{"id":155,"date":"2020-06-23T12:09:05","date_gmt":"2020-06-23T12:09:05","guid":{"rendered":"https:\/\/opentextbc.ca\/mathfortrades2\/chapter\/perimeter\/"},"modified":"2022-07-13T17:40:21","modified_gmt":"2022-07-13T17:40:21","slug":"perimeter","status":"publish","type":"chapter","link":"https:\/\/opentextbc.ca\/mathfortrades2\/chapter\/perimeter\/","title":{"raw":"Perimeter","rendered":"Perimeter"},"content":{"raw":"&nbsp;\r\n\r\nhttps:\/\/media.bccampus.ca\/id\/0_zcnd7r40?width=608&height=402&playerId=23449753\r\n\r\nClick play on the following audio player to listen along as you read this section.\r\n\r\nhttps:\/\/media.bccampus.ca\/id\/0_x6n0abu8?width=608&height=402&playerId=23449753\r\n\r\n<img class=\"alignleft\" style=\"font-size: 18.6667px; orphans: 1;\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2020\/06\/a-baseball-field-e1620154751434.jpg\" alt=\"\" width=\"150\" height=\"150\" \/>\r\n\r\nWhat does the word perimeter refer to? What if someone asked you to walk the perimeter of a baseball field? What does that mean?\r\n\r\n<strong>Perimeter:<\/strong><strong><em>\u00a0<\/em><\/strong> A perimeter is a path that surrounds a two-dimensional object. The word comes from the Greek peri (around) and metre (measure). The term may be used either for the path or its length \u2013 it can be thought of as the length of an outline of a shape. The perimeter of a circle is called its circumference.\r\n\r\nIf you were to walk the perimeter of a baseball field you would walk around the outer edges of the field and calculate the length. If you wanted to find the perimeter of anything it would basically be like walking around the outer edge of it. Obviously we can\u2019t do that for smaller shapes or objects but you get the idea.\r\n\r\n<img class=\"aligncenter wp-image-127 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-1-3.png\" alt=\"Stick figures walking around the outside of a square, circle, triange, and pentagon.\" width=\"1742\" height=\"373\" \/>\r\n\r\nWhen calculating perimeter the answer will always be a linear (or one dimensional) measurement such as feet, inches, metres or centimetres.\r\n\r\n<img class=\"alignleft\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/interior-of-a-house-e1620154830828.png\" width=\"150\" height=\"150\" \/>\r\n\r\nWhy would perimeter be important to us in the construction world?\r\n\r\nLet\u2019s say you are a carpenter and you want to put baseboard in a room. Calculating how much baseboard you need around the walls involves calculating the perimeter of the room. This would also be true for plumbers if they are putting perimeter drain around a house. Perimeter can be used in many different areas of the construction world.\r\n<h1>The Perimeter of a Square and a Rectangle<\/h1>\r\n<img class=\"alignleft wp-image-129\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture11-2.png\" alt=\"\" width=\"300\" height=\"177\" \/>\r\n\r\nA square and a rectangle are both similar in that they have four sides. Another characteristic that is common to both is each has four right angles. A right angle is an angle of 90 degrees.\r\n\r\nIn a square, all four sides are equal while in a rectangle the opposite sides are equal but not the adjacent sides. Calculating the perimeter of a square and a rectangle is very similar. First we'll define what each side is called.\r\n\r\n<img class=\"aligncenter wp-image-130 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-3-1.png\" alt=\"\" width=\"100%\" \/>\r\n\r\nThe square is straight forward as the length of each of the sides is the same, and the name of each side is simply \"SIDE.\" In a rectangle, the long side of the rectangle is referred to as the \"LENGTH\" while the shorter side is referred to as the \"WIDTH.\"\r\n\r\n<img class=\"alignleft wp-image-131 size-thumbnail\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/lightbulb-150x150.jpg\" alt=\"\" width=\"150\" height=\"150\" \/>\r\n\r\nBefore I go through calculating perimeter of a square and rectangle, take a guess at what the formula might be.\r\n\r\n<img class=\"aligncenter wp-image-132 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1.png\" alt=\"\" width=\"100%\" \/>\r\n\r\n<img class=\"aligncenter wp-image-133\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-7-1-300x279.png\" alt=\"\" width=\"200\" height=\"186\" \/>\r\n\r\nIf we go back to our definition and say that the perimeter is the length that surrounds a two dimensional object, then the perimeter of both would be the length of the four sides combined.\r\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{ll} \\textbf{Square:} &amp; \\text{Perimeter}= \\text{ side}+ \\text{ side} + \\text{ side} + \\text{ side}\\\\ \\textbf{Rectangle:} &amp; \\text{Perimeter} = \\text{length} + \\text{width} + \\text{width} + \\text{length}\\end{array}[\/latex]<\/p>\r\n<img class=\"alignleft wp-image-134\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/questionmark-e1611092707517.jpg\" alt=\"\" width=\"150\" height=\"122\" \/>\r\n\r\nWould there be any other way to express the two formulas?\r\n\r\nTake a guess.\r\n\r\n<img class=\"aligncenter wp-image-132 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1.png\" alt=\"\" width=\"100%\" \/>\r\n\r\n<img class=\"aligncenter wp-image-133\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-7-1-300x279.png\" alt=\"\" width=\"200\" height=\"186\" \/>\r\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{ll} \\textbf{Square:} &amp; \\text{Perimeter}= \\text{ side} \\times 4 \\\\ \\textbf{Rectangle:} &amp; \\text{Perimeter} = (\\text{length}\\times 2)+(\\text{width} \\times 2) \\end{array}[\/latex]<\/p>\r\nBoth versions of each formula are correct and you can use whichever you choose to answer questions.\r\n\r\n<img class=\"alignleft wp-image-135\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/memory-300x214.jpg\" alt=\"\" width=\"150\" height=\"107\" \/>\r\n\r\nThis might be a good time to stop and discuss memorization.\r\n\r\nMemorization is a topic that comes up quite frequently in math. Students often ask if they have to memorize formulas and for the most part the answer is yes.\r\n\r\nMemorizing formulas can become time consuming and can also take up a lot of your brain power.\r\n\r\nThe problem that occurs when students memorize formulas is they often forget what the formula represents. Students get really good at plugging numbers into formulas but they don't really understand what the formula does.\r\n\r\nIf the numbers were to change or the question was asked in a different manner than normal the student might become lost.\r\n\r\nYou might want to think about the following. Every time you get a formula, instead of memorizing that formula try to VISUALIZE that formula. What I mean by that is visualize what the formula represents. Hopefully it will become easier for you to work with the formula and easier for your brain to recall the formula when needed.\r\n\r\n<img class=\"aligncenter wp-image-136 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-9-2.png\" alt=\"\" width=\"75%\" \/>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n<img class=\"alignright wp-image-137\" style=\"font-size: 16.8px; orphans: 1;\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-10-1.png\" alt=\"\" width=\"150\" height=\"180\" \/>Find the perimeter of a square which has a side measuring 8 inches.\r\n\r\n<strong>Step 1: <\/strong>Write down the formula.\r\n<p style=\"text-align: center;\">[latex]\\Large \\text{Perimeter}= \\text{ side} + \\text{ side} + \\text{ side} + \\text{ side}[\/latex]<\/p>\r\n<strong>Step 2:<\/strong> Solve for perimeter.\r\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\text{Perimeter}=8+8+8+8 \\\\ \\text{Perimeter} = 32 \\text{ inches} \\end{array}[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nFind the perimeter of a rectangle if the length is 12 and the width is 7.<img class=\"aligncenter wp-image-138\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-11-1.png\" alt=\"\" width=\"300\" height=\"152\" \/>\r\n\r\n<strong>Step 1: <\/strong>Write down the formula\r\n<p style=\"text-align: center;\">[latex]\\Large \\text{Perimeter} = (\\text{length}\\times 2) + (\\text{width} \\times 2) [\/latex]<\/p>\r\n<strong>Step 2:<\/strong> Solve for perimeter\r\n<h2 style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\text{Perimeter} = (7 \\times 2)+(12 \\times 2) \\\\ \\text{Perimeter} = 14 + 24 \\\\ \\text{Perimeter} =38 \\end{array}[\/latex]<\/h2>\r\n<\/div>\r\n<\/div>\r\n<h1>The Perimeter of a Polygon<\/h1>\r\n<img class=\"alignleft wp-image-99\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2020\/06\/help-147419_1280-300x300.png\" alt=\"\" width=\"100\" height=\"100\" \/>\r\n\r\nFirst of all, what is a polygon? Ever heard of one?