{"id":7932,"date":"2021-06-08T21:58:10","date_gmt":"2021-06-08T21:58:10","guid":{"rendered":"https:\/\/opentextbc.ca\/introductorychemistry\/chapter\/end-of-chapter-16-material\/"},"modified":"2021-10-13T18:58:46","modified_gmt":"2021-10-13T18:58:46","slug":"end-of-chapter-16-material","status":"publish","type":"chapter","link":"https:\/\/opentextbc.ca\/introductorychemistry\/chapter\/end-of-chapter-16-material\/","title":{"raw":"End-of-Chapter Material","rendered":"End-of-Chapter Material"},"content":{"raw":"[latexpage]\r\n
\r\n

Additional Exercises<\/p>\r\n\r\n<\/header>\r\n

\r\n
    \r\n \t
  1. Cycloalkanes are named based on the number of C atoms in them, just like regular alkanes, but with the prefix cyclo<\/em>\u2013 on the name. What are the names of the three smallest cycloalkanes?<\/li>\r\n \t
  2. Cycloalkenes are named similarly to cycloalkanes (see Exercise 1). What are the names of the cycloalkenes with five, six, and seven C atoms?<\/li>\r\n \t
  3. Draw the bond-line structure of all noncyclic alkanes with only four C atoms.<\/li>\r\n \t
  4. Draw the bond-line structure of all noncyclic alkanes with only five C atoms.<\/li>\r\n \t
  5. Cyclic alkanes can also have substituent groups on the ring. Draw the bond-line structure of all cyclic alkanes with only four C atoms.<\/li>\r\n \t
  6. Cyclic alkanes can also have substituent groups on the ring. Draw the bond-line structure of all cyclic alkanes with only five C atoms.<\/li>\r\n \t
  7. Draw and name all possible isomers of pentene.<\/li>\r\n \t
  8. Draw and name all possible normal (that is, straight-chain) isomers of heptyne.<\/li>\r\n \t
  9. Polyunsaturated alkenes have more than one C\u2013C double bond. Draw the carbon backbone of all possible noncyclic polyunsaturated alkenes with four C atoms and two double bonds. What are the complete molecular formulas for each possible molecule?<\/li>\r\n \t
  10. Draw the carbon backbone of all possible five-carbon cyclic alkenes with two double bonds, assuming no substituents on the ring.<\/li>\r\n \t
  11. If a hydrocarbon is combined with enough halogen, all the H atoms will eventually be substituted with that halogen atom. Write the balanced chemical reaction between ethane and excess chlorine.<\/li>\r\n \t
  12. If a hydrocarbon is combined with enough halogen, all the H atoms will eventually be substituted with that halogen atom. Write the balanced chemical reaction between butane and excess bromine.<\/li>\r\n \t
  13. Molecules with multiple double bonds can also participate in addition reactions. Draw the structure of the product when butadiene, CH2<\/sub>=CH\u2013CH=CH2<\/sub>, reacts with chlorine.<\/li>\r\n \t
  14. Draw the structure of the product when allene, CH2<\/sub>=C=CH2<\/sub>, reacts with bromine.<\/li>\r\n \t
  15. What is the maximum number of methyl groups that can be on a propane backbone before the molecule cannot be named as a propane compound?<\/li>\r\n \t
  16. Explain why cycloethane cannot exist as a real molecule.<\/li>\r\n \t
  17. In the gasoline industry, what is called isooctane is actually 2,2,4-trimethylpentane. Draw the structure of isooctane.<\/li>\r\n \t
  18. Isooctane (see Exercise 17) is an isomer of what straight-chain alkane?<\/li>\r\n \t
  19. The actual name for the explosive TNT is 2,4,6-trinitrotoluene. If the structure of TNT is as shown below, propose the structure of the parent compound toluene.\r\n

    [latex]\\chemfig{-[:-90]*6(-(-O_2N)=-(-NO_2)=-(-NO_2)=)}[\/latex]<\/p>\r\n<\/li>\r\n \t

