><sub>sp<\/sub> of PbBr<sub>2<\/sub>(s)<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Consider a saturated solution of Pb<sub>3<\/sub>(PO<sub>4<\/sub>)<sub>2<\/sub>(s). If [Pb<sup>2+<\/sup>] is 7.34 \u00d7 10<sup>\u221214<\/sup> M, find each of the following.\r\n<ol type=\"a\">\r\n \t<li>[PO<sub>4<\/sub><sup>3\u2212<\/sup>]<\/li>\r\n \t<li>the <em>K<\/em><sub>sp<\/sub> of Pb<sub>3<\/sub>(PO<sub>4<\/sub>)<sub>2<\/sub>(s)<\/li>\r\n<\/ol>\r\n<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Answers<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n<ol>\r\n \t<li>They are reciprocals of each other.<\/li>\r\n<\/ol>\r\n<ol start=\"3\">\r\n \t<li>increase the pressure; decrease the temperature; add PCl<sub>3<\/sub>; add Cl<sub>2<\/sub>; remove PCl<sub>5<\/sub><\/li>\r\n<\/ol>\r\n<ol start=\"5\">\r\n \t<li>favour products because the numerator of the ratio for the Keq is larger than the denominator<\/li>\r\n<\/ol>\r\n<ol start=\"7\">\r\n \t<li>[latex]K_{\\text{a}}\\times K_{\\text{b}}=\\dfrac{[\\ce{H+}]\\cancel{[\\ce{X-}]}}{\\cancel{[\\ce{HX}]}}\\times \\dfrac{\\cancel{[\\ce{HX}]}[\\ce{OH-}]}{\\cancel{[\\ce{X-}]}}=[\\ce{H+}][\\ce{OH-}]=K_{\\text{w}}[\/latex]<\/li>\r\n<\/ol>\r\n<ol start=\"9\">\r\n \t<li>1.3 \u00d7 10<sup>\u22125<\/sup> mol\/L<\/li>\r\n<\/ol>\r\n<ol start=\"11\">\r\n \t<li><em>K<\/em><sub>eq<\/sub> = <em>K<\/em><sub>P<\/sub> when the number of moles of gas on both sides of the reaction is the same.<\/li>\r\n<\/ol>\r\n<ol start=\"13\">\r\n \t<li>10.35<\/li>\r\n<\/ol>\r\n<ol start=\"15\">\r\n \t<li>4<em>x<\/em><sup>3<\/sup><\/li>\r\n<\/ol>\r\n<ol start=\"17\">\r\n \t<li>\r\n<ol type=\"a\">\r\n \t<li>2.66 \u00d7 10<sup>\u22125<\/sup> M<\/li>\r\n \t<li>9.41 \u00d7 10<sup>\u221215<\/sup><\/li>\r\n<\/ol>\r\n<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>","rendered":"<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Additional Exercises<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<ol>\n<li>What is the relationship between the <em>K<\/em><sub>sp<\/sub> expressions for a chemical reaction and its reverse chemical reaction?<\/li>\n<li>What is the relationship between the <em>K<\/em><sub>w<\/sub> value for H<sub>2<\/sub>O and its reverse chemical reaction?<\/li>\n<li>For the equilibrium\n<p style=\"text-align: center;\">PCl<sub>3<\/sub>(g)\u00a0+\u00a0Cl<sub>2<\/sub>(g) \u21c4 PCl<sub>5<\/sub>(g)\u00a0+\u00a060\u00a0kJ<\/p>\n<p>list four stresses that serve to increase the amount of PCl<sub>5<\/sub>.<\/li>\n<li>For the equilibrium\n<p style=\"text-align: center;\">N<sub>2<\/sub>O<sub>4<\/sub>\u00a0+\u00a057\u00a0kJ \u21c4 2NO<sub>2<\/sub><\/p>\n<p>list four stresses that serve to increase the amount of NO<sub>2<\/sub>.<\/li>\n<li>Does a very large <em>K<\/em><sub>eq<\/sub> favour the reactants or the products? Explain your answer.<\/li>\n<li>Is the <em>K<\/em><sub>eq<\/sub> for reactions that favour reactants large or small? Explain your answer.