\r\n\r\n<strong>Definition: <\/strong>\r\n\r\nA polygon is a plane figure (plane refers to it being two dimensional) with at least 3 sides and those sides must be straight.\r\n\r\nWe\u2019ve actually already worked with polygons in this chapter. By the definition both a square and a rectangle are polygons. By definition a circle is not a polygon due to the fact that it doesn\u2019t have straight lines.\r\n\r\nThe following are some examples of polygons\u2026\r\n\r\n<img class=\"aligncenter wp-image-139 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-12-2.png\" alt=\"Drawings of polygons.\" width=\"521\" height=\"239\" \/>\r\n\r\nEach of the shapes is different but all have straight lines.\r\n\r\nThe question becomes:\u00a0 Are we going to need a different formula to calculate the perimeter of each of the shapes?\r\n\r\nThe answer:\u00a0 \u00a0 <b>NO<\/b>\r\n\r\nSo if a polygon is made up of sides, all of which are straight lines, how do you think we would calculate the perimeter?\r\n\r\nFinding the perimeter of a polygon can be done by adding up all the sides of that polygon. And if fact we could make a generic formula for this.\r\n\r\n<strong>Formula:\u00a0\u00a0\u00a0 <\/strong>\r\n<p style=\"text-align: center;\">[latex]\\Large \\text{Perimeter of a polygon} = \\text{side} + \\text{ side} + \\text{side and so on... }[\/latex]<\/p>\r\nWhat the formula is saying is just add up all the sides to get the perimeter.\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nCalculate the perimeter of the following polygon.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"300\"]<a href=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/1008\/2020\/06\/picture-13-1.png\"><img src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-13-1.png\" alt=\"\" width=\"300\" height=\"179\" \/><\/a> Click on the image to see it full size.[\/caption]\r\n\r\n<strong>Step 1: <\/strong>Write down the formula\r\n<p style=\"text-align: center;\">[latex] \\Large \\text{Perimeter of a polygon} = \\text{side} + \\text{ side} + \\text{side and so on... }[\/latex]<\/p>\r\n<strong>Step 2:<\/strong> Solve for perimeter\r\n<p style=\"text-align: center;\">[latex] \\Large \\begin{array}{c} \\text{Perimeter of a polygon}= 5+10+6+4+7+8 \\\\ \\text{Perimeter}=40\\end{array}[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nFind the perimeter of the following polygon.\r\n\r\n[caption id=\"attachment_468\" align=\"aligncenter\" width=\"300\"]<a class=\"internal\" href=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/1008\/2020\/06\/picture-14-2.png\"><img class=\"wp-image-141\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-14-2-300x228.png\" alt=\"a polygon with 6 sides. the length of each side is 10, 10, 13, 8, 8, 6.\" width=\"300\" height=\"228\" \/><\/a> Click on the image to see it full size.[\/caption]\r\n\r\n<strong>Step 1: <\/strong>Make sure to use the correct formula.\r\n<p style=\"text-align: center;\">[latex]\\large \\text{Perimeter of a polygon}= \\text{side} + \\text{ side} + \\text{ side} + \\text{side} + \\text{ side} + \\text{ side}[\/latex]<\/p>\r\n<strong>Step 2:<\/strong> Solve for perimeter\r\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c}\\text{Perimeter}=10+10+13+8+8+6 \\\\ \\text{Perimeter} = 55 \\end{array} [\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<h1>Practice Questions<\/h1>\r\nTry a couple practice questions for yourself. Make sure to check the video answers to see how you did.\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Question 1<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n<img class=\"alignleft wp-image-142\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/room-300x150.png\" alt=\"\" width=\"150\" height=\"75\" \/>\r\n<p class=\"cover4\" style=\"text-align: left;\" align=\"left\">Jacques is a carpet layer who is going to re - carpet a room. In order to do this he has to nail a small piece of wood to the ground which runs the entire perimeter of the room. This wood is there to attach the carpet at the edges of the room.<\/p>\r\n<p class=\"cover4\" style=\"text-align: left;\" align=\"left\">The room itself is in the shape of a rectangle with the length being 12 feet 2 inches and the width being 10 feet 1 inch.<\/p>\r\n<p class=\"cover4\" style=\"text-align: left;\" align=\"left\">How much wood does Jacques need?<\/p>\r\nhttps:\/\/media.bccampus.ca\/id\/0_0i789l8k?width=608&height=402&playerId=23449753\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Question 2<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nFred is a farmer who is a \"jack of all trades.\" Fred has to build a new fence around the farm that he owns. The area that he has to build the fence is neither a square or rectangle but has many straight sides and contains a large pond in it. Take a look at the picture below and calculate the total perimeter of the farm and pond where Fred had to construct the fence.\r\n\r\n[caption id=\"attachment_470\" align=\"aligncenter\" width=\"500\"]<a class=\"internal\" href=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/1008\/2020\/06\/picture-15-2.png\"><img class=\"wp-image-143\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-15-2.png\" alt=\"the fences is a polygon with 8 sides. the length of each side is 8352 feet, 5123 feet, 3888 feet, 4001 feet, 9234 feet, 12817 feet, 4021 feet, 3993 feet.\" width=\"500\" height=\"342\" \/><\/a> Click on the image to see it full size.[\/caption]\r\n\r\nhttps:\/\/media.bccampus.ca\/id\/0_3oqrx3ce?width=608&height=402&playerId=23449753\r\n\r\n<\/div>\r\n<\/div>\r\n<h1>Perimeter of a Circle<\/h1>\r\nTake a look at the circle below.\r\n\r\n<img class=\"alignleft wp-image-144\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture1-2-300x300.png\" alt=\"\" width=\"150\" height=\"150\" \/>\r\n\r\nNotice anything different between the circle and the square or rectangle?\r\n\r\n<strong>Answer:<\/strong> The circle doesn\u2019t have any straight lines. It\u2019s just one continuous line.\r\n\r\nWhat we are calculating when dealing with a circle is not referred to as the perimeter but as the circumference. Essentially the circumference is the perimeter of a circle.\r\n\r\nIn order to find the circumference we need to know a thing or two about the circle. We need to know either the diameter or the radius. Take a look at the next picture to see what the diameter and radius are.\r\n\r\n<img class=\"aligncenter wp-image-145\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture2-3.png\" alt=\"\" width=\"300\" height=\"182\" \/>\r\n\r\nIf you go to the exact center of a circle and then draw a straight line to the edge of the circle the distance measured is referred to as the radius.\r\n\r\nIf you start at any point on the edge of the circle and draw a straight line through the circle ending up on the other side, you have the diameter. Note that this straight line must go through the exact center of the circle.\r\n\r\nAs it turns out, the radius of a circle is exactly half the diameter or...\r\n<p style=\"text-align: center;\">[latex]\\Large \\text{radius} = \\dfrac{\\text{diameter}}{2}[\/latex]<\/p>\r\nWorking with the equation we could also state that...\r\n<p style=\"text-align: center;\">[latex]\\Large \\text{diameter} = \\text{radius} \\times 2 [\/latex]<\/p>\r\nNo matter which way you work it both equations represent the relationship between the radius and diameter.\r\n\r\nHaving gotten that out of the way we can look at the formula for finding the circumference of a circle. Before I go through the formula try and take a guess at what the formula is. Once again think about the relationship between the variables and how they might work together in the formula.\r\n\r\n<img class=\"aligncenter wp-image-146 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture20-e1611611814804.png\" alt=\"\" width=\"557\" height=\"157\" \/>\r\n\r\n<img class=\" aligncenter\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21.jpg\" width=\"300\" height=\"200\" \/>\r\n\r\n<strong>Formula:\u00a0\u00a0\u00a0<\/strong>\r\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\textbf{Circle} \\\\ \\text{Circumference} = \\pi \\times \\text{diameter} \\end{array}[\/latex]<\/p>\r\nWe could also write it as\u2026\r\n<p style=\"text-align: center;\">[latex]\\Large \\text{C} = \\pi \\times \\text{D} [\/latex]<\/p>\r\n<img class=\"wp-image-148 alignleft\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture24-300x200.jpg\" alt=\"\" width=\"150\" height=\"100\" \/>\r\n\r\n<strong>Hang on a minute!<\/strong>\r\n\r\nWhat is that symbol?