  20. Phenol is hydroxybenzene, the simplest aromatic alcohol. Picric acid is an explosive derivative of phenol whose formal name is 2,4,6-trinitrophenol. With reference to Exercise 19, draw the structure of picric acid.<\/li>\r\n \t
  21. Draw the structures of all possible straight-chain isomers of bromopentane.<\/li>\r\n \t
  22. Draw the structures of all the possible isomers of butanol. Include branched isomers.<\/li>\r\n \t
  23. What is the final product of the double<\/em> elimination of HCl from 1,1-dichloroethane?<\/li>\r\n \t
  24. Draw the structure of the final product of the double<\/em> elimination of 1,3-dibromopropane.<\/li>\r\n \t
  25. Draw the structure of and name the alcohol whose double elimination would yield the same product as in Exercise 23. Name the molecule as a hydroxyl-substituted compound.<\/li>\r\n \t
  26. Draw the structure of and name the alcohol whose double elimination would yield the same product as in Exercise 24. Name the molecule as a hydroxyl-substituted compound.<\/li>\r\n \t
  27. Draw the smallest molecule that can have a separate aldehyde and carboxylic acid group.<\/li>\r\n \t
  28. Name the functional group(s) in the following structure:\r\n

    [latex]\\chemfig{*6(-=(*5(-(--[:0]NH_2)--(=O)-))-=-(-HO)=)}[\/latex]<\/p>\r\n<\/li>\r\n \t

  29. Ethyl acetate is a common ingredient in nail-polish remover because it is a good solvent. Draw the structure of ethyl acetate.<\/li>\r\n \t
  30. A lactone is an ester that has its ester functional group in a ring. Draw the structure of the smallest possible lactone. (It is called acetolactone, which might give you a hint about its structure.)<\/li>\r\n \t
  31. Draw the structure of diethyl ether, once used as an anaesthetic.<\/li>\r\n \t
  32. The smallest cyclic ether is called an epoxide. Draw its structure.<\/li>\r\n \t
  33. Write the chemical reaction of HCl with trimethylamine.<\/li>\r\n \t
  34. Putrescine and cadaverine are molecules with two amine groups on the opposite ends of a butane backbone and a pentane backbone, respectively. They are both emitted by rotting corpses. Draw their structures and determine their molecular formulas.<\/li>\r\n \t
  35. With four monomers, draw two possible structures of a copolymer composed of ethylene and propylene.<\/li>\r\n \t
  36. With four monomers, draw two possible structures of a copolymer composed of ethylene and styrene.<\/li>\r\n \t
  37. Draw the silicone that can be made from this monomer:\r\n

    [latex]\\chemfig{[:90]*6((-[:-90]Si?[a]-[:-90])-----(-[:-90]Si?[a,2]-[:-90]([:-60]*6(-----))))}[\/latex]<\/p>\r\n<\/li>\r\n \t

  38. One of the ingredients in the original Silly Putty was a silicone polymer with two methyl groups on each Si atom. Draw this silicone.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n
    \r\n

    Answers<\/p>\r\n\r\n<\/header>\r\n

    \r\n
      \r\n \t
    1. cyclopropane, cyclobutane, and cyclopentane<\/li>\r\n<\/ol>\r\n
        \r\n \t
      1. Bond-line structure of all noncyclic alkanes with only four C atoms:\r\n

        [latex]\\chemfig{-[:-30]-[:30]-[:-30]}\\hspace{4em}\\chemfig{-[:-90](-[:-150])-[:-30]}[\/latex]<\/p>\r\n<\/li>\r\n<\/ol>\r\n

          \r\n \t
        1. Bond-line structure of all cyclic alkanes with only four C atoms:\r\n

          [latex]\\chemfig{*4(----)}\\hspace{4em}\\chemfig{*3(-(-)--)}[\/latex]<\/p>\r\n<\/li>\r\n<\/ol>\r\n

            \r\n \t
          1. Isomers of pentene:\r\n

            [latex]\\begin{align*}\r\n\\chemfig{=[:30]-[:-30]-[:30]-[:-30]}&\\hspace{4em}\\chemfig{-[:30]=[:-30]-[:30]-[:-30]} \\\\ \\\\\r\n\\chemfig{=[:30](-[:90])-[:-30]-[:30]}&\\hspace{4em}\\chemfig{-[:30](-[:90])=[:-30]-[:30]}\r\n\\end{align*}[\/latex]<\/p>\r\n<\/li>\r\n<\/ol>\r\n

              \r\n \t
            1. Carbon backbone of all possible noncyclic polyunsaturated alkenes with four C atoms and two double bonds:\r\n