<\/li>\n<li>Show that <em>K<\/em><sub>a<\/sub> \u00d7 <em>K<\/em><sub>b<\/sub> = <em>K<\/em><sub>w<\/sub> by determining the expressions for these two reactions and multiplying them together.\n<p style=\"text-align: center;\">HX(aq) \u21c4 H<sup>+<\/sup>(aq) + X<sup>\u2013<\/sup>(aq)<br \/>\nX<sup>\u2013<\/sup>(aq)\u00a0+\u00a0H<sub>2<\/sub>O(\u2113) \u21c4 HX(aq)\u00a0+\u00a0OH<sup>\u2013<\/sup>(aq)<\/p>\n<\/li>\n<li>Is the conjugate base of a strong acid weak or strong? Explain your answer.<\/li>\n<li>What is the solubility in moles per litre of AgCl? Use data from <a class=\"internal\" href=\"\/introductorychemistry\/chapter\/some-special-types-of-equilibria\/#table13.2\">Table 13.2 \u201cSolubility Product Constants for Slightly Soluble Ionic Compounds\u201d<\/a>.<\/li>\n<li>What is the solubility in moles per litre of Ca(OH)<sub>2<\/sub>? Use data from <a class=\"internal\" href=\"\/introductorychemistry\/chapter\/some-special-types-of-equilibria\/#table13.2\">Table 13.2<\/a>.<\/li>\n<li>Under what conditions is <em>K<\/em><sub>eq<\/sub> = <em>K<\/em><sub>P<\/sub>?<\/li>\n<li>Under what conditions is <em>K<\/em><sub>eq<\/sub> &gt; <em>K<\/em><sub>P<\/sub> when the temperature is 298 K?<\/li>\n<li>What is the pH of a saturated solution of Mg(OH)<sub>2<\/sub>? Use data from <a class=\"internal\" href=\"\/introductorychemistry\/chapter\/some-special-types-of-equilibria\/#table13.2\">Table 13.2<\/a>.<\/li>\n<li>What are the pH and the pOH of a saturated solution of Fe(OH)<sub>3<\/sub>? The <em>K<\/em><sub>sp<\/sub> of Fe(OH)<sub>3<\/sub> is 2.8 \u00d7 10<sup>\u221239<\/sup>.<\/li>\n<li>For a salt that has the general formula MX, an ICE chart shows that the <em>K<\/em><sub>sp<\/sub> is equal to <em>x<\/em><sup>2<\/sup>, where <em>x<\/em> is the concentration of the cation. What is the appropriate formula for the <em>K<\/em><sub>sp<\/sub> of a salt that has a general formula of MX<sub>2<\/sub>?<\/li>\n<li>Referring to Exercise 15, what is the appropriate formula for the <em>K<\/em><sub>sp<\/sub> of a salt that has a general formula of M<sub>2<\/sub>X<sub>3<\/sub> if the concentration of the cation is defined as 2<em>x<\/em>, rather than <em>x<\/em>?<\/li>\n<li>Consider a saturated solution of PbBr<sub>2<\/sub>(s). If [Pb<sup>2+<\/sup>] is 1.33 \u00d7 10<sup>\u22125<\/sup> M, find each of the following.\n<ol type=\"a\">\n<li>[Br\u2212]<\/li>\n<li>the <em>K<\/em><sub>sp<\/sub> of PbBr<sub>2<\/sub>(s)<\/li>\n<\/ol>\n<\/li>\n<li>Consider a saturated solution of Pb<sub>3<\/sub>(PO<sub>4<\/sub>)<sub>2<\/sub>(s). If [Pb<sup>2+<\/sup>] is 7.34 \u00d7 10<sup>\u221214<\/sup> M, find each of the following.\n<ol type=\"a\">\n<li>[PO<sub>4<\/sub><sup>3\u2212<\/sup>]<\/li>\n<li>the <em>K<\/em><sub>sp<\/sub> of Pb<sub>3<\/sub>(PO<sub>4<\/sub>)<sub>2<\/sub>(s)<\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Answers<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<ol>\n<li>They are reciprocals of each other.