\r\n\r\n<img class=\"aligncenter wp-image-149 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture25-2-e1611095771898.png\" alt=\"Pi symbol.\" width=\"150\" height=\"175\" \/>\r\n\r\nHave you ever seen or heard of this symbol before?\r\n\r\nWell it\u2019s a constant. It\u2019s referred to as \"pi,\" and if you were to sound it out, it would sound like \"pie.\"\r\n\r\n<img class=\" alignright\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/pi-e1620154944710.jpg\" width=\"150\" height=\"150\" \/>\r\n\r\nWhat \"pi\" represents is the relationship between the circumference of a circle and the diameter of that same circle. \"Pi\" is a constant and never changes.\r\n\r\nHaving said that, the number \"pi\" is a bit of an anomaly. You would think that a constant would be something like 7 or maybe 12.64 or maybe even 0.00004.\r\n\r\n\"Pi\" is a bit trickier than that. The following is the value of \"pi.\"\r\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\pi \\\\ = 3.141592653589793238462643383279 \\end{array}[\/latex]<\/p>\r\nAnd that\u2019s just the first few digits. The constant \"pi\" goes on forever. It doesn\u2019t actually stop. People have figured out \"pi\" to thousands of digits.\r\n\r\n<img class=\"wp-image-151 alignright\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture8-3-300x251.png\" alt=\"\" width=\"150\" height=\"126\" \/>\r\n\r\nThe good news for us is that we don\u2019t have to worry about all those digits that come after the decimal point. For our purpose we\u2019ll use just the following...\r\n<p style=\"text-align: center;\">[latex]\\Large \\pi = 3.14 [\/latex]<\/p>\r\n<img class=\"wp-image-47 alignleft\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-2-e1611097542522.png\" alt=\"\" width=\"100\" height=\"172\" \/>\r\n\r\n&nbsp;\r\n\r\nIf you want to find out more about the number \"pi\" and how far people have calculated it, check out the following websites: <a href=\"http:\/\/en.wikipedia.org\/wiki\/Pi\">Pi (Wikipedia)<\/a> and <a href=\"https:\/\/www.piday.org\/million\/\">1 Million Digits of Pi (piday)<\/a>.\r\n\r\n&nbsp;\r\n\r\n&nbsp;\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nFind the circumference of a circle given that its diameter is 24.\r\n\r\n<strong>Step 1: <\/strong>Write down the formula.\r\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\text{circumference} = \\pi \\times \\text{diameter} \\\\ \\text{OR} \\\\ \\text{C} = \\pi \\times \\text{D}\\end{array}[\/latex]<\/p>\r\n<strong>Step 2:<\/strong> Solve for circumference.\r\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\text{C} = \\pi \\times \\text{D} \\\\ \\text{C} = 3.14 \\times 24 \\\\ \\text{C} = 75.36 \\end{array}[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nFind the circumference of a circle given that its radius is 8.\r\n\r\n<strong>Step 1: <\/strong>Write down the formula.\r\n<p style=\"text-align: center;\">[latex]\\Large \\text{C} = \\pi \\times \\text{D}[\/latex]<\/p>\r\n\r\n<div class=\"textbox\">\r\n\r\n<img class=\"alignleft wp-image-62\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-15-e1611951062987.png\" alt=\"Note.\" width=\"80\" height=\"67\" \/>The formula calls for the diameter but we are given the radius. We have to use the relationship between radius and diameter to find the diameter.\r\n\r\n&nbsp;\r\n\r\n<\/div>\r\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\text{diameter} = \\text{radius} \\times 2 \\\\ \\text{diameter} = 8 \\times 2 \\\\ \\text{diameter} = 16 \\end{array}[\/latex]<\/p>\r\n<strong>Step 2:<\/strong> Solve for circumference.\r\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\text{C} = \\pi \\times \\text{D} \\\\ \\text{C} = 3.14 \\times 16 \\\\ \\text{C} = 50.24 \\end{array}[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<img class=\"alignleft wp-image-152\" style=\"font-size: 18.6667px; orphans: 1;\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture35-300x200.jpg\" alt=\"\" width=\"150\" height=\"100\" \/>\r\n\r\nWe\u2019re going to take the difficulty up a step here, and we\u2019ll need to use the rules of transposing in the last section to help us out.\r\n\r\n&nbsp;\r\n<div class=\"textbox textbox--examples\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Example<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\nFind the diameter of a circle given that the circumference is exactly 153.\r\n\r\n<strong>Step 1:<\/strong> Write down the formula.\r\n<p style=\"text-align: center;\">[latex]\\Large \\text{circumference} = \\pi \\times \\text{diameter} [\/latex]<\/p>\r\n<strong>Step 2:<\/strong> Rework the formula to solve for diameter.\r\n<p style=\"text-align: center;\">[latex]\\Large\\text{diameter}= \\dfrac{\\text{circumference}}{\\pi}[\/latex]<\/p>\r\n<strong>Step 3: <\/strong>Solve for diameter.\r\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\text{diameter}= \\dfrac{\\text{circumference}}{\\pi} \\\\ \\text{diameter} = \\dfrac{153}{3.14} \\\\ \\text{diameter} = 48.73 \\end{array}[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<h1>Practice Questions<\/h1>\r\nTry a couple practice questions for yourself. Make sure to check the video answers to see how you did. Note: Check out the \"SO WHAT\" video at the end of the practice questions before you head over to the next section.\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Question 1<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n<img class=\"alignleft wp-image-153\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture36-266x300.jpg\" alt=\"\" width=\"150\" height=\"169\" \/>\r\n\r\nHaley is a Red Seal welder and is fabricating stainless steel tanks for a food storage facility. The radius of the tanks is 24 inches. What is the circumference of the tanks going to be?\r\n\r\nhttps:\/\/media.bccampus.ca\/id\/0_3h8bvnym?width=608&height=402&playerId=23449753\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox textbox--exercises\"><header class=\"textbox__header\">\r\n<p class=\"textbox__title\">Question 2<\/p>\r\n\r\n<\/header>\r\n<div class=\"textbox__content\">\r\n\r\n<img class=\"alignleft wp-image-154\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture37-1-e1611097212354.png\" alt=\"\" width=\"150\" height=\"84\" \/>\r\n\r\nFloyd is a concrete worker who is building a foundation for a cabin. The cabin and wraparound deck are supported by round concrete footings. The radius of each footing has been engineered to be 4 inches. What is the circumference of the footings?\r\n\r\nhttps:\/\/media.bccampus.ca\/id\/0_ybxa1ejq?width=608&amp;height=402&amp;playerId=23449753\r\n\r\n<\/div>\r\n<\/div>","rendered":"<p>&nbsp;<\/p>\n<p><iframe loading=\"lazy\" id=\"kaltura_player\" title=\"Perimeter and Area\" src=\"https:\/\/api.ca.kaltura.com\/p\/148\/sp\/14800\/embedIframeJs\/uiconf_id\/23449753\/partner_id\/148?iframeembed=true&#38;playerId=kaltura_player&#38;entry_id=0_zcnd7r40&#38;flashvars[leadWithHTML5]=true&#38;flashvars[streamerType]=auto&#38;flashvars[localizationCode]=en&#38;flashvars[sideBarContainer.plugin]=true&#38;flashvars[sideBarContainer.position]=left&#38;flashvars[sideBarContainer.clickToClose]=true&#38;flashvars[chapters.plugin]=true&#38;flashvars[chapters.layout]=vertical&#38;flashvars[chapters.thumbnailRotator]=false&#38;flashvars[streamSelector.plugin]=true&#38;flashvars[EmbedPlayer.SpinnerTarget]=videoHolder&#38;flashvars[dualScreen.plugin]=true&#38;flashvars[Kaltura.addCrossoriginToIframe]=true&#38;wid=0_6xjl5xbb\" width=\"608\" height=\"402\" allowfullscreen=\"allowfullscreen\" sandbox=\"allow-downloads allow-forms allow-same-origin allow-scripts allow-top-navigation allow-pointer-lock allow-popups allow-modals allow-orientation-lock allow-popups-to-escape-sandbox allow-presentation allow-top-navigation-by-user-activation\" frameborder=\"0\"><\/iframe><\/p>\n<p>Click play on the following audio player to listen along as you read this section.<\/p>\n<p><iframe loading=\"lazy\" id=\"kaltura_player\" title=\"3.12 Perimeter\" src=\"https:\/\/api.ca.kaltura.com\/p\/148\/sp\/14800\/embedIframeJs\/uiconf_id\/23449753\/partner_id\/148?iframeembed=true&#38;playerId=kaltura_player&#38;entry_id=0_x6n0abu8&#38;flashvars[leadWithHTML5]=true&#38;flashvars[streamerType]=auto&#38;flashvars[localizationCode]=en&#38;flashvars[sideBarContainer.plugin]=true&#38;flashvars[sideBarContainer.position]=left&#38;flashvars[sideBarContainer.clickToClose]=true&#38;flashvars[chapters.plugin]=true&#38;flashvars[chapters.layout]=vertical&#38;flashvars[chapters.thumbnailRotator]=false&#38;flashvars[streamSelector.plugin]=true&#38;flashvars[EmbedPlayer.SpinnerTarget]=videoHolder&#38;flashvars[dualScreen.plugin]=true&#38;flashvars[Kaltura.addCrossoriginToIframe]=true&#38;wid=0_nlz5ceih\" width=\"608\" height=\"402\" allowfullscreen=\"allowfullscreen\" sandbox=\"allow-downloads allow-forms allow-same-origin allow-scripts allow-top-navigation allow-pointer-lock allow-popups allow-modals allow-orientation-lock allow-popups-to-escape-sandbox allow-presentation allow-top-navigation-by-user-activation\" frameborder=\"0\"><\/iframe><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignleft\" style=\"font-size: 18.6667px; orphans: 1;\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2020\/06\/a-baseball-field-e1620154751434.jpg\" alt=\"\" width=\"150\" height=\"150\" \/><\/p>\n<p>What does the word perimeter refer to? What if someone asked you to walk the perimeter of a baseball field? What does that mean?