Answer Key 2.8

\begin{array}{ll} \begin{array}{cccc} \text{1st}&&& \\ &&5& \\ \\ &&31& \\ \\ &3&&6 \end{array} & \hspace{0.5in} \Longrightarrow \hspace{0.5in} \begin{array}{rrl} 3\cdot 5 + 6&& \\ 15+6&=&21 \end{array} \end{array}

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\begin{array}{ll} \begin{array}{cccc} \text{2nd}&&& \\ &&3& \\ \\ &&42& \\ \\ &11&&9 \end{array} & \hspace{0.5in} \Longrightarrow \hspace{0.5in} \begin{array}{rrl} 3\cdot 11 + 9&& \\ 33+9&=&42 \end{array} \end{array}

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\begin{array}{ll} \begin{array}{cccc} \text{3rd}&&& \\ &&12& \\ \\ &&64& \\ \\ &5&&X \end{array} & \hspace{0.5in} \Longrightarrow \hspace{0.5in} \begin{array}{rrrrl} 5\cdot 12&+&x&=&\phantom{-}64 \\ 60&+&x&=&\phantom{-}64 \\ -60&&&&-60 \\ \midrule &&x&=&4 \end{array} \end{array}

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Intermediate Algebra by Terrance Berg is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.

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