CHAPTER 3 Measurement, Perimeter, Area, and Volume

3.4 Solve Geometry Applications: Circles and Irregular Figures

Learning Objectives

By the end of this section, you will be able to:

  • Use the properties of circles
  • Find the area of irregular figures

In this section, we’ll continue working with geometry applications. We will add several new formulas to our collection of formulas. To help you as you do the examples and exercises in this section, we will show the Problem Solving Strategy for Geometry Applications here.

Problem Solving Strategy for Geometry Applications

  1. Read the problem and make sure you understand all the words and ideas. Draw the figure and label it with the given information.
  2. Identify what you are looking for.
  3. Name what you are looking for. Choose a variable to represent that quantity.
  4. Translate into an equation by writing the appropriate formula or model for the situation. Substitute in the given information.
  5. Solve the equation using good algebra techniques.
  6. Check the answer in the problem and make sure it makes sense.
  7. Answer the question with a complete sentence.

Use the Properties of Circles

 We’ll  refer to the properties of circles as we use them to solve applications.

Properties of Circles

An image of a circle is shown. There is a line drawn through the widest part at the centre of the circle with a red dot indicating the centre of the circle. The line is labeled d. The two segments from the centre of the circle to the outside of the circle are each labeled r.

  • r is the length of the radius
  • d is the length of the diametre
  • d=2r
  • Circumference is the perimeter of a circle. The formula for circumference is
    C=2\pi r
  • The formula for area of a circle is
    A=\pi {r}^{2}

Remember, that we approximate \pi with 3.14 or \frac{22}{7} depending on whether the radius of the circle is given as a decimal or a fraction. If you use the \pi key on your calculator to do the calculations in this section, your answers will be slightly different from the answers shown. That is because the \pi key uses more than two decimal places.

EXAMPLE 1

A circular sandbox has a radius of 2.5 feet. Find the a) circumference and b) area of the sandbox.

Solution
a)
Step 1. Read the problem. Draw the figure and label it with the given information. .
Step 2. Identify what you are looking for. the circumference of the circle
Step 3. Name. Choose a variable to represent it. Let c = circumference of the circle
Step 4. Translate.
Write the appropriate formula
Substitute
C=2\pi r
C=2\pi \left(2.5\right)
Step 5. Solve the equation. C\approx 2\left(3.14\right)\left(2.5\right)
C\approx 15\text{ft}
Step 6. Check. Does this answer make sense?
Yes. If we draw a square around the circle, its sides would be 5 ft (twice the radius), so its perimeter would be 20 ft. This is slightly more than the circle’s circumference, 15.7 ft.
.
Step 7. Answer the question. The circumference of the sandbox is 15.7 feet.

 

b)

Step 1. Read the problem. Draw the figure and label it with the given information .
Step 2. Identify what you are looking for. the area of the circle
Step 3. Name. Choose a variable to represent it. Let A = the area of the circle
Step 4. Translate.
Write the appropriate formula
Substitute
A=\pi{r}^{2}
A=\pi{\left(2.5\right)}^{2}
Step 5. Solve the equation. A\approx \left(3.14\right){\left(2.5\right)}^{2}
A\approx 19.625\phantom{\rule{0.2em}{0ex}}\text{sq. ft}
Step 6. Check.
Yes. If we draw a square around the circle, its sides would be 5 ft, as shown in part a). So the area of the square would be 25 sq. ft. This is slightly more than the circle’s area, 19.625 sq. ft.
Step 7. Answer the question. The area of the circle is 19.625 square feet.

TRY IT 1.1

A circular mirror has radius of 5 inches. Find the a) circumference and b) area of the mirror.

Show answer
  1. 31.4 in.
  2. 78.5 sq. in.

TRY IT 1.2

A circular spa has radius of 4.5 feet. Find the a) circumference and b) area of the spa.

Show answer
  1. 28.26 ft
  2. 63.585 sq. ft

We usually see the formula for circumference in terms of the radius r of the circle:

C=2\pi r

But since the diametre of a circle is two times the radius, we could write the formula for the circumference in terms \text{of}\phantom{\rule{0.2em}{0ex}}d.

\begin{array}{cccc}& & & C=2\pi r\hfill \\ \text{Using the commutative property, we get}\hfill & & & C=\pi \cdot2r\hfill \\ \text{Then substituting}\phantom{\rule{0.2em}{0ex}}d=2r\hfill & & & C=\pi \cdot\text{d}\hfill \\ \text{So}\hfill & & & C=\pi d\hfill \end{array}

We will use this form of the circumference when we’re given the length of the diametre instead of the radius.