<\/p>\n<p><strong>Perimeter:<\/strong><strong><em>\u00a0<\/em><\/strong> A perimeter is a path that surrounds a two-dimensional object. The word comes from the Greek peri (around) and metre (measure). The term may be used either for the path or its length \u2013 it can be thought of as the length of an outline of a shape. The perimeter of a circle is called its circumference.<\/p>\n<p>If you were to walk the perimeter of a baseball field you would walk around the outer edges of the field and calculate the length. If you wanted to find the perimeter of anything it would basically be like walking around the outer edge of it. Obviously we can\u2019t do that for smaller shapes or objects but you get the idea.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-127 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-1-3.png\" alt=\"Stick figures walking around the outside of a square, circle, triange, and pentagon.\" width=\"1742\" height=\"373\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-1-3.png 1742w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-1-3-300x64.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-1-3-1024x219.png 1024w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-1-3-768x164.png 768w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-1-3-1536x329.png 1536w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-1-3-65x14.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-1-3-225x48.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-1-3-350x75.png 350w\" sizes=\"auto, (max-width: 1742px) 100vw, 1742px\" \/><\/p>\n<p>When calculating perimeter the answer will always be a linear (or one dimensional) measurement such as feet, inches, metres or centimetres.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignleft\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/interior-of-a-house-e1620154830828.png\" width=\"150\" height=\"150\" alt=\"image\" \/><\/p>\n<p>Why would perimeter be important to us in the construction world?<\/p>\n<p>Let\u2019s say you are a carpenter and you want to put baseboard in a room. Calculating how much baseboard you need around the walls involves calculating the perimeter of the room. This would also be true for plumbers if they are putting perimeter drain around a house. Perimeter can be used in many different areas of the construction world.<\/p>\n<h1>The Perimeter of a Square and a Rectangle<\/h1>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignleft wp-image-129\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture11-2.png\" alt=\"\" width=\"300\" height=\"177\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture11-2.png 757w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture11-2-300x177.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture11-2-65x38.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture11-2-225x133.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture11-2-350x207.png 350w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>A square and a rectangle are both similar in that they have four sides. Another characteristic that is common to both is each has four right angles. A right angle is an angle of 90 degrees.<\/p>\n<p>In a square, all four sides are equal while in a rectangle the opposite sides are equal but not the adjacent sides. Calculating the perimeter of a square and a rectangle is very similar. First we&#8217;ll define what each side is called.<\/p>\n<p><img decoding=\"async\" class=\"aligncenter wp-image-130 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-3-1.png\" alt=\"\" width=\"100%\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-3-1.png 995w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-3-1-300x86.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-3-1-768x220.png 768w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-3-1-65x19.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-3-1-225x64.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-3-1-350x100.png 350w\" sizes=\"(max-width: 995px) 100vw, 995px\" \/><\/p>\n<p>The square is straight forward as the length of each of the sides is the same, and the name of each side is simply &#8220;SIDE.&#8221; In a rectangle, the long side of the rectangle is referred to as the &#8220;LENGTH&#8221; while the shorter side is referred to as the &#8220;WIDTH.&#8221;<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignleft wp-image-131 size-thumbnail\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/lightbulb-150x150.jpg\" alt=\"\" width=\"150\" height=\"150\" \/><\/p>\n<p>Before I go through calculating perimeter of a square and rectangle, take a guess at what the formula might be.<\/p>\n<p><img decoding=\"async\" class=\"aligncenter wp-image-132 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1.png\" alt=\"\" width=\"100%\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1.png 1473w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1-300x36.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1-1024x122.png 1024w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1-768x91.png 768w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1-65x8.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1-225x27.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1-350x42.png 350w\" sizes=\"(max-width: 1473px) 100vw, 1473px\" \/><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-133\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-7-1-300x279.png\" alt=\"\" width=\"200\" height=\"186\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-7-1-300x279.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-7-1-65x60.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-7-1-225x209.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-7-1-350x325.png 350w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-7-1.png 709w\" sizes=\"auto, (max-width: 200px) 100vw, 200px\" \/><\/p>\n<p>If we go back to our definition and say that the perimeter is the length that surrounds a two dimensional object, then the perimeter of both would be the length of the four sides combined.<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{ll} \\textbf{Square:} & \\text{Perimeter}= \\text{ side}+ \\text{ side} + \\text{ side} + \\text{ side}\\\\ \\textbf{Rectangle:} & \\text{Perimeter} = \\text{length} + \\text{width} + \\text{width} + \\text{length}\\end{array}[\/latex]<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignleft wp-image-134\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/questionmark-e1611092707517.jpg\" alt=\"\" width=\"150\" height=\"122\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/questionmark-e1611092707517.jpg 1233w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/questionmark-e1611092707517-300x244.jpg 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/questionmark-e1611092707517-1024x833.jpg 1024w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/questionmark-e1611092707517-768x625.jpg 768w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/questionmark-e1611092707517-65x53.jpg 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/questionmark-e1611092707517-225x183.jpg 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/questionmark-e1611092707517-350x285.jpg 350w\" sizes=\"auto, (max-width: 150px) 100vw, 150px\" \/><\/p>\n<p>Would there be any other way to express the two formulas?<\/p>\n<p>Take a guess.<\/p>\n<p><img decoding=\"async\" class=\"aligncenter wp-image-132 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1.png\" alt=\"\" width=\"100%\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1.png 1473w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1-300x36.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1-1024x122.png 1024w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1-768x91.png 768w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1-65x8.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1-225x27.