Answer Key 3.2

  1. \begin{array}{lllll} \\ \\ \\ \\ \\ \\ d^2&=&\Delta x^2&+&\Delta y^2 \\ d^2&=&(6--6)^2&+&(4--1)^2 \\ d^2&=&12^2&+&5^2 \\ d^2&=&144&+&25 \\ d^2&=&169&& \\ d^2&=&\sqrt{169}&& \\ d&=&13&& \end{array}
  2. \begin{array}{lllll} \\ \\ \\ \\ \\ \\ d^2&=&\Delta x^2&+&\Delta y^2 \\ d^2&=&(5-1)^2&+&(-1--4)^2 \\ d^2&=&4^2&+&3^2 \\ d^2&=&16&+&9 \\ d^2&=&25&& \\ d^2&=&\sqrt{25}&& \\ d&=&5&& \end{array}
  3. \begin{array}{lllll} \\ \\ \\ \\ \\ \\ d^2&=&\Delta x^2&+&\Delta y^2 \\ d^2&=&(3--5)^2&+&(5--1)^2 \\ d^2&=&8^2&+&6^2 \\ d^2&=&64&+&36 \\ d^2&=&100&& \\ d^2&=&\sqrt{100}&& \\ d&=&10&& \end{array}
  4. \begin{array}{lllll} \\ \\ \\ \\ \\ \\ d^2&=&\Delta x^2&+&\Delta y^2 \\ d^2&=&(12-6)^2&+&(4--4)^2 \\ d^2&=&6^2&+&8^2 \\ d^2&=&36&+&64 \\ d^2&=&100&& \\ d^2&=&\sqrt{100}&& \\ d&=&10&& \end{array}
  5. \begin{array}{lllll} \\ \\ \\ \\ \\ \\ d^2&=&\Delta x^2&+&\Delta y^2 \\ d^2&=&(4--8)^2&+&(3--2)^2 \\ d^2&=&12^2&+&5^2 \\ d^2&=&144&+&25 \\ d^2&=&169&& \\ d^2&=&\sqrt{169}&& \\ d&=&13&& \end{array}
  6. \begin{array}{lllll} \\ \\ \\ \\ \\ \\ d^2&=&\Delta x^2&+&\Delta y^2 \\ d^2&=&(7-3)^2&+&(1--2)^2 \\ d^2&=&4^2&+&3^2 \\ d^2&=&16&+&9 \\ d^2&=&25&& \\ d^2&=&\sqrt{25}&& \\ d&=&5&& \end{array}
  7. \begin{array}{lllll} \\ \\ \\ \\ \\ \\ d^2&=&\Delta x^2&+&\Delta y^2 \\ d^2&=&(-2--10)^2&+&(0--6)^2 \\ d^2&=&8^2&+&6^2 \\ d^2&=&64&+&36 \\ d^2&=&100&& \\ d^2&=&\sqrt{100}&& \\ d&=&10&& \end{array}
  8. \begin{array}{lllll} \\ \\ \\ \\ \\ \\ d^2&=&\Delta x^2&+&\Delta y^2 \\ d^2&=&(14-8)^2&+&(6--2)^2 \\ d^2&=&6^2&+&8^2 \\ d^2&=&36&+&64 \\ d^2&=&100&& \\ d^2&=&\sqrt{100}&& \\ d&=&10&& \end{array}
  9. \left(\dfrac{6+-6}{2}, \dfrac{5+-1}{2}\right)\Rightarrow \left(\dfrac{0}{2}, \dfrac{4}{2}\right) \Rightarrow (0,2)
  10. \left(\dfrac{5+1}{2}, \dfrac{-2+-4}{2}\right)\Rightarrow \left(\dfrac{6}{2}, \dfrac{-6}{2}\right)\Rightarrow (3,-3)
  11. \left(\dfrac{3+-5}{2}, \dfrac{5+-1}{2}\right)\Rightarrow \left(\dfrac{-2}{2}, \dfrac{4}{2}\right)\Rightarrow (-1,2)
  12. \left(\dfrac{12+6}{2}, \dfrac{4+-4}{2}\right)\Rightarrow \left(\dfrac{18}{2}, \dfrac{0}{2}\right) \Rightarrow (9,0)
  13. \left(\dfrac{-8+6}{2}, \dfrac{-1+7}{2}\right)\Rightarrow \left(\dfrac{-2}{2}, \dfrac{6}{2}\right) \Rightarrow (-1,3)
  14. \left(\dfrac{1+3}{2}, \dfrac{-6+-2}{2}\right)\Rightarrow \left(\dfrac{4}{2}, \dfrac{-8}{2}\right) \Rightarrow (2,-4)
  15. \left(\dfrac{-7+3}{2}, \dfrac{-1+9}{2}\right)\Rightarrow \left(\dfrac{-4}{2}, \dfrac{8}{2}\right) \Rightarrow (-2,4)
  16. \left(\dfrac{2+12}{2}, \dfrac{-2+4}{2}\right)\Rightarrow \left(\dfrac{14}{2}, \dfrac{2}{2}\right) \Rightarrow (7,1)

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Intermediate Algebra by Terrance Berg is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.

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