              [latex]\\chemfig{H_2C=C=CH-[:-60]CH_3}\\hspace{4em}\\chemfig{H_2C=[:-60]HC-CH=[:-60]CH_2}[\/latex]<\/p>\r\nBoth molecular formulas are C4<\/sub>H6<\/sub>.<\/li>\r\n<\/ol>\r\n

                \r\n \t
              1. C2<\/sub>H6<\/sub> + 6Cl2<\/sub> \u2192 C2<\/sub>Cl6<\/sub> + 6HCl<\/li>\r\n<\/ol>\r\n
                  \r\n \t
                1. Structure of butadiene's reaction with chlorine:\r\n

                  [latex]\\chemfig{H-(-[:90]Cl)(-[:-90]H)-(-[:90]Cl)(-[:-90]H)-(-[:90]Cl)(-[:-90]H)-(-[:90]Cl)(-[:-90]H)-H}[\/latex]<\/p>\r\n<\/li>\r\n<\/ol>\r\n

                    \r\n \t
                  1. two<\/li>\r\n<\/ol>\r\n
                      \r\n \t
                    1. Structure of isooctane:\r\n

                      [latex]\\chemfig{-[:30](-[:90])(-[:150])-[:-30](-[:-90])-[:30]-[:-30]}[\/latex]<\/p>\r\n<\/li>\r\n<\/ol>\r\n

                        \r\n \t
                      1. Structure of toluene:\r\n

                        [latex]\\chemfig{-[:-90]*6(-=-=-=)}[\/latex]<\/p>\r\n<\/li>\r\n<\/ol>\r\n

                          \r\n \t
                        1. Straight-chain isomers of bromopentane:\r\n

                          [latex]\\chemfig{Br-[:30]-[:-30]-[:30]-[:-30]-[:30]}\\hspace{4em}\\chemfig{-[:30](-[:90]Br)-[:-30]-[:30]-[:-30]}\\hspace{4em}\\chemfig{-[:-30]-[:30](-[:90]Br)-[:-30]-[:30]}[\/latex]<\/p>\r\n<\/li>\r\n<\/ol>\r\n

                            \r\n \t
                          1. ethyne\r\n

                            [latex]\\begin{align*}\\chemfig{HO-[:-60]--[:60]OH} &\\hspace{2em} \\chemfig{HO-[:-60](-[:-120]HO)-}\\end{align*}[\/latex]<\/p>\r\n<\/li>\r\n<\/ol>\r\n

                              \r\n \t
                            1. The names are 1,2-dihydroxyethane and 1,1-dihydroxyethane, respectively.<\/li>\r\n<\/ol>\r\n
                                \r\n \t
                              1. [latex]\\chemfig{H-[:-30](=[:-90]O)-[:30](=[:90]O)-[:-30]OH}[\/latex]<\/li>\r\n<\/ol>\r\n
                                  \r\n \t
                                1. [latex]\\chemfig{-[:30](=[:90]O)-[:-30]O-[:30]-[:-30]}[\/latex]<\/li>\r\n<\/ol>\r\n
                                    \r\n \t
                                  1. [latex]\\chemfig{-[:30]-[:-30]O-[:30]-[:-30]}[\/latex]<\/li>\r\n<\/ol>\r\n
                                      \r\n \t
                                    1. (CH3<\/sub>)3<\/sub>N +\u00a0HCl \u2192\u00a0(CH3<\/sub>)3<\/sub>NHCl<\/li>\r\n<\/ol>\r\n
                                        \r\n \t
                                      1. (answers will vary)\r\n

                                        [latex]\\begin{array}{c}\\chemfig{-[@{left,0.5}]C(-[:90]H_2)-C(-[:90]H_2)-C(-[:90]H)(-[:-90]CH_3)-C(-[:90]H_2)-C(-[:90]H_2)-C(-[:90]H_2)-C(-[:90]H)(-[:-90]CH_3)-C(-[:90]H_2)-[@{right,0.5}]}\r\n\\polymerdelim[delimiters={[]},height=25 pt]{left}{right} \\\\ \\\\\r\n\\chemfig{-[@{left,0.5}]C(-[:90]H_2)-C(-[:90]H)(-[:-90]CH_3)-C(-[:90]H_2)-C(-[:90]H_2)-C(-[:90]H_2)-C(-[:90]H_2)-C(-[:90]H)(-[:-90]CH_3)-C(-[:90]H_2)-[@{right,0.5}]}\r\n\\polymerdelim[delimiters={[]},height=25 pt]{left}{right}\r\n\\end{array}[\/latex]<\/p>\r\n<\/li>\r\n<\/ol>\r\n

