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Chapter 10: Quadratics

10.8 Construct a Quadratic Equation from its Roots

It is possible to construct an equation from its roots, and the process is surprisingly simple. Consider the following:

Example 10.8.1

Construct a quadratic equation whose roots are x=4 and x=6.

This means that x=4 (or x4=0) and x=6 (or x6=0).

The quadratic equation these roots come from would have as its factored form:

(x4)(x6)=0

All that needs to be done is to multiply these two terms together:

(x4)(x6)=x210x+24=0

This means that the original equation will be equivalent to x210x+24=0.

This strategy works for even more complicated equations, such as:

Example 10.8.2

Construct a polynomial equation whose roots are x=±2 and x=5.

This means that x=2 (or x2=0), x=2 (or x+2=0) and x=5 (or x5=0).

These solutions come from the factored polynomial that looks like:

(x2)(x+2)(x5)=0

Multiplying these terms together yields:

(x24)(x5)=0x35x24x+20=0

The original equation will be equivalent to x35x24x+20=0.

Caveat: the exact form of the original equation cannot be recreated; only the equivalent. For example, x35x24x+20=0 is the same as 2x310x28x+40=0, 3x315x212x+60=0, 4x320x216x+80=0, 5x325x220x+100=0, and so on. There simply is not enough information given to recreate the exact original—only an equation that is equivalent.

Questions

Construct a quadratic equation from its solution(s).

  1. 2, 5
  2. 3, 6
  3. 20, 2
  4. 13, 1
  5. 4, 4
  6. 0, 9
  7. 34,14
  8. 58,57
  9. 12,13
  10. 12,23
  11. ± 5
  12. ± 1
  13. ±15
  14. ±7
  15. ±11
  16. ±23
  17. 3, 5, 8
  18. −4, 0, 4
  19. −9, −6, −2
  20. ± 1, 5
  21. ± 2, ± 5
  22. ±23,±5

Answer Key 10.8

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