EXAMPLE 2

A circular table has a diametre of four feet. What is the circumference of the table?

Solution
Step 1. Read the problem. Draw the figure and label it with the given information. .
Step 2. Identify what you are looking for. the circumference of the table
Step 3. Name. Choose a variable to represent it. Let c = the circumference of the table
Step 4. Translate.
Write the appropriate formula for the situation.
Substitute.
C=\pi d
C=\pi \left(4\right)
Step 5. Solve the equation, using 3.14 for \pi. C\approx \left(3.14\right)\left(4\right)
C\approx 12.56\phantom{\rule{0.2em}{0ex}}\text{feet}
Step 6. Check: If we put a square around the circle, its side would be 4.
The perimeter would be 16. It makes sense that the circumference of the circle, 12.56, is a little less than 16.
.
Step 7. Answer the question. The diametre of the table is 12.56 square feet

TRY IT 2.1

Find the circumference of a circular fire pit whose diametre is 5.5 feet.

Show answer

17.27 ft

TRY IT 2.2

If the diametre of a circular trampoline is 12 feet, what is its circumference?

Show answer

37.68 ft

EXAMPLE 3

Find the diametre of a circle with a circumference of 47.1 centimetres.

Solution
Step 1. Read the problem. Draw the figure and label it with the given information. .
Step 2. Identify what you are looking for. the diametre of the circle
Step 3. Name. Choose a variable to represent it. Let d = the diametre of the circle
Step 4. Translate.
Write the formula.
Substitute, using 3.14 to approximate \pi.
.
.
Step 5. Solve. .
.
Step 6. Check:
47.1\stackrel{?}{=}\left(3.14\right)\left(15\right)
47.1=47.1
.
Step 7. Answer the question. The diametre of the circle is approximately 15 centimetres.

TRY IT 3.1

Find the diametre of a circle with circumference of 94.2 centimetres.

Show answer

30 cm

TRY IT 3.2

Find the diametre of a circle with circumference of 345.4 feet.

Show answer

110 ft

Find the Area of Irregular Figures

So far, we have found area for rectangles, triangles, trapezoids, and circles. An irregular figure is a figure that is not a standard geometric shape. Its area cannot be calculated using any of the standard area formulas. But some irregular figures are made up of two or more standard geometric shapes. To find the area of one of these irregular figures, we can split it into figures whose formulas we know and then add the areas of the figures.

EXAMPLE 4

Find the area of the shaded region.

An image of an attached horizontal rectangle and a vertical rectangle is shown. The top is labeled 12, the side of the horizontal rectangle is labeled 4. The side is labeled 10, the width of the vertical rectangle is labeled 2.

Solution

The given figure is irregular, but we can break it into two rectangles. The area of the shaded region will be the sum of the areas of both rectangles.

An image of an attached horizontal rectangle and a vertical rectangle is shown. The top is labeled 12, the side of the horizontal rectangle is labeled 4. The side is labeled 10, the width of the vertical rectangle is labeled 2.

The blue rectangle has a width of 12 and a length of 4. The red rectangle has a width of 2, but its length is not labeled. The right side of the figure is the length of the red rectangle plus the length of the blue rectangle. Since the right side of the blue rectangle is 4 units long, the length of the red rectangle must be 6 units.

An image of a blue horizontal rectangle attached to a red vertical rectangle is shown. The top is labeled 12, the side of the blue rectangle is labeled 4. The whole side is labeled 10, the blue portion is labeled 4 and the red portion is labeled 6. The width of the red rectangle is labeled 2.The first line says A sub figure equals A sub rectangle plus A sub red rectangle. Below this is A sub figure equals bh plus red bh. Below this is A sub figure equals 12 times 4 plus red 2 times 6. Below this is A sub figure equals 48 plus red 12. Below this is A sub figure equals 60.

The area of the figure is 60 square units.

Is there another way to split this figure into two rectangles? Try it, and make sure you get the same area.

TRY IT 4.1

Find the area of each shaded region:

A blue geometric shape is shown. It looks like a horizontal rectangle attached to a vertical rectangle. The top is labeled as 8, the width of the horizontal rectangle is labeled as 2. The side is labeled as 6, the width of the vertical rectangle is labeled as 3.

Show answer

28 sq. units

TRY IT 4.2

Find the area of each shaded region:

A blue geometric shape is shown. It looks like a horizontal rectangle attached to a vertical rectangle. The top is labeled as 14, the width of the horizontal rectangle is labeled as 5. The side is labeled as 10, the width of the missing space is labeled as 6.