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21-1-350x42.png 350w\" sizes=\"(max-width: 1473px) 100vw, 1473px\" \/><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-133\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-7-1-300x279.png\" alt=\"\" width=\"200\" height=\"186\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-7-1-300x279.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-7-1-65x60.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-7-1-225x209.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-7-1-350x325.png 350w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-7-1.png 709w\" sizes=\"auto, (max-width: 200px) 100vw, 200px\" \/><\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{ll} \\textbf{Square:} & \\text{Perimeter}= \\text{ side} \\times 4 \\\\ \\textbf{Rectangle:} & \\text{Perimeter} = (\\text{length}\\times 2)+(\\text{width} \\times 2) \\end{array}[\/latex]<\/p>\n<p>Both versions of each formula are correct and you can use whichever you choose to answer questions.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignleft wp-image-135\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/memory-300x214.jpg\" alt=\"\" width=\"150\" height=\"107\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/memory-300x214.jpg 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/memory-1024x731.jpg 1024w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/memory-768x548.jpg 768w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/memory-1536x1097.jpg 1536w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/memory-65x46.jpg 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/memory-225x161.jpg 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/memory-350x250.jpg 350w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/memory.jpg 1920w\" sizes=\"auto, (max-width: 150px) 100vw, 150px\" \/><\/p>\n<p>This might be a good time to stop and discuss memorization.<\/p>\n<p>Memorization is a topic that comes up quite frequently in math. Students often ask if they have to memorize formulas and for the most part the answer is yes.<\/p>\n<p>Memorizing formulas can become time consuming and can also take up a lot of your brain power.<\/p>\n<p>The problem that occurs when students memorize formulas is they often forget what the formula represents. Students get really good at plugging numbers into formulas but they don&#8217;t really understand what the formula does.<\/p>\n<p>If the numbers were to change or the question was asked in a different manner than normal the student might become lost.<\/p>\n<p>You might want to think about the following. Every time you get a formula, instead of memorizing that formula try to VISUALIZE that formula. What I mean by that is visualize what the formula represents. Hopefully it will become easier for you to work with the formula and easier for your brain to recall the formula when needed.<\/p>\n<p><img decoding=\"async\" class=\"aligncenter wp-image-136 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-9-2.png\" alt=\"\" width=\"75%\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-9-2.png 1269w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-9-2-300x112.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-9-2-1024x381.png 1024w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-9-2-768x286.png 768w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-9-2-65x24.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-9-2-225x84.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-9-2-350x130.png 350w\" sizes=\"(max-width: 1269px) 100vw, 1269px\" \/><\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignright wp-image-137\" style=\"font-size: 16.8px; orphans: 1;\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-10-1.png\" alt=\"\" width=\"150\" height=\"180\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-10-1.png 303w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-10-1-250x300.png 250w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-10-1-65x78.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-10-1-225x270.png 225w\" sizes=\"auto, (max-width: 150px) 100vw, 150px\" \/>Find the perimeter of a square which has a side measuring 8 inches.<\/p>\n<p><strong>Step 1: <\/strong>Write down the formula.<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\text{Perimeter}= \\text{ side} + \\text{ side} + \\text{ side} + \\text{ side}[\/latex]<\/p>\n<p><strong>Step 2:<\/strong> Solve for perimeter.<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\text{Perimeter}=8+8+8+8 \\\\ \\text{Perimeter} = 32 \\text{ inches} \\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Find the perimeter of a rectangle if the length is 12 and the width is 7.<img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-138\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-11-1.png\" alt=\"\" width=\"300\" height=\"152\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-11-1.png 749w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-11-1-300x152.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-11-1-65x33.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-11-1-225x114.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-11-1-350x177.png 350w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/p>\n<p><strong>Step 1: <\/strong>Write down the formula<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\text{Perimeter} = (\\text{length}\\times 2) + (\\text{width} \\times 2)[\/latex]<\/p>\n<p><strong>Step 2:<\/strong> Solve for perimeter<\/p>\n<h2 style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\text{Perimeter} = (7 \\times 2)+(12 \\times 2) \\\\ \\text{Perimeter} = 14 + 24 \\\\ \\text{Perimeter} =38 \\end{array}[\/latex]<\/h2>\n<\/div>\n<\/div>\n<h1>The Perimeter of a Polygon<\/h1>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignleft wp-image-99\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2020\/06\/help-147419_1280-300x300.png\" alt=\"\" width=\"100\" height=\"100\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2020\/06\/help-147419_1280-300x300.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2020\/06\/help-147419_1280-1024x1024.png 1024w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2020\/06\/help-147419_1280-150x150.png 150w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2020\/06\/help-147419_1280-768x768.png 768w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2020\/06\/help-147419_1280-65x65.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2020\/06\/help-147419_1280-225x225.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2020\/06\/help-147419_1280-350x350.png 350w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2020\/06\/help-147419_1280.png 1280w\" sizes=\"auto, (max-width: 100px) 100vw, 100px\" \/><\/p>\n<p>First of all, what is a polygon? Ever heard of one?<\/p>\n<p><strong>Definition: <\/strong><\/p>\n<p>A polygon is a plane figure (plane refers to it being two dimensional) with at least 3 sides and those sides must be straight.<\/p>\n<p>We\u2019ve actually already worked with polygons in this chapter. By the definition both a square and a rectangle are polygons. By definition a circle is not a polygon due to the fact that it doesn\u2019t have straight lines.<\/p>\n<p>The following are some examples of polygons\u2026<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-139 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-12-2.png\" alt=\"Drawings of polygons.\" width=\"521\" height=\"239\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-12-2.png 521w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-12-2-300x138.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-12-2-65x30.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-12-2-225x103.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-12-2-350x161.png 350w\" sizes=\"auto, (max-width: 521px) 100vw, 521px\" \/><\/p>\n<p>Each of the shapes is different but all have straight lines.<\/p>\n<p>The question becomes:\u00a0 Are we going to need a different formula to calculate the perimeter of each of the shapes?<\/p>\n<p>The answer:\u00a0 \u00a0 <b>NO<\/b><\/p>\n<p>So if a polygon is made up of sides, all of which are straight lines, how do you think we would calculate the perimeter?<\/p>\n<p>Finding the perimeter of a polygon can be done by adding up all the sides of that polygon. And if fact we could make a generic formula for this.<\/p>\n<p><strong>Formula:\u00a0\u00a0\u00a0 <\/strong><\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\text{Perimeter of a polygon} = \\text{side} + \\text{ side} + \\text{side and so on... }[\/latex]<\/p>\n<p>What the formula is saying is just add up all the sides to get the perimeter.