Answer Key 3.2

Terrance Berg

Answer Key 3.2

$d^{2} = Δ x^{2} + Δ y^{2}$
$\begin{array}{lllll} d^{2} & = & (6 - - 6)^{2} & + & (4 - - 1)^{2} \\ d^{2} & = & 12^{2} & + & 5^{2} \\ d^{2} & = & 144 & + & 25 \\ d^{2} & = & 169 \\ d^{2} & = & \sqrt{169} \\ d & = & 13 \end{array}$
$d^{2} = Δ x^{2} + Δ y^{2}$
$\begin{array}{lllll} d^{2} & = & (5 - 1)^{2} & + & (- 1 - - 4)^{2} \\ d^{2} & = & 4^{2} & + & 3^{2} \\ d^{2} & = & 16 & + & 9 \\ d^{2} & = & 25 \\ d^{2} & = & \sqrt{25} \\ d & = & 5 \end{array}$
$d^{2} = Δ x^{2} + Δ y^{2}$
$\begin{array}{lllll} d^{2} & = & (3 - - 5)^{2} & + & (5 - - 1)^{2} \\ d^{2} & = & 8^{2} & + & 6^{2} \\ d^{2} & = & 64 & + & 36 \\ d^{2} & = & 100 \\ d^{2} & = & \sqrt{100} \\ d & = & 10 \end{array}$
$d^{2} = Δ x^{2} + Δ y^{2}$
$\begin{array}{lllll} d^{2} & = & (12 - 6)^{2} & + & (4 - - 4)^{2} \\ d^{2} & = & 6^{2} & + & 8^{2} \\ d^{2} & = & 36 & + & 64 \\ d^{2} & = & 100 \\ d^{2} & = & \sqrt{100} \\ d & = & 10 \end{array}$
$d^{2} = Δ x^{2} + Δ y^{2}$
$\begin{array}{lllll} d^{2} & = & (4 - - 8)^{2} & + & (3 - - 2)^{2} \\ d^{2} & = & 12^{2} & + & 5^{2} \\ d^{2} & = & 144 & + & 25 \\ d^{2} & = & 169 \\ d^{2} & = & \sqrt{169} \\ d & = & 13 \end{array}$
$d^{2} = Δ x^{2} + Δ y^{2}$
$\begin{array}{lllll} d^{2} & = & (7 - 3)^{2} & + & (1 - - 2)^{2} \\ d^{2} & = & 4^{2} & + & 3^{2} \\ d^{2} & = & 16 & + & 9 \\ d^{2} & = & 25 \\ d^{2} & = & \sqrt{25} \\ d & = & 5 \end{array}$
$d^{2} = Δ x^{2} + Δ y^{2}$
$\begin{array}{lllll} d^{2} & = & (- 2 - - 10)^{2} & + & (0 - - 6)^{2} \\ d^{2} & = & 8^{2} & + & 6^{2} \\ d^{2} & = & 64 & + & 36 \\ d^{2} & = & 100 \\ d^{2} & = & \sqrt{100} \\ d & = & 10 \end{array}$
$d^{2} = Δ x^{2} + Δ y^{2}$
$\begin{array}{lllll} d^{2} & = & (14 - 8)^{2} & + & (6 - - 2)^{2} \\ d^{2} & = & 6^{2} & + & 8^{2} \\ d^{2} & = & 36 & + & 64 \\ d^{2} & = & 100 \\ d^{2} & = & \sqrt{100} \\ d & = & 10 \end{array}$
$(\frac{6 + - 6}{2}, \frac{5 + - 1}{2}) \Rightarrow (\frac{0}{2}, \frac{4}{2}) \Rightarrow (0, 2)$
$(\frac{5 + 1}{2}, \frac{- 2 + - 4}{2}) \Rightarrow (\frac{6}{2}, \frac{- 6}{2}) \Rightarrow (3, - 3)$
$(\frac{3 + - 5}{2}, \frac{5 + - 1}{2}) \Rightarrow (\frac{- 2}{2}, \frac{4}{2}) \Rightarrow (- 1, 2)$
$(\frac{12 + 6}{2}, \frac{4 + - 4}{2}) \Rightarrow (\frac{18}{2}, \frac{0}{2}) \Rightarrow (9, 0)$
$(\frac{- 8 + 6}{2}, \frac{- 1 + 7}{2}) \Rightarrow (\frac{- 2}{2}, \frac{6}{2}) \Rightarrow (- 1, 3)$
$(\frac{1 + 3}{2}, \frac{- 6 + - 2}{2}) \Rightarrow (\frac{4}{2}, \frac{- 8}{2}) \Rightarrow (2, - 4)$
$(\frac{- 7 + 3}{2}, \frac{- 1 + 9}{2}) \Rightarrow (\frac{- 4}{2}, \frac{8}{2}) \Rightarrow (- 2, 4)$
$(\frac{2 + 12}{2}, \frac{- 2 + 4}{2}) \Rightarrow (\frac{14}{2}, \frac{2}{2}) \Rightarrow (7, 1)$

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