<\/li>\n<\/ol>\n<ol start=\"3\">\n<li>increase the pressure; decrease the temperature; add PCl<sub>3<\/sub>; add Cl<sub>2<\/sub>; remove PCl<sub>5<\/sub><\/li>\n<\/ol>\n<ol start=\"5\">\n<li>favour products because the numerator of the ratio for the Keq is larger than the denominator<\/li>\n<\/ol>\n<ol start=\"7\">\n<li><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/ql-cache\/quicklatex.com-36d8b28e45f539aadad8c775c3ed3381_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#75;&#95;&#123;&#92;&#116;&#101;&#120;&#116;&#123;&#97;&#125;&#125;&#92;&#116;&#105;&#109;&#101;&#115;&#32;&#75;&#95;&#123;&#92;&#116;&#101;&#120;&#116;&#123;&#98;&#125;&#125;&#61;&#92;&#100;&#102;&#114;&#97;&#99;&#123;&#91;&#92;&#99;&#101;&#123;&#72;&#43;&#125;&#93;&#92;&#99;&#97;&#110;&#99;&#101;&#108;&#123;&#91;&#92;&#99;&#101;&#123;&#88;&#45;&#125;&#93;&#125;&#125;&#123;&#92;&#99;&#97;&#110;&#99;&#101;&#108;&#123;&#91;&#92;&#99;&#101;&#123;&#72;&#88;&#125;&#93;&#125;&#125;&#92;&#116;&#105;&#109;&#101;&#115;&#32;&#92;&#100;&#102;&#114;&#97;&#99;&#123;&#92;&#99;&#97;&#110;&#99;&#101;&#108;&#123;&#91;&#92;&#99;&#101;&#123;&#72;&#88;&#125;&#93;&#125;&#91;&#92;&#99;&#101;&#123;&#79;&#72;&#45;&#125;&#93;&#125;&#123;&#92;&#99;&#97;&#110;&#99;&#101;&#108;&#123;&#91;&#92;&#99;&#101;&#123;&#88;&#45;&#125;&#93;&#125;&#125;&#61;&#91;&#92;&#99;&#101;&#123;&#72;&#43;&#125;&#93;&#91;&#92;&#99;&#101;&#123;&#79;&#72;&#45;&#125;&#93;&#61;&#75;&#95;&#123;&#92;&#116;&#101;&#120;&#116;&#123;&#119;&#125;&#125;\" title=\"Rendered by QuickLaTeX.com\" height=\"47\" width=\"431\" style=\"vertical-align: -19px;\" \/><\/li>\n<\/ol>\n<ol start=\"9\">\n<li>1.3 \u00d7 10<sup>\u22125<\/sup> mol\/L<\/li>\n<\/ol>\n<ol start=\"11\">\n<li><em>K<\/em><sub>eq<\/sub> = <em>K<\/em><sub>P<\/sub> when the number of moles of gas on both sides of the reaction is the same.<\/li>\n<\/ol>\n<ol start=\"13\">\n<li>10.35<\/li>\n<\/ol>\n<ol start=\"15\">\n<li>4<em>x<\/em><sup>3<\/sup><\/li>\n<\/ol>\n<ol start=\"17\">\n<li>\n<ol type=\"a\">\n<li>2.66 \u00d7 10<sup>\u22125<\/sup> M<\/li>\n<li>9.41 \u00d7 10<sup>\u221215<\/sup><\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n","protected":false},"author":90,"menu_order":6,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-7689","chapter","type-chapter","status-publish","hentry"],"part":7638,"_links":{"self":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7689","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/users\/90"}],"version-history":[{"count":3,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7689\/revisions"}],"predecessor-version":[{"id":8955,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7689\/revisions\/8955"}],"part":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/parts\/7638"}],"metadata":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7689\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/media?parent=7689"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=7689"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/contributor?post=7689"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/license?post=7689"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}