<\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Calculate the perimeter of the following polygon.<\/p>\n<figure style=\"width: 300px\" class=\"wp-caption aligncenter\"><a href=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/1008\/2020\/06\/picture-13-1.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-13-1.png\" alt=\"\" width=\"300\" height=\"179\" \/><\/a><figcaption class=\"wp-caption-text\">Click on the image to see it full size.<\/figcaption><\/figure>\n<p><strong>Step 1: <\/strong>Write down the formula<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\text{Perimeter of a polygon} = \\text{side} + \\text{ side} + \\text{side and so on... }[\/latex]<\/p>\n<p><strong>Step 2:<\/strong> Solve for perimeter<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\text{Perimeter of a polygon}= 5+10+6+4+7+8 \\\\ \\text{Perimeter}=40\\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Find the perimeter of the following polygon.<\/p>\n<figure id=\"attachment_468\" aria-describedby=\"caption-attachment-468\" style=\"width: 300px\" class=\"wp-caption aligncenter\"><a class=\"internal\" href=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/1008\/2020\/06\/picture-14-2.png\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-141\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-14-2-300x228.png\" alt=\"a polygon with 6 sides. the length of each side is 10, 10, 13, 8, 8, 6.\" width=\"300\" height=\"228\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-14-2-300x228.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-14-2-768x583.png 768w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-14-2-65x49.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-14-2-225x171.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-14-2-350x266.png 350w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-14-2.png 856w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a><figcaption id=\"caption-attachment-468\" class=\"wp-caption-text\">Click on the image to see it full size.<\/figcaption><\/figure>\n<p><strong>Step 1: <\/strong>Make sure to use the correct formula.<\/p>\n<p style=\"text-align: center;\">[latex]\\large \\text{Perimeter of a polygon}= \\text{side} + \\text{ side} + \\text{ side} + \\text{side} + \\text{ side} + \\text{ side}[\/latex]<\/p>\n<p><strong>Step 2:<\/strong> Solve for perimeter<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c}\\text{Perimeter}=10+10+13+8+8+6 \\\\ \\text{Perimeter} = 55 \\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<h1>Practice Questions<\/h1>\n<p>Try a couple practice questions for yourself. Make sure to check the video answers to see how you did.<\/p>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Question 1<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignleft wp-image-142\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/room-300x150.png\" alt=\"\" width=\"150\" height=\"75\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/room-300x150.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/room-1024x512.png 1024w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/room-768x384.png 768w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/room-65x33.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/room-225x113.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/room-350x175.png 350w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/room.png 1280w\" sizes=\"auto, (max-width: 150px) 100vw, 150px\" \/><\/p>\n<p class=\"cover4\" style=\"text-align: left; text-align: left;\">Jacques is a carpet layer who is going to re &#8211; carpet a room. In order to do this he has to nail a small piece of wood to the ground which runs the entire perimeter of the room. This wood is there to attach the carpet at the edges of the room.<\/p>\n<p class=\"cover4\" style=\"text-align: left; text-align: left;\">The room itself is in the shape of a rectangle with the length being 12 feet 2 inches and the width being 10 feet 1 inch.<\/p>\n<p class=\"cover4\" style=\"text-align: left; text-align: left;\">How much wood does Jacques need?<\/p>\n<p><iframe loading=\"lazy\" id=\"kaltura_player\" title=\"Perimeter #1\" src=\"https:\/\/api.ca.kaltura.com\/p\/148\/sp\/14800\/embedIframeJs\/uiconf_id\/23449753\/partner_id\/148?iframeembed=true&#38;playerId=kaltura_player&#38;entry_id=0_0i789l8k&#38;flashvars[leadWithHTML5]=true&#38;flashvars[streamerType]=auto&#38;flashvars[localizationCode]=en&#38;flashvars[sideBarContainer.plugin]=true&#38;flashvars[sideBarContainer.position]=left&#38;flashvars[sideBarContainer.clickToClose]=true&#38;flashvars[chapters.plugin]=true&#38;flashvars[chapters.layout]=vertical&#38;flashvars[chapters.thumbnailRotator]=false&#38;flashvars[streamSelector.plugin]=true&#38;flashvars[EmbedPlayer.SpinnerTarget]=videoHolder&#38;flashvars[dualScreen.plugin]=true&#38;flashvars[Kaltura.addCrossoriginToIframe]=true&#38;wid=0_12q8r5u6\" width=\"608\" height=\"402\" allowfullscreen=\"allowfullscreen\" sandbox=\"allow-downloads allow-forms allow-same-origin allow-scripts allow-top-navigation allow-pointer-lock allow-popups allow-modals allow-orientation-lock allow-popups-to-escape-sandbox allow-presentation allow-top-navigation-by-user-activation\" frameborder=\"0\"><\/iframe><\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Question 2<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Fred is a farmer who is a &#8220;jack of all trades.&#8221; Fred has to build a new fence around the farm that he owns. The area that he has to build the fence is neither a square or rectangle but has many straight sides and contains a large pond in it. Take a look at the picture below and calculate the total perimeter of the farm and pond where Fred had to construct the fence.<\/p>\n<figure id=\"attachment_470\" aria-describedby=\"caption-attachment-470\" style=\"width: 500px\" class=\"wp-caption aligncenter\"><a class=\"internal\" href=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/1008\/2020\/06\/picture-15-2.png\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-143\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-15-2.png\" alt=\"the fences is a polygon with 8 sides. the length of each side is 8352 feet, 5123 feet, 3888 feet, 4001 feet, 9234 feet, 12817 feet, 4021 feet, 3993 feet.\" width=\"500\" height=\"342\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-15-2.png 1131w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-15-2-300x205.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-15-2-1024x700.png 1024w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-15-2-768x525.png 768w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-15-2-65x44.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-15-2-225x154.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-15-2-350x239.png 350w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><\/a><figcaption id=\"caption-attachment-470\" class=\"wp-caption-text\">Click on the image to see it full size.<\/figcaption><\/figure>\n<p><iframe loading=\"lazy\" id=\"kaltura_player\" title=\"Perimeter #2\" src=\"https:\/\/api.ca.kaltura.com\/p\/148\/sp\/14800\/embedIframeJs\/uiconf_id\/23449753\/partner_id\/148?iframeembed=true&#38;playerId=kaltura_player&#38;entry_id=0_3oqrx3ce&#38;flashvars[leadWithHTML5]=true&#38;flashvars[streamerType]=auto&#38;flashvars[localizationCode]=en&#38;flashvars[sideBarContainer.plugin]=true&#38;flashvars[sideBarContainer.position]=left&#38;flashvars[sideBarContainer.clickToClose]=true&#38;flashvars[chapters.plugin]=true&#38;flashvars[chapters.layout]=vertical&#38;flashvars[chapters.thumbnailRotator]=false&#38;flashvars[streamSelector.plugin]=true&#38;flashvars[EmbedPlayer.SpinnerTarget]=videoHolder&#38;flashvars[dualScreen.plugin]=true&#38;flashvars[Kaltura.addCrossoriginToIframe]=true&#38;wid=0_ygtx9v7b\" width=\"608\" height=\"402\" allowfullscreen=\"allowfullscreen\" sandbox=\"allow-downloads allow-forms allow-same-origin allow-scripts allow-top-navigation allow-pointer-lock allow-popups allow-modals allow-orientation-lock allow-popups-to-escape-sandbox allow-presentation allow-top-navigation-by-user-activation\" frameborder=\"0\"><\/iframe><\/p>\n<\/div>\n<\/div>\n<h1>Perimeter of a Circle<\/h1>\n<p>Take a look at the circle below.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignleft wp-image-144\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture1-2-300x300.png\" alt=\"\" width=\"150\" height=\"150\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture1-2-300x300.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture1-2-150x150.png 150w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture1-2-65x65.