Midterm 2: Version B Answer Key

  1. x+y=5
    x y
    5 0
    0 5
    3 2
    2x-y=1
    x y
    1 1
    0 −1
    −1 −3

    Graph with lines intersecting at (2,3)

  2. \begin{array}{ll} \begin{array}{rrrrrrr} \\ \\ \\ \\ 4(4y&+&2)&+&3y&=&8 \\ 16y&+&8&+&3y&=&8 \\ &-&8&&&&-8 \\ \midrule &&&&19y&=&0 \\ &&&&y&=&0 \end{array} & \hspace{0.25in} \begin{array}{rrrrr} \\ \\ x&=&4y&+&2 \\ x&=&\cancel{4y}0&+&2 \\ x&=&2&& \end{array} \end{array}
    (2,0)
  3. \begin{array}{rrrrrl} \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ &5x&-&3y&=&2 \\ &(3x&+&y&=&4)(3) \\ \\ &5x&-&3y&=&\phantom{1}2 \\ +&9x&+&3y&=&12 \\ \midrule &&&14x&=&14 \\ &&&x&=&1 \\ \\ &\therefore 3(1)&+&y&=&4 \\ &3&+&y&=&4 \\ &&&y&=&1 \end{array}
  4. \begin{array}{ll} \begin{array}{rrrrrrrl} \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ &&&(x&-&2z&=&-7)(-1) \\ \\ &x&+&y&+&z&=&3 \\ +&-x&&&+&2z&=&7 \\ \midrule &&&y&+&3z&=&10 \\ &&&(-2y&+&4z&=&20)(\div 2) \\ &&&&&\Downarrow&& \\ &&&y&+&3z&=&10 \\ &&+&-y&+&2z&=&10 \\ \midrule &&&&&5z&=&20 \\ &&&&&z&=&4 \\ \end{array} & \hspace{0.25in} \begin{array}{rrrrr} \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ x&-&2z&=&-7 \\ x&-&2(4)&=&-7 \\ x&-&8&=&-7 \\ &+&8&&+8 \\ \midrule &&x&=&1 \\ \\ y&+&3z&=&10 \\ y&+&3(4)&=&10 \\ y&+&12&=&10 \\ &-&12&&-12 \\ \midrule &&y&=&-2 \\ \end{array} \end{array}
    (1,-2,4)
  5. 5-3\left[4x-2\cancel{(6x-5)^0}1-(7-2x)\right]
    5-3\left[4x-2(1)-(7-2x)\right]
    5-3\left[6x-9\right]
    5-18x+27\Rightarrow -18x+32
  6. \begin{array}{rrrlrl} \\ \\ \\ \\ \\ \\ \\ &a&+&3&& \\ \times &a&+&3&& \\ \midrule &a^2&+&3a&& \\ +&&&3a&+&9 \\ \midrule &a^2&+&6a&+&9 \\ \times&&&&&3a^2 \\ \midrule &3a^4&+&18a^3&+&27a^2 \end{array}
  7. \begin{array}{rrrlrrrrrr} \\ \\ \\ \\ \\ \\ &x^2&+&x&+&5\phantom{x^2}&&&& \\ \times&x^2&+&x&-&5\phantom{x^2}&&&& \\ \midrule &x^4&+&x^3&+&5x^2&&&& \\ &&&x^3&+&x^2&+&5x&& \\ +&&&&&-5x^2&-&5x&-&25 \\ \midrule &x^4&+&2x^3&+&x^2&-&25&& \end{array}
  8. (x^{4n-3n}x^{-6})^{-1}
    (x^nx^{-6})^{-1}
    x^{-n}x^6\text{ or }\dfrac{x^6}{x^n}
  9. 2a(7xy-3z)-1(7xy-3z)
    (7xy-3z)(2a-1)
  10. a^2-3ab+5ab-15b^2
    a(a-3b)+5b(a-3b)
    (a-3b)(a+5b)
  11. 2x^2(x+4)-1(x+4)
    (x+4)(2x^2-1)
  12. (3x)^3+(2y)^3
    (3x+2y)(9x^2-6xy+4y^2)
  13. \phantom{1}
    F+D=38\Rightarrow F=38-D \\
    \begin{array}{rrrrrrr} (F&+&6)&=&4(D&+&6) \\ 38-D&+&6\phantom{)}&=&4D&+&24 \\ -24+D&&&&+D&-&24 \\ \midrule &&20&=&5D&& \\ \\ &&D&=&\dfrac{20}{5}&=&4 \\ \\ &&\therefore F&=&38&-&D \\ &&F&=&38&-&4 \\ &&F&=&34&& \end{array}
  14. \phantom{1}
    A+B=90\Rightarrow B=90-A \\
    \begin{array}{rrrrrrl} 3A&+&5(90&-&A)&=&\phantom{-}370 \\ 3A&+&450&-&5A&=&\phantom{-}370 \\ &-&450&&&&-450 \\ \midrule &&&&-2A&=&-80 \\ \\ &&&&A&=&\dfrac{-80}{-2}\text{ or }40\text{ kg} \\ \\ &&&&\therefore B&=&90-A \\ &&&&B&=&90-40 \\ &&&&B&=&50\text{ kg} \end{array}
  15. \begin{array}{rrrrrrr} \\ \\ \\ \\ \\ \\ \\ 10x&+&25(40)&=&15(x&+&40) \\ \\ 10x&+&1000&=&15x&+&600 \\ -10x&-&600&&-10x&-&600 \\ \midrule &&400&=&5x&& \\ \\ &&x&=&\dfrac{400}{5}&=&80 \end{array}

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Intermediate Algebra by Terrance Berg is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.

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