                                          \r\n \t
                                        1. [latex]\\chemfig{-[@{left,0.5}]Si(-[:90])(-[:-90]([:-60]*6(-----)))-Si(-[:90]([:120]*6(-----)))(-[:-90])-[:0, 2.0]Si(-[:90])(-[:-90]([:-60]*6(-----)))-Si(-[:90]([:120]*6(-----)))(-[:-90])-[@{right,0.5}]}\r\n\\polymerdelim[delimiters={[]},height=20 pt]{left}{right}[\/latex]<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>","rendered":"
                                          \n
                                          \n

                                          Additional Exercises<\/p>\n<\/header>\n

                                          \n
                                            \n
                                          1. Cycloalkanes are named based on the number of C atoms in them, just like regular alkanes, but with the prefix cyclo<\/em>\u2013 on the name. What are the names of the three smallest cycloalkanes?<\/li>\n
                                          2. Cycloalkenes are named similarly to cycloalkanes (see Exercise 1). What are the names of the cycloalkenes with five, six, and seven C atoms?<\/li>\n
                                          3. Draw the bond-line structure of all noncyclic alkanes with only four C atoms.<\/li>\n
                                          4. Draw the bond-line structure of all noncyclic alkanes with only five C atoms.<\/li>\n
                                          5. Cyclic alkanes can also have substituent groups on the ring. Draw the bond-line structure of all cyclic alkanes with only four C atoms.<\/li>\n
                                          6. Cyclic alkanes can also have substituent groups on the ring. Draw the bond-line structure of all cyclic alkanes with only five C atoms.<\/li>\n
                                          7. Draw and name all possible isomers of pentene.<\/li>\n
                                          8. Draw and name all possible normal (that is, straight-chain) isomers of heptyne.<\/li>\n
                                          9. Polyunsaturated alkenes have more than one C\u2013C double bond. Draw the carbon backbone of all possible noncyclic polyunsaturated alkenes with four C atoms and two double bonds. What are the complete molecular formulas for each possible molecule?<\/li>\n
                                          10. Draw the carbon backbone of all possible five-carbon cyclic alkenes with two double bonds, assuming no substituents on the ring.<\/li>\n
                                          11. If a hydrocarbon is combined with enough halogen, all the H atoms will eventually be substituted with that halogen atom. Write the balanced chemical reaction between ethane and excess chlorine.<\/li>\n
                                          12. If a hydrocarbon is combined with enough halogen, all the H atoms will eventually be substituted with that halogen atom. Write the balanced chemical reaction between butane and excess bromine.<\/li>\n
                                          13. Molecules with multiple double bonds can also participate in addition reactions. Draw the structure of the product when butadiene, CH2<\/sub>=CH\u2013CH=CH2<\/sub>, reacts with chlorine.<\/li>\n
                                          14. Draw the structure of the product when allene, CH2<\/sub>=C=CH2<\/sub>, reacts with bromine.<\/li>\n
                                          15. What is the maximum number of methyl groups that can be on a propane backbone before the molecule cannot be named as a propane compound?<\/li>\n
                                          16. Explain why cycloethane cannot exist as a real molecule.<\/li>\n
                                          17. In the gasoline industry, what is called isooctane is actually 2,2,4-trimethylpentane. Draw the structure of isooctane.<\/li>\n
                                          18. Isooctane (see Exercise 17) is an isomer of what straight-chain alkane?<\/li>\n
                                          19. The actual name for the explosive TNT is 2,4,6-trinitrotoluene. If the structure of TNT is as shown below, propose the structure of the parent compound toluene.\n

