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Mid Term 1: Review Questions Answer Key

  1. True
  2. Undefined
  3. 15
  4. 16
  5. 12
  6. 19
  7. True
  8. −18
  9. 18
  10. −16
  11. 16
  12. −16
  1. (6)(6)24(8)(2)(6)(6)24(8)(2)
    636+646104636+646104
  2. aa
    3x1227=75x30+5x+12+27+5x+12+7+278x=16x=23x1227=75x30+5x+12+27+5x+12+7+278x=16x=2
  3. aa
    (1R=1r1+1r2)(Rr1r2)r1r2=Rr2+Rr1r1r2=R(r2+r1)R=r1r2r2+r1(1R=1r1+1r2)(Rr1r2)r1r2=Rr2+Rr1r1r2=R(r2+r1)R=r1r2r2+r1
  4. (x+3834=x+610)(40)(x+3834=x+610)(40)
    5(x+3)3(10)=4(x+6)5x+1530=4x+244x15+304x15+30x=395(x+3)3(10)=4(x+6)5x+1530=4x+244x15+304x15+30x=39
  5. Need graph drawn. y=5y=5
  6. m=ΔyΔx23=y2x12(x+1)=3(y2)2x+2=3y63y+63y+62x3y+8=0y=23x+83m=ΔyΔx23=y2x12(x+1)=3(y2)2x+2=3y63y+63y+62x3y+8=0y=23x+83
  7. aa
    1st slopem=ΔyΔxm=11122m=124m=32nd slopem=ΔyΔx3=y1x23(x+2)=y+13x+6=y+1y1y13xy+5=0y=3x+51st slopem=ΔyΔxm=11122m=124m=32nd slopem=ΔyΔx3=y1x23(x+2)=y+13x+6=y+1y1y13xy+5=0y=3x+5
  8. aa
    Line on graph intercepts (0,-1), (3,1)
    Use slop intercept method.
  9. aa
    d2=Δx2+Δy2d2=(157)2+(33)2d2=82+62d=10d2=Δx2+Δy2d2=(157)2+(33)2d2=82+62d=10
  10. x=x1+x22=7+152=11x=x1+x22=7+152=11
    y=y1+y22=3+32=0y=y1+y22=3+32=0
    (11,0)(11,0)
  11. True
  12. True
  13. {r,s,t}{r,s,t}
  14. True
  15. aa
    3x636x>60+6+633x>66x<23x636x>60+6+633x>66x<2
    - infinity, 2
    (−∞, −2)
  16. aa
    184x62+6+6+61244x4843x2184x62+6+6+61244x4843x2

    -3, 2
    [−3, 2]
  17. aa
    2x1<7+1+12x2<62x<37<2x1+1+182<2x24<x2x1<7+1+12x2<62x<37<2x1+1+182<2x24<x
    - infinity, -3 or 4, infinity
    (−∞, −3) or (4, ∞)
  18. |3x45|<13x45<1 (1<3x45<1)(5)(1<3x45<1)(5) 5<3x4<5+4+4+413<3x3<9313<x<3
    -1/3, 3
    (13,3)
  19. a
    3x2y=10+10+2y10+2y3x2102=2y2y=32x5

    Line on graph passes through 0(-5), (2<-2), (4,1), (6,4)
    Slope intercept method. Check (0, 0): 3(0) − 2(0) < 10. Shade the (0, 0) side.
  20. y=|x1|2
    x y
    4 1
    3 0
    2 −1
    1 −2
    0 −1
    −1 0
    −2 1
  21. a
    6L+2S=38+4L2S=1210L=50L=56(5)+2S=3830+2S=3830302S=8S=4
  22. Insert diagram.
    5x+x=366x=36x=65x=30
  23. a
    (d+q=14)(10)10d+25q=26010d10q=140+10d+25q=26015q15=12015q=8d+8=1488d=6
  24. x,x+2
    x+x+2=x102x+2=x10x2x2x=12
    numbers are −12, −10
  25. a
    1st_y=kmn2d2nd_y=12k=findm=3n=4d=812=k(3)(4)28k=12(8)316k=23rd_y=findk=2m=3n=3d=6y=(2)(3)(3)26y=9

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