Show answer

110 sq. units

EXAMPLE 5

Find the area of the shaded region.

A blue geometric shape is shown. It looks like a rectangle with a triangle attached to the top on the right side. The left side is labeled 4, the top 5, the bottom 8, the right side 7.

Solution

We can break this irregular figure into a triangle and rectangle. The area of the figure will be the sum of the areas of triangle and rectangle.

The rectangle has a length of 8 units and a width of 4 units.

We need to find the base and height of the triangle.

Since both sides of the rectangle are 4, the vertical side of the triangle is 3, which is 7-4.

The length of the rectangle is 8, so the base of the triangle will be 3, which is 8-4.

A geometric shape is shown. It is a blue rectangle with a red triangle attached to the top on the right side. The left side is labeled 4, the top 5, the bottom 8, the right side 7. The right side of the rectangle is labeled 4. The right side and bottom of the triangle are labeled 3.

Now we can add the areas to find the area of the irregular figure.

The top line reads A sub figure equals A sub rectangle plus A sub red triangle. The second line reads A sub figure equals lw plus one-half red bh. The next line says A sub figure equals 8 times 4 plus one-half times red 3 times red 3. The next line reads A sub figure equals 32 plus red 4.5. The last line says A sub figure equals 36.5 sq. units.

The area of the figure is 36.5 square units.

TRY IT 5.1

Find the area of each shaded region.

A blue geometric shape is shown. It looks like a rectangle with a triangle attached to the lower right side. The base of the rectangle is labeled 8, the height of the rectangle is labeled 4. The distance from the top of the rectangle to where the triangle begins is labeled 3, the top of the triangle is labeled 3.

Show answer

36.5 sq. units

TRY IT 5.2

Find the area of each shaded region.

A blue geometric shape is shown. It looks like a rectangle with an equilateral triangle attached to the top. The base of the rectangle is labeled 12, each side is labeled 5. The base of the triangle is split into two pieces, each labeled 2.5.

Show answer

70 sq. units

EXAMPLE 6

A high school track is shaped like a rectangle with a semi-circle (half a circle) on each end. The rectangle has length 105 metres and width 68 metres. Find the area enclosed by the track. Round your answer to the nearest hundredth.

A track is shown, shaped like a rectangle with a semi-circle attached to each side.

Solution

We will break the figure into a rectangle and two semi-circles. The area of the figure will be the sum of the areas of the rectangle and the semicircles.

A blue geometric shape is shown. It looks like a rectangle with a semi-circle attached to each side. The base of the rectangle is labeled 105 m. The height of the rectangle and diametre of the circle on the left is labeled 68 m.

The rectangle has a length of 105 m and a width of 68 m. The semi-circles have a diametre of 68 m, so each has a radius of 34 m.

The top line reads A sub figure equals A sub rectangle plus A sub semicircles. The second line reads A sub figure equals bh plus red 2 times (in parentheses) red 1/2pi times r squared. The next line says A sub figure approximately equals 105 times 68 plus red 2 times (in parentheses) red 1/2 times 3.14 times 34 squared. The next line reads A sub figure approximately equals 7140 plus red 3629.84. The last line says A sub figure approximately equals 10,769.84 square metres.

TRY IT 6.1

Find the area:

A shape is shown. It is a blue rectangle with a portion of the rectangle missing. There is a red circle the same height as the rectangle attached to the missing side of the rectangle. The top of the rectangle is labeled 15, the height is labeled 9.

Show answer

103.2 sq. units

Key Concepts

  • Problem Solving Strategy for Geometry Applications
    1. Read the problem and make sure you understand all the words and ideas. Draw the figure and label it with the given information.
    2. Identify what you are looking for.
    3. Name what you are looking for. Choose a variable to represent that quantity.
    4. Translate into an equation by writing the appropriate formula or model for the situation. Substitute in the given information.
    5. Solve the equation using good algebra techniques.
    6. Check the answer in the problem and make sure it makes sense.
    7. Answer the question with a complete sentence.
  • Properties of Circles
    .
  • d=2r
  • Circumference:C=2\pi r or C=\pi d
  • Area:A=\pi {r}^{2}

Glossary

irregular figure
An irregular figure is a figure that is not a standard geometric shape. Its area cannot be calculated using any of the standard area formulas.

Practice Makes Perfect

Use the Properties of Circles

In the following exercises, solve using the properties of circles.