                                            \"\chemfig{-[:-90]*6(-(-O_2N)=-(-NO_2)=-(-NO_2)=)}\"<\/p>\n<\/li>\n

                                          20. Phenol is hydroxybenzene, the simplest aromatic alcohol. Picric acid is an explosive derivative of phenol whose formal name is 2,4,6-trinitrophenol. With reference to Exercise 19, draw the structure of picric acid.<\/li>\n
                                          21. Draw the structures of all possible straight-chain isomers of bromopentane.<\/li>\n
                                          22. Draw the structures of all the possible isomers of butanol. Include branched isomers.<\/li>\n
                                          23. What is the final product of the double<\/em> elimination of HCl from 1,1-dichloroethane?<\/li>\n
                                          24. Draw the structure of the final product of the double<\/em> elimination of 1,3-dibromopropane.<\/li>\n
                                          25. Draw the structure of and name the alcohol whose double elimination would yield the same product as in Exercise 23. Name the molecule as a hydroxyl-substituted compound.<\/li>\n
                                          26. Draw the structure of and name the alcohol whose double elimination would yield the same product as in Exercise 24. Name the molecule as a hydroxyl-substituted compound.<\/li>\n
                                          27. Draw the smallest molecule that can have a separate aldehyde and carboxylic acid group.<\/li>\n
                                          28. Name the functional group(s) in the following structure:\n

                                            \"\chemfig{*6(-=(*5(-(--[:0]NH_2)--(=O)-))-=-(-HO)=)}\"<\/p>\n<\/li>\n

                                          29. Ethyl acetate is a common ingredient in nail-polish remover because it is a good solvent. Draw the structure of ethyl acetate.<\/li>\n
                                          30. A lactone is an ester that has its ester functional group in a ring. Draw the structure of the smallest possible lactone. (It is called acetolactone, which might give you a hint about its structure.)<\/li>\n
                                          31. Draw the structure of diethyl ether, once used as an anaesthetic.<\/li>\n
                                          32. The smallest cyclic ether is called an epoxide. Draw its structure.<\/li>\n
                                          33. Write the chemical reaction of HCl with trimethylamine.<\/li>\n
                                          34. Putrescine and cadaverine are molecules with two amine groups on the opposite ends of a butane backbone and a pentane backbone, respectively. They are both emitted by rotting corpses. Draw their structures and determine their molecular formulas.<\/li>\n
                                          35. With four monomers, draw two possible structures of a copolymer composed of ethylene and propylene.<\/li>\n
                                          36. With four monomers, draw two possible structures of a copolymer composed of ethylene and styrene.<\/li>\n
                                          37. Draw the silicone that can be made from this monomer:\n

                                            \"\chemfig{[:90]*6((-[:-90]Si?[a]-[:-90])-----(-[:-90]Si?[a,2]-[:-90]([:-60]*6(-----))))}\"<\/p>\n<\/li>\n

                                          38. One of the ingredients in the original Silly Putty was a silicone polymer with two methyl groups on each Si atom. Draw this silicone.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n
                                            \n
                                            \n

                                            Answers<\/p>\n<\/header>\n

                                            \n
                                              \n
                                            1. cyclopropane, cyclobutane, and cyclopentane<\/li>\n<\/ol>\n
                                                \n
                                              1. Bond-line structure of all noncyclic alkanes with only four C atoms:\n

                                                \"\chemfig{-[:-30]-[:30]-[:-30]}\hspace{4em}\chemfig{-[:-90](-[:-150])-[:-30]}\"<\/p>\n<\/li>\n<\/ol>\n

                                                  \n
                                                1. Bond-line structure of all cyclic alkanes with only four C atoms:\n

                                                  \"\chemfig{*4(----)}\hspace{4em}\chemfig{*3(-(-)--)}\"<\/p>\n<\/li>\n<\/ol>\n

                                                    \n
                                                  1. Isomers of pentene:\n

                                                    \n

                                                      <\/span>   <\/span>\"\begin{align*}<\/p>\n<\/li>\n<\/ol>\n

                                                      \n
                                                    1. Carbon backbone of all possible noncyclic polyunsaturated alkenes with four C atoms and two double bonds:\n

                                                      \"\chemfig{H_2C=C=CH-[:-60]CH_3}\hspace{4em}\chemfig{H_2C=[:-60]HC-CH=[:-60]CH_2}\"<\/p>\n

                                                      Both molecular formulas are C4<\/sub>H6<\/sub>.<\/li>\n<\/ol>\n

                                                        \n
                                                      1. C2<\/sub>H6<\/sub> + 6Cl2<\/sub> \u2192 C2<\/sub>Cl6<\/sub> + 6HCl<\/li>\n<\/ol>\n
                                                          \n
                                                        1. Structure of butadiene’s reaction with chlorine:\n

