{"id":7721,"date":"2021-06-08T21:57:31","date_gmt":"2021-06-08T21:57:31","guid":{"rendered":"https:\/\/opentextbc.ca\/introductorychemistry\/chapter\/radioactivity\/"},"modified":"2021-10-12T21:50:55","modified_gmt":"2021-10-12T21:50:55","slug":"radioactivity","status":"publish","type":"chapter","link":"https:\/\/opentextbc.ca\/introductorychemistry\/chapter\/radioactivity\/","title":{"raw":"Radioactivity","rendered":"Radioactivity"},"content":{"raw":"[latexpage]\r\n
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Learning Objectives<\/p>\r\n\r\n<\/header>\r\n

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  1. Define and give examples of the major types of radioactivity.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\nWe saw in Chapter 3 \"Atoms, Molecules, and Ions\"<\/a> that atoms are composed of subatomic particles \u2014 protons, neutrons, and electrons. Protons and neutrons are located in the nucleus and provide most of the mass of an atom, while electrons circle the nucleus in shells and subshells and account for an atom\u2019s size.\r\n\r\nWe also introduced in Chapter 3 the notation for succinctly representing an isotope of a particular atom:\r\n

    [latex]\\ce{^12_6C}[\/latex]<\/p>\r\nThe element in this example, represented by the symbol C, is carbon. Its atomic number, 6, is the subscript next to the symbol and is the number of protons in the atom. The mass number, the superscript next to the symbol, is the sum of the number of protons and neutrons in the nucleus of this particular isotope. In this case, the mass number is 12, which means that the number of neutrons in the atom is 12 \u2212 6 = 6 (that is, the mass number of the atom minus the number of protons in the nucleus equals the number of neurons). Occasionally, the atomic number is omitted in this notation because the symbol of the element itself conveys its characteristic atomic number. The two isotopes of hydrogen \u2014 2<\/sup>H and 3<\/sup>H \u2014 are given their own names and symbols: deuterium (D) and tritium (T), respectively.\r\n\r\nAtomic theory in the nineteenth century presumed that nuclei had fixed compositions. But in 1896, the French scientist Henri Becquerel found that a uranium compound placed near a photographic plate made an image on the plate, even if the compound was wrapped in black cloth. He reasoned that the uranium compound was emitting some kind of radiation that passed through the cloth to expose the photographic plate. Further investigations showed that the radiation was a combination of particles and electromagnetic rays, with its ultimate source being the atomic nucleus. These emanations were ultimately called, collectively, radioactivity<\/strong>.\r\n\r\nThere are three main forms of radioactive emissions. The first is called an alpha particle<\/strong>, which is symbolized by the Greek letter \u03b1. An alpha particle is composed of two protons and two neutrons and is the same as a helium nucleus. (We often use [latex]\\ce{^4_2He}[\/latex] to represent an alpha particle.) It has a 2+ charge. When a radioactive atom emits an alpha particle, the original atom\u2019s atomic number decreases by two (because of the loss of two protons), and its mass number decreases by four (because of the loss of four nuclear particles). We can represent the emission of an alpha particle with a chemical equation\u2014for example, the alpha-particle emission of uranium-235 is as follows:\r\n

    [latex]\\ce{^235_92U}\\rightarrow\\ce{^4_2He}+\\ce{^231_90Th}[\/latex]<\/p>\r\nRather than calling this equation a chemical equation, we call it a nuclear equation<\/strong> to emphasize that the change occurs in an atomic nucleus. How do we know that a product of this reaction is [latex]\\ce{^231_90Th}[\/latex]? We use the law of conservation of matter, which says that matter cannot be created or destroyed. This means we must have the same number of protons and neutrons on both sides of the nuclear equation. If our uranium nucleus loses 2 protons, there are 90 protons remaining, identifying the element as thorium. Moreover, if we lose four nuclear particles of the original 235, there are 231 remaining. Thus we use subtraction to identify the isotope of the Th atom \u2014 in this case, [latex]\\ce{^231_90Th}[\/latex].\r\n\r\nChemists often use the names parent isotope<\/strong>\u00a0and daughter isotope<\/strong>\u00a0to represent the original atom and the product other than the alpha particle. In the previous example,\u00a0[latex]\\ce{^235_92U}[\/latex] is the parent isotope, and\u00a0[latex]\\ce{^231_90Th}[\/latex] is the daughter isotope. When one element changes into another in this manner, it undergoes radioactive decay<\/strong>.\r\n