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture1-2-225x225.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture1-2-350x349.png 350w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture1-2.png 611w\" sizes=\"auto, (max-width: 150px) 100vw, 150px\" \/><\/p>\n<p>Notice anything different between the circle and the square or rectangle?<\/p>\n<p><strong>Answer:<\/strong> The circle doesn\u2019t have any straight lines. It\u2019s just one continuous line.<\/p>\n<p>What we are calculating when dealing with a circle is not referred to as the perimeter but as the circumference. Essentially the circumference is the perimeter of a circle.<\/p>\n<p>In order to find the circumference we need to know a thing or two about the circle. We need to know either the diameter or the radius. Take a look at the next picture to see what the diameter and radius are.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-145\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture2-3.png\" alt=\"\" width=\"300\" height=\"182\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture2-3.png 587w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture2-3-300x182.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture2-3-65x39.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture2-3-225x136.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture2-3-350x212.png 350w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>If you go to the exact center of a circle and then draw a straight line to the edge of the circle the distance measured is referred to as the radius.<\/p>\n<p>If you start at any point on the edge of the circle and draw a straight line through the circle ending up on the other side, you have the diameter. Note that this straight line must go through the exact center of the circle.<\/p>\n<p>As it turns out, the radius of a circle is exactly half the diameter or&#8230;<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\text{radius} = \\dfrac{\\text{diameter}}{2}[\/latex]<\/p>\n<p>Working with the equation we could also state that&#8230;<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\text{diameter} = \\text{radius} \\times 2[\/latex]<\/p>\n<p>No matter which way you work it both equations represent the relationship between the radius and diameter.<\/p>\n<p>Having gotten that out of the way we can look at the formula for finding the circumference of a circle. Before I go through the formula try and take a guess at what the formula is. Once again think about the relationship between the variables and how they might work together in the formula.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-146 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture20-e1611611814804.png\" alt=\"\" width=\"557\" height=\"157\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture20-e1611611814804.png 557w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture20-e1611611814804-300x85.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture20-e1611611814804-65x18.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture20-e1611611814804-225x63.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture20-e1611611814804-350x99.png 350w\" sizes=\"auto, (max-width: 557px) 100vw, 557px\" \/><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture21.jpg\" width=\"300\" height=\"200\" alt=\"image\" \/><\/p>\n<p><strong>Formula:\u00a0\u00a0\u00a0<\/strong><\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\textbf{Circle} \\\\ \\text{Circumference} = \\pi \\times \\text{diameter} \\end{array}[\/latex]<\/p>\n<p>We could also write it as\u2026<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\text{C} = \\pi \\times \\text{D}[\/latex]<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-148 alignleft\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture24-300x200.jpg\" alt=\"\" width=\"150\" height=\"100\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture24-300x200.jpg 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture24-65x43.jpg 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture24-225x150.jpg 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture24-350x233.jpg 350w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture24.jpg 404w\" sizes=\"auto, (max-width: 150px) 100vw, 150px\" \/><\/p>\n<p><strong>Hang on a minute!<\/strong><\/p>\n<p>What is that symbol?<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-149 size-full\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture25-2-e1611095771898.png\" alt=\"Pi symbol.\" width=\"150\" height=\"175\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture25-2-e1611095771898.png 150w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture25-2-e1611095771898-65x76.png 65w\" sizes=\"auto, (max-width: 150px) 100vw, 150px\" \/><\/p>\n<p>Have you ever seen or heard of this symbol before?<\/p>\n<p>Well it\u2019s a constant. It\u2019s referred to as &#8220;pi,&#8221; and if you were to sound it out, it would sound like &#8220;pie.&#8221;<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignright\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/pi-e1620154944710.jpg\" width=\"150\" height=\"150\" alt=\"image\" \/><\/p>\n<p>What &#8220;pi&#8221; represents is the relationship between the circumference of a circle and the diameter of that same circle. &#8220;Pi&#8221; is a constant and never changes.<\/p>\n<p>Having said that, the number &#8220;pi&#8221; is a bit of an anomaly. You would think that a constant would be something like 7 or maybe 12.64 or maybe even 0.00004.<\/p>\n<p>&#8220;Pi&#8221; is a bit trickier than that. The following is the value of &#8220;pi.&#8221;<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\pi \\\\ = 3.141592653589793238462643383279 \\end{array}[\/latex]<\/p>\n<p>And that\u2019s just the first few digits. The constant &#8220;pi&#8221; goes on forever. It doesn\u2019t actually stop. People have figured out &#8220;pi&#8221; to thousands of digits.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-151 alignright\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture8-3-300x251.png\" alt=\"\" width=\"150\" height=\"126\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture8-3-300x251.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture8-3-65x54.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture8-3-225x188.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture8-3-350x293.png 350w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/Picture8-3.png 474w\" sizes=\"auto, (max-width: 150px) 100vw, 150px\" \/><\/p>\n<p>The good news for us is that we don\u2019t have to worry about all those digits that come after the decimal point. For our purpose we\u2019ll use just the following&#8230;<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\pi = 3.14[\/latex]<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-47 alignleft\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-2-e1611097542522.png\" alt=\"\" width=\"100\" height=\"172\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-2-e1611097542522.png 127w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-2-e1611097542522-65x112.png 65w\" sizes=\"auto, (max-width: 100px) 100vw, 100px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>If you want to find out more about the number &#8220;pi&#8221; and how far people have calculated it, check out the following websites: <a href=\"http:\/\/en.wikipedia.org\/wiki\/Pi\">Pi (Wikipedia)<\/a> and <a href=\"https:\/\/www.piday.org\/million\/\">1 Million Digits of Pi (piday)<\/a>.<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Find the circumference of a circle given that its diameter is 24.<\/p>\n<p><strong>Step 1: <\/strong>Write down the formula.<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\text{circumference} = \\pi \\times \\text{diameter} \\\\ \\text{OR} \\\\ \\text{C} = \\pi \\times \\text{D}\\end{array}[\/latex]<\/p>\n<p><strong>Step 2:<\/strong> Solve for circumference.<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\text{C} = \\pi \\times \\text{D} \\\\ \\text{C} = 3.14 \\times 24 \\\\ \\text{C} = 75.36 \\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Find the circumference of a circle given that its radius is 8.<\/p>\n<p><strong>Step 1: <\/strong>Write down the formula.<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\text{C} = \\pi \\times \\text{D}[\/latex]<\/p>\n<div class=\"textbox\">\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignleft wp-image-62\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-15-e1611951062987.png\" alt=\"Note.