                                                          \"\chemfig{H-(-[:90]Cl)(-[:-90]H)-(-[:90]Cl)(-[:-90]H)-(-[:90]Cl)(-[:-90]H)-(-[:90]Cl)(-[:-90]H)-H}\"<\/p>\n<\/li>\n<\/ol>\n

                                                            \n
                                                          1. two<\/li>\n<\/ol>\n
                                                              \n
                                                            1. Structure of isooctane:\n

                                                              \"\chemfig{-[:30](-[:90])(-[:150])-[:-30](-[:-90])-[:30]-[:-30]}\"<\/p>\n<\/li>\n<\/ol>\n

                                                                \n
                                                              1. Structure of toluene:\n

                                                                \"\chemfig{-[:-90]*6(-=-=-=)}\"<\/p>\n<\/li>\n<\/ol>\n

                                                                  \n
                                                                1. Straight-chain isomers of bromopentane:\n

                                                                  \"\chemfig{Br-[:30]-[:-30]-[:30]-[:-30]-[:30]}\hspace{4em}\chemfig{-[:30](-[:90]Br)-[:-30]-[:30]-[:-30]}\hspace{4em}\chemfig{-[:-30]-[:30](-[:90]Br)-[:-30]-[:30]}\"<\/p>\n<\/li>\n<\/ol>\n

                                                                    \n
                                                                  1. ethyne\n

                                                                    \n

                                                                      <\/span>   <\/span>\"\begin{align*}\chemfig{HO-[:-60]--[:60]OH} &\hspace{2em} \chemfig{HO-[:-60](-[:-120]HO)-}\end{align*}\"<\/p>\n<\/li>\n<\/ol>\n

                                                                      \n
                                                                    1. The names are 1,2-dihydroxyethane and 1,1-dihydroxyethane, respectively.<\/li>\n<\/ol>\n
                                                                        \n
                                                                      1. \"\chemfig{H-[:-30](=[:-90]O)-[:30](=[:90]O)-[:-30]OH}\"<\/li>\n<\/ol>\n
                                                                          \n
                                                                        1. \"\chemfig{-[:30](=[:90]O)-[:-30]O-[:30]-[:-30]}\"<\/li>\n<\/ol>\n
                                                                            \n
                                                                          1. \"\chemfig{-[:30]-[:-30]O-[:30]-[:-30]}\"<\/li>\n<\/ol>\n
                                                                              \n
                                                                            1. (CH3<\/sub>)3<\/sub>N +\u00a0HCl \u2192\u00a0(CH3<\/sub>)3<\/sub>NHCl<\/li>\n<\/ol>\n
                                                                                \n
                                                                              1. (answers will vary)\n

                                                                                \"\begin{array}{c}\chemfig{-[@{left,0.5}]C(-[:90]H_2)-C(-[:90]H_2)-C(-[:90]H)(-[:-90]CH_3)-C(-[:90]H_2)-C(-[:90]H_2)-C(-[:90]H_2)-C(-[:90]H)(-[:-90]CH_3)-C(-[:90]H_2)-[@{right,0.5}]}<\/p>\n<\/li>\n<\/ol>\n

                                                                                  \n
                                                                                1. \"\chemfig{-[@{left,0.5}]Si(-[:90])(-[:-90]([:-60]*6(-----)))-Si(-[:90]([:120]*6(-----)))(-[:-90])-[:0, 2.0]Si(-[:90])(-[:-90]([:-60]*6(-----)))-Si(-[:90]([:120]*6(-----)))(-[:-90])-[@{right,0.5}]}<\/li>\n<\/ol>\n<\/div>\n<\/div>\n","protected":false},"author":90,"menu_order":7,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-7932","chapter","type-chapter","status-publish","hentry"],"part":7735,"_links":{"self":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7932","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/users\/90"}],"version-history":[{"count":6,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7932\/revisions"}],"predecessor-version":[{"id":9013,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7932\/revisions\/9013"}],"part":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/parts\/7735"}],"metadata":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/7932\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/media?parent=7932"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=7932"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/contributor?post=7932"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/opentextbc.ca\/introductorychemistry\/wp-json\/wp\/v2\/license?post=7932"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}