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    Example 15.5<\/p>\r\n\r\n<\/header>\r\n

    \r\n\r\nWrite the nuclear equation that represents the radioactive decay of radon-222 by alpha particle emission and identify the daughter isotope.\r\n\r\nSolution<\/em>\r\nRadon has an atomic number of 86, so the parent isotope is represented as [latex]\\ce{^222_86Rn}[\/latex]. We represent the alpha particle as [latex]\\ce{^4_2He}[\/latex] and use subtraction (222 \u2212 4 = 218 and 86 \u2212 2 = 84) to identify the daughter isotope as polonium:\r\n

    [latex]\\ce{^222_86Rn}\\rightarrow\\ce{^4_2He}+\\ce{^218_84Po}[\/latex]<\/p>\r\nTest Yourself<\/em>\r\nWrite the nuclear equation that represents radioactive decay of polonium-208 by alpha particle emission and identify the daughter isotope.\r\n\r\nAnswer<\/em>\r\n[latex]\\ce{^208_84Po}\\rightarrow \\ce{^4_2He}+\\ce{^204_82Pb}[\/latex]; daughter isotope: [latex]\\ce{^204_82Pb}[\/latex]\r\n\r\n<\/div>\r\n<\/div>\r\nThe second major type of radioactive emission is called a beta particle<\/strong>, symbolized by the Greek letter \u03b2. A beta particle is an electron ejected from the nucleus (not from the shells of electrons about the nucleus) and has a 1\u2212 charge. We can also represent a beta particle as [latex]\\ce{^0_{-1}e}[\/latex]. The net effect of beta particle emission on a nucleus is that a neutron is converted to a proton. The overall mass number stays the same, but because the number of protons increases by one, the atomic number goes up by one. Carbon-14 decays by emitting a beta particle:\r\n

    [latex]\\ce{^14_6C}\\rightarrow\\ce{^14_7N}+\\ce{^0_{-1}e}[\/latex]<\/p>\r\nAgain, the sum of the atomic numbers is the same on both sides of the equation, as is the sum of the mass numbers. (Note that the electron is assigned an \u201catomic number\u201d of \u20131, equal to its charge.)\r\n\r\nThe third major type of radioactive emission is not a particle but rather a very energetic form of electromagnetic radiation called gamma rays<\/strong>, symbolized by the Greek letter \u03b3. Gamma rays themselves do not carry an overall electrical charge, but they may knock electrons out of atoms in a sample of matter and make it electrically charged (for which gamma rays are termed ionizing radiation<\/em>). For example, in the radioactive decay of radon-222, both alpha and gamma radiation are emitted, with the latter having an energy of 8.2 \u00d7 10\u221214<\/sup> J per nucleus decayed:\r\n

    [latex]\\ce{^222_86Rn}\\rightarrow\\ce{^4_2He}+\\ce{^218_84Po}+\\gamma[\/latex]<\/p>\r\nThis may not seem like much energy, but if 1 mol of Rn atoms were to decay, the gamma ray energy would be 4.9 \u00d7 107<\/sup> kJ!\r\n

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    Example 15.6<\/p>\r\n\r\n<\/header>\r\n