\" width=\"80\" height=\"67\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-15-e1611951062987.png 120w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture-15-e1611951062987-65x54.png 65w\" sizes=\"auto, (max-width: 80px) 100vw, 80px\" \/>The formula calls for the diameter but we are given the radius. We have to use the relationship between radius and diameter to find the diameter.<\/p>\n<p>&nbsp;<\/p>\n<\/div>\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\text{diameter} = \\text{radius} \\times 2 \\\\ \\text{diameter} = 8 \\times 2 \\\\ \\text{diameter} = 16 \\end{array}[\/latex]<\/p>\n<p><strong>Step 2:<\/strong> Solve for circumference.<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\text{C} = \\pi \\times \\text{D} \\\\ \\text{C} = 3.14 \\times 16 \\\\ \\text{C} = 50.24 \\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignleft wp-image-152\" style=\"font-size: 18.6667px; orphans: 1;\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture35-300x200.jpg\" alt=\"\" width=\"150\" height=\"100\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture35-300x200.jpg 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture35-65x43.jpg 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture35-225x150.jpg 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture35-350x233.jpg 350w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture35.jpg 372w\" sizes=\"auto, (max-width: 150px) 100vw, 150px\" \/><\/p>\n<p>We\u2019re going to take the difficulty up a step here, and we\u2019ll need to use the rules of transposing in the last section to help us out.<\/p>\n<p>&nbsp;<\/p>\n<div class=\"textbox textbox--examples\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Example<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p>Find the diameter of a circle given that the circumference is exactly 153.<\/p>\n<p><strong>Step 1:<\/strong> Write down the formula.<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\text{circumference} = \\pi \\times \\text{diameter}[\/latex]<\/p>\n<p><strong>Step 2:<\/strong> Rework the formula to solve for diameter.<\/p>\n<p style=\"text-align: center;\">[latex]\\Large\\text{diameter}= \\dfrac{\\text{circumference}}{\\pi}[\/latex]<\/p>\n<p><strong>Step 3: <\/strong>Solve for diameter.<\/p>\n<p style=\"text-align: center;\">[latex]\\Large \\begin{array}{c} \\text{diameter}= \\dfrac{\\text{circumference}}{\\pi} \\\\ \\text{diameter} = \\dfrac{153}{3.14} \\\\ \\text{diameter} = 48.73 \\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<h1>Practice Questions<\/h1>\n<p>Try a couple practice questions for yourself. Make sure to check the video answers to see how you did. Note: Check out the &#8220;SO WHAT&#8221; video at the end of the practice questions before you head over to the next section.<\/p>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Question 1<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignleft wp-image-153\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture36-266x300.jpg\" alt=\"\" width=\"150\" height=\"169\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture36-266x300.jpg 266w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture36-65x73.jpg 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture36-225x253.jpg 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture36.jpg 325w\" sizes=\"auto, (max-width: 150px) 100vw, 150px\" \/><\/p>\n<p>Haley is a Red Seal welder and is fabricating stainless steel tanks for a food storage facility. The radius of the tanks is 24 inches. What is the circumference of the tanks going to be?<\/p>\n<p><iframe loading=\"lazy\" id=\"kaltura_player\" title=\"Perimeter of a Circle #1\" src=\"https:\/\/api.ca.kaltura.com\/p\/148\/sp\/14800\/embedIframeJs\/uiconf_id\/23449753\/partner_id\/148?iframeembed=true&#38;playerId=kaltura_player&#38;entry_id=0_3h8bvnym&#38;flashvars[leadWithHTML5]=true&#38;flashvars[streamerType]=auto&#38;flashvars[localizationCode]=en&#38;flashvars[sideBarContainer.plugin]=true&#38;flashvars[sideBarContainer.position]=left&#38;flashvars[sideBarContainer.clickToClose]=true&#38;flashvars[chapters.plugin]=true&#38;flashvars[chapters.layout]=vertical&#38;flashvars[chapters.thumbnailRotator]=false&#38;flashvars[streamSelector.plugin]=true&#38;flashvars[EmbedPlayer.SpinnerTarget]=videoHolder&#38;flashvars[dualScreen.plugin]=true&#38;flashvars[Kaltura.addCrossoriginToIframe]=true&#38;wid=0_e61cirto\" width=\"608\" height=\"402\" allowfullscreen=\"allowfullscreen\" sandbox=\"allow-downloads allow-forms allow-same-origin allow-scripts allow-top-navigation allow-pointer-lock allow-popups allow-modals allow-orientation-lock allow-popups-to-escape-sandbox allow-presentation allow-top-navigation-by-user-activation\" frameborder=\"0\"><\/iframe><\/p>\n<\/div>\n<\/div>\n<div class=\"textbox textbox--exercises\">\n<header class=\"textbox__header\">\n<p class=\"textbox__title\">Question 2<\/p>\n<\/header>\n<div class=\"textbox__content\">\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignleft wp-image-154\" src=\"https:\/\/opentextbc.ca\/oerdiscipline\/wp-content\/uploads\/sites\/347\/2021\/05\/picture37-1-e1611097212354.png\" alt=\"\" width=\"150\" height=\"84\" srcset=\"https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture37-1-e1611097212354.png 517w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture37-1-e1611097212354-300x168.png 300w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture37-1-e1611097212354-65x36.png 65w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture37-1-e1611097212354-225x126.png 225w, https:\/\/opentextbc.ca\/mathfortrades2\/wp-content\/uploads\/sites\/347\/2021\/05\/picture37-1-e1611097212354-350x196.png 350w\" sizes=\"auto, (max-width: 150px) 100vw, 150px\" \/><\/p>\n<p>Floyd is a concrete worker who is building a foundation for a cabin. The cabin and wraparound deck are supported by round concrete footings. The radius of each footing has been engineered to be 4 inches. What is the circumference of the footings?<\/p>\n<p><iframe loading=\"lazy\" id=\"kaltura_player\" title=\"Perimeter of a Circle #2\" src=\"https:\/\/api.ca.kaltura.com\/p\/148\/sp\/14800\/embedIframeJs\/uiconf_id\/23449753\/partner_id\/148?iframeembed=true&#38;playerId=kaltura_player&#38;entry_id=0_ybxa1ejq&#38;flashvars[leadWithHTML5]=true&#38;flashvars[streamerType]=auto&#38;flashvars[localizationCode]=en&#38;flashvars[sideBarContainer.plugin]=true&#38;flashvars[sideBarContainer.position]=left&#38;flashvars[sideBarContainer.clickToClose]=true&#38;flashvars[chapters.plugin]=true&#38;flashvars[chapters.layout]=vertical&#38;flashvars[chapters.thumbnailRotator]=false&#38;flashvars[streamSelector.plugin]=true&#38;flashvars[EmbedPlayer.SpinnerTarget]=videoHolder&#38;flashvars[dualScreen.plugin]=true&#38;flashvars[Kaltura.addCrossoriginToIframe]=true&#38;wid=0_qzzxr23q\" width=\"608\" height=\"402\" allowfullscreen=\"allowfullscreen\" sandbox=\"allow-downloads allow-forms allow-same-origin allow-scripts allow-top-navigation allow-pointer-lock allow-popups allow-modals allow-orientation-lock allow-popups-to-escape-sandbox allow-presentation allow-top-navigation-by-user-activation\" frameborder=\"0\"><\/iframe><\/p>\n<\/div>\n<\/div>\n","protected":false},"author":125,"menu_order":1,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-155","chapter","type-chapter","status-publish","hentry"],"part":125,"_links":{"self":[{"href":"https:\/\/opentextbc.ca\/mathfortrades2\/wp-json\/pressbooks\/v2\/chapters\/155","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/opentextbc.ca\/mathfortrades2\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/opentextbc.ca\/mathfortrades2\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/opentextbc.ca\/mathfortrades2\/wp-json\/wp\/v2\/users\/125"}],"version-history":[{"count":2,"href":"https:\/\/opentextbc.ca\/mathfortrades2\/wp-json\/pressbooks\/v2\/chapters\/155\/revisions"}],"predecessor-version":[{"id":314,"href":"https:\/\/opentextbc.ca\/mathfortrades2\/wp-json\/pressbooks\/v2\/chapters\/155\/revisions\/314"}],"part":[{"href":"https:\/\/opentextbc.ca\/mathfortrades2\/wp-json\/pressbooks\/v2\/parts\/125"}],"metadata":[{"href":"https:\/\/opentextbc.ca\/mathfortrades2\/wp-json\/pressbooks\/v2\/chapters\/155\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/opentextbc.ca\/mathfortrades2\/wp-json\/wp\/v2\/media?parent=155"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/opentextbc.ca\/mathfortrades2\/wp-json\/pressbooks\/v2\/chapter-type?post=155"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/opentextbc.ca\/mathfortrades2\/wp-json\/wp\/v2\/contributor?post=155"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/opentextbc.ca\/mathfortrades2\/wp-json\/wp\/v2\/license?post=155"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}