Mid Term 1: Review Questions Answer Key
- True
- Undefined
- 15
- 16
- 12
- 19
- True
- −18
- 18
- −16
- 16
- −16
- −(−6)−√(−6)2−4(8)(−2)−(−6)−√(−6)2−4(8)(−2)
6−√36+646−10−46−√36+646−10−4 - aa
3x−12−27=7−5x−30+5x+12+27+5x+12+7+278x=16x=23x−12−27=7−5x−30+5x+12+27+5x+12+7+278x=16x=2 - aa
(1R=1r1+1r2)(Rr1r2)r1r2=Rr2+Rr1r1r2=R(r2+r1)R=r1r2r2+r1(1R=1r1+1r2)(Rr1r2)r1r2=Rr2+Rr1r1r2=R(r2+r1)R=r1r2r2+r1 - (x+38−34=x+610)(40)(x+38−34=x+610)(40)
5(x+3)−3(10)=4(x+6)5x+15−30=4x+24−4x−15+30−4x−15+30x=395(x+3)−3(10)=4(x+6)5x+15−30=4x+24−4x−15+30−4x−15+30x=39 - Need graph drawn. y=5y=5
- m=ΔyΔx23=y−2x−−12(x+1)=3(y−2)2x+2=3y−6−3y+6−3y+62x−3y+8=0y=23x+83m=ΔyΔx23=y−2x−−12(x+1)=3(y−2)2x+2=3y−6−3y+6−3y+62x−3y+8=0y=23x+83
- aa
1st slopem=ΔyΔxm=11−−12−−2m=124m=32nd slopem=ΔyΔx3=y−−1x−−23(x+2)=y+13x+6=y+1−y−1−y−13x−y+5=0y=3x+51st slopem=ΔyΔxm=11−−12−−2m=124m=32nd slopem=ΔyΔx3=y−−1x−−23(x+2)=y+13x+6=y+1−y−1−y−13x−y+5=0y=3x+5 - aa
Use slop intercept method. - aa
d2=Δx2+Δy2d2=(15−7)2+(3−−3)2d2=82+62d=10d2=Δx2+Δy2d2=(15−7)2+(3−−3)2d2=82+62d=10 - x=x1+x22=7+152=11x=x1+x22=7+152=11
y=y1+y22=−3+32=0y=y1+y22=−3+32=0
(11,0)(11,0) - True
- True
- {r,s,t}{r,s,t}
- True
- aa
3x−6−36x>60+6+6−33x>66x<−23x−6−36x>60+6+6−33x>66x<−2(−∞, −2) - aa
−18≤4x−6≤2+6+6+6−124≤4x4≤84−3≤x≤2−18≤4x−6≤2+6+6+6−124≤4x4≤84−3≤x≤2[−3, 2] - aa
2x−1<−7+1+12x2<−62x<−37<2x−1+1+182<2x24<x2x−1<−7+1+12x2<−62x<−37<2x−1+1+182<2x24<x(−∞, −3) or (4, ∞) - |3x−45|<1∣∣∣3x−45∣∣∣<1
(−1<3x−45<1)(5)(−1<3x−45<1)(5)
−5<3x−4<5+4+4+4−13<3x3<93−13<x<3
(−13,3) - a
3x−2y=10+−10+2y−10+2y3x2−102=2y2y=32x−5Slope intercept method. Check (0, 0): 3(0) − 2(0) < 10. Shade the (0, 0) side. -
y=|x−1|−2 x y 4 1 3 0 2 −1 1 −2 0 −1 −1 0 −2 1 - a
6L+2S=38+4L−2S=1210L=50L=5∴6(5)+2S=3830+2S=38−30−302S=8S=4 - Insert diagram.
5x+x=366x=36x=6∴5x=30 - a
(d+q=14)(−10)10d+25q=260−10d−10q=−140+10d+25q=−26015q15=12015q=8∴d+8=14−8−8d=6 - x,x+2
x+x+2=x−102x+2=x−10−x−2−x−2x=−12
numbers are −12, −10 - a
1st_y=kmn2d2nd_y=12k=findm=3n=4d=812=k(3)(4)28k=12(8)3⋅16k=23rd_y=findk=2m=−3n=3d=6y=(2)(−3)(3)26y=−9