    \r\n\r\nWrite the nuclear equation that represents the radioactive decay of boron-12 by beta particle emission and identify the daughter isotope. A gamma ray is emitted simultaneously with the beta particle.\r\n\r\nSolution<\/em>\r\nThe parent isotope is[latex]\\ce{^12_5B}[\/latex], while one of the products is [latex]\\ce{^0_{-1}e}[\/latex]. So that the mass and atomic numbers have the same value on both sides, the mass number of the daughter isotope must be 12, and its atomic number must be 6. The element having an atomic number of 6 is carbon. Thus the complete nuclear equation is as follows:\r\n

    [latex]\\ce{^12_5B}\\rightarrow\\ce{^12_6C}+\\ce{^0_{-1}e}+\\gamma[\/latex]<\/p>\r\nThe daughter isotope is carbon-12.\r\n\r\nTest Yourself<\/em>\r\nWrite the nuclear equation that represents the radioactive decay of technetium-133 by beta particle emission and identify the daughter isotope. A gamma ray is emitted simultaneously with the beta particle.\r\n\r\nAnswer<\/em>\r\n[latex]\\ce{^133_43Tc}\\rightarrow\\ce{^133_44Ru}+\\ce{^0_-1e}+\\gamma[\/latex]; daughter isotope: ruthenium-133\r\n\r\n<\/div>\r\n<\/div>\r\nAlpha, beta, and gamma emissions have different abilities to penetrate matter. The relatively large alpha particle is easily stopped by matter (although it may impart a significant amount of energy to the matter it contacts). Beta particles penetrate slightly into matter, perhaps a few centimetres at most. Gamma rays can penetrate deeply into matter and can impart a large amount of energy into the surrounding matter. Table 15.5 \"The Three Main Forms of Radioactive Emissions\" summarizes the properties of the three main types of radioactive emissions.\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n
    Table 15.5 The Three Main Forms of Radioactive Emissions<\/caption>\r\n
    Characteristic<\/th>\r\nAlpha Particles<\/th>\r\nBeta Particles<\/th>\r\nGamma Rays<\/th>\r\n<\/tr>\r\n<\/thead>\r\n
    symbols<\/td>\r\n\u03b1, [latex]\\ce{^4_2He}[\/latex]<\/td>\r\n\u03b2, [latex]\\ce{^0_-1e}[\/latex]<\/td>\r\n\u03b3<\/td>\r\n<\/tr>\r\n
    identity<\/td>\r\nhelium nucleus<\/td>\r\nelectron<\/td>\r\nelectromagnetic radiation<\/td>\r\n<\/tr>\r\n
    charge<\/td>\r\n2+<\/td>\r\n1\u2212<\/td>\r\nnone<\/td>\r\n<\/tr>\r\n
    mass number<\/td>\r\n4<\/td>\r\n0<\/td>\r\n0<\/td>\r\n<\/tr>\r\n
    penetrating power<\/td>\r\nminimal (will not penetrate skin)<\/td>\r\nshort (will penetrate skin and some tissues slightly)<\/td>\r\ndeep (will penetrate tissues deeply)<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\nOccasionally, an atomic nucleus breaks apart into smaller pieces in a radioactive process called spontaneous fission (or fission)<\/strong>. Typically, the daughter isotopes produced by fission are a varied mix of products, rather than a specific isotope as with alpha and beta particle emission. Often, fission produces excess neutrons that will sometimes be captured by other nuclei, possibly inducing additional radioactive events. Uranium-235 undergoes spontaneous fission to a small extent. One typical reaction is:\r\n

    [latex]\\ce{^235_92U}\\rightarrow\\ce{^139_56Ba}+\\ce{^94_36Kr}+2\\ce{^1_0n}[\/latex]<\/p>\r\nwhere [latex]\\ce{^1_0n}[\/latex] is a neutron. As with any nuclear process, the sums of the atomic numbers and mass numbers must be the same on both sides of the equation. Spontaneous fission is found only in large nuclei. The smallest nucleus that exhibits spontaneous fission is lead-208. (Fission is the radioactive process used in nuclear power plants and one type of nuclear bomb.)\r\n

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    Key Takeaways<\/p>\r\n\r\n<\/header>\r\n

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