Answer Key 5.6
- a
t+x+y+z=−6+−t+x−y−z=−22x2=42x=2(−t+x−y−z=−2)(−1)t−x+y+z=−2+−t+3x+y−z=−22x+2y=−42(2)+2y=−4−4−42y=−0y=−0
t+2x+2y+4z=17+−t+3x+y−z=25x+3y+3z=195(2)+3(0)+3z=1910+3z=19−10−103z3=93z=3t+x+y+z=6t+2+0+3=6t+5=6−5−5t=1 - a
t+x−y+z=−1+−t+3x+y−z=14x=0x=0∴t−y+z=−1−t+2y+z=3−t+y−z=1−2t+y−3z=0−t+2y+z=3+−t+y−z=1−2t+3y=4(−t+y−z=1)(−3)3t−3y+3z=−3+−2t+y−3z=0(t−2y=−3)(2)2t−4y=−6+−2t+3y=4−y=−2y=2
t−y+z=−1t−2+z=−1+2+2t+z=1−t+2y+z=3−t+2(2)+z=3−t+4+z=3−4−4−t+z=−1+t+z=12z=0z=0t+z=1t+0=1t=1