1. The lid of a paint bucket is a circle with radius 7 inches. Find the a) circumference and b) area of the lid. 2. An extra-large pizza is a circle with radius 8 inches. Find the a) circumference and b) area of the pizza.
3. A farm sprinkler spreads water in a circle with radius of 8.5 feet. Find the a) circumference and b) area of the watered circle. 4. A circular rug has radius of 3.5 feet. Find the a) circumference and b) area of the rug.
5. A reflecting pool is in the shape of a circle with diametre of 20 feet. What is the circumference of the pool? 6. A turntable is a circle with diametre of 10 inches. What is the circumference of the turntable?
7. A circular saw has a diametre of 12 inches. What is the circumference of the saw? 8. A round coin has a diametre of 3 centimetres. What is the circumference of the coin?
9. A barbecue grill is a circle with a diametre of 2.2 feet. What is the circumference of the grill? 10. The top of a pie tin is a circle with a diametre of 9.5 inches. What is the circumference of the top?
11. A circle has a circumference of 163.28 inches. Find the diametre. 12. A circle has a circumference of 59.66 feet. Find the diametre.
13. A circle has a circumference of 17.27 metres. Find the diametre. 14. A circle has a circumference of 80.07 centimetres. Find the diametre.

In the following exercises, find the radius of the circle with given circumference.

15. A circle has a circumference of 150.72 feet. 16. A circle has a circumference of 251.2 centimetres.
17. A circle has a circumference of 40.82 miles. 18. A circle has a circumference of 78.5 inches.

Find the Area of Irregular Figures

In the following exercises, find the area of the irregular figure. Round your answers to the nearest hundredth.

19. A geometric shape is shown. It is a horizontal rectangle attached to a vertical rectangle. The top is labeled 6, the height of the horizontal rectangle is labeled 2, the distance from the edge of the horizontal rectangle to the start of the vertical rectangle is 4, the base of the vertical rectangle is 2, the right side of the shape is 4. 20. A geometric shape is shown. It is an L-shape. The base is labeled 10, the right side 1, the top and left side are each labeled 4.
21. A geometric shape is shown. It is a sideways U-shape. The top is labeled 6, the left side is labeled 6. An inside horizontal piece is labeled 3. Each of the vertical pieces on the right are labeled 2. 22. A geometric shape is shown. It is a U-shape. The base is labeled 7. The right side is labeled 5. The two horizontal lines at the top and the vertical line on the inside are all labeled 3.
23. A geometric shape is shown. It is a rectangle with a triangle attached to the bottom left side. The top is labeled 4. The right side is labeled 10. The base is labeled 9. The vertical line from the top of the triangle to the top of the rectangle is labeled 3. 24. A trapezoid is shown. The bases are labeled 5 and 10, the height is 5.
25. Two triangles are shown. They appear to be right triangles. The bases are labeled 3, the heights 4, and the longest sides 5. 26. A geometric shape is shown. It appears to be composed of two triangles. The shared base of both triangles is 8, the heights are both labeled 6.
27. A geometric shape is shown. It is composed of two trapezoids. The base is labeled 10. The height of one trapezoid is 2. The horizontal and vertical sides are all labeled 5. 28. A geometric shape is shown. It is a trapezoid attached to a triangle. The base of the triangle is labeled 6, the height is labeled 5. The height of the trapezoid is 6, one base is 3.
29. A geometric shape is shown. It is a rectangle with a triangle and another rectangle attached. The left side is labeled 8, the bottom is 8, the right side is 13, and the width of the smaller rectangle is 2. 30. A geometric shape is shown. It is a rectangle with a triangle and another rectangle attached. The left side is labeled 12, the right side 7, the base 6. The width of the smaller rectangle is labeled 1.
31. A geometric shape is shown. It is a rectangle attached to a semi-circle. The base of the rectangle is labeled 5, the height is 7. 32. A geometric shape is shown. It is a rectangle attached to a semi-circle. The base of the rectangle is labeled 10, the height is 6. The portion of the rectangle on the left of the semi-circle is labeled 5, the portion on the right is labeled 2.
33. A geometric shape is shown. A triangle is attached to a semi-circle. The base of the triangle is labeled 4. The height of the triangle and the diametre of the circle are 8. 34. A geometric shape is shown. A triangle is attached to a semi-circle. The height of the triangle is labeled 4. The base of the triangle, also the diametre of the semi-circle, is labeled 4.
35. A geometric shape is shown. It is a rectangle attached to a semi-circle. The base of the rectangle is labeled 5, the height is 7. 36. A geometric shape is shown. A trapezoid is shown with a semi-circle attached to the top. The diametre of the circle, which is also the top of the trapezoid, is labeled 8. The height of the trapezoid is 6. The bottom of the trapezoid is 13.
37. A geometric shape is shown. It is a rectangle with a triangle attached to the top on the left side and a circle attached to the top right corner. The diametre of the circle is labeled 5. The height of the triangle is labeled 5, the base is labeled 4. The height of the rectangle is labeled 6, the base 11. 38. A geometric shape is shown. It is a trapezoid with a triangle attached to the top, and a circle attached to the triangle. The diametre of the circle is 4. The height of the triangle is 5, the base of the triangle, which is also the top of the trapezoid, is 6. The bottom of the trapezoid is 9. The height of the trapezoid is 7. 

In the following exercises, solve.

39. A city park covers one block plus parts of four more blocks, as shown. The block is a square with sides 250 feet long, and the triangles are isosceles right triangles. Find the area of the park.

A square is shown with four triangles coming off each side.

40. A gift box will be made from a rectangular piece of cardboard measuring 12 inches by 20 inches, with squares cut out of the corners of the sides, as shown. The sides of the squares are 3 inches. Find the area of the cardboard after the corners are cut out.

A rectangle is shown. Each corner has a gray shaded square. There are dotted lines drawn across the side of each square attached to the next square.

41. Perry needs to put in a new lawn. His lot is a rectangle with a length of 120 feet and a width of 100 feet. The house is rectangular and measures 50 feet by 40 feet. His driveway is rectangular and measures 20 feet by 30 feet, as shown. Find the area of Perry’s lawn.

A rectangular lot is shown. In it is a home shaped like a rectangle attached to a rectangular driveway.

42. Denise is planning to put a deck in her back yard. The deck will be a \text{20-ft} by \text{12-ft} rectangle with a semicircle of diametre 6 feet, as shown below. Find the area of the deck.

A picture of a deck is shown. It is shaped like a rectangle with a semi-circle attached to the top on the left side.

Everyday Math

43. Area of a Tabletop Yuki bought a drop-leaf kitchen table. The rectangular part of the table is a \text{1-ft} by \text{3-ft} rectangle with a semicircle at each end, as shown. a) Find the area of the table with one leaf up. b) Find the area of the table with both leaves up.

An image of a table is shown. There is a rectangular portion attached to a semi-circular portion. There is another semi-circular leaf folded down on the other side of the rectangle.

44. Painting Leora wants to paint the nursery in her house. The nursery is an \text{8-ft} by \text{10-ft} rectangle, and the ceiling is 8 feet tall. There is a \text{3-ft} by \text{6.5-ft} door on one wall, a \text{3-ft} by \text{6.5-ft} closet door on another wall, and one \text{4-ft} by \text{3.5-ft} window on the third wall. The fourth wall has no doors or windows. If she will only paint the four walls, and not the ceiling or doors, how many square feet will she need to paint?

Writing Exercises

45. Describe two different ways to find the area of this figure, and then show your work to make sure both ways give the same area.

A geometric shape is shown. It is a vertical rectangle attached to a horizontal rectangle. The width of the vertical rectangle is 3, the left side is labeled 6, the bottom is labeled 9, and the width of the horizontal rectangle is labeled 3. The top of the horizontal rectangle is labeled 6, and the distance from the top of that rectangle to the top of the other rectangle is labeled 3.

46. A circle has a diametre of 14 feet. Find the area of the circle a) using 3.14 for \pi b) using \frac{22}{7} for \pi. c) Which calculation to do prefer? Why?

Answers

1.

a) 43.96 in.

b) 153.86 sq. in.

3.

a) 53.38 ft

b) 226.865 sq. ft

5. 62.8 ft
7. 37.68 in. 9. 6.908 ft 11. 52 in.
13. 5.5 m 15. 24 ft 17. 6.5 mi
19. 16 sq. units 21. 30 sq. units 23. 57.5 sq. units
25. 12 sq. units 27. 67.5 sq. units 29. 89 sq. units
31. 44.81 sq. units 33. 41.12 sq. units 35. 35.13 sq. units
37. 95.625 sq. units 39. 187,500 sq. ft 41. 9400 sq. ft
43. a) 6.5325 sq. ft  b) 10.065 sq. ft 45. Answers will vary.

Attributions

This chapter has been adapted from “Solve Geometry Applications: Circles and Irregular Figures” in Prealgebra (OpenStax) by Lynn Marecek, MaryAnne Anthony-Smith, and Andrea Honeycutt Mathis, which is under a CC BY 4.0 Licence. Adapted by Izabela Mazur. See the Copyright page for more information.

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Introductory Algebra Copyright © 2021 by Izabela Mazur is licensed under a Creative Commons Attribution 4.0 International License